similar to: Arguments to order()

Does anyone know how to execute the following sort problem in R? Matrix X has positive integer entries, and each column has been sorted in ascending order. The problem is now to order the columns lexicographically. For instance if the matrix X is 1 2 1 1 2 2 2 3 3 2 3 5 5 4 2 then the result should be 1 1 1 2 2 2 3 3 2 2 3 4 5 2 5 Let ONE be a vector of 1's of length

Hi, I have a list of vectors (of varying lengths). I'd like to sort this list by applying a function to each pair of vectors in the list and returning information to sorting routine that let's it know which one is larger. To solve problems like this in Common Lisp, the sort function accepts a function as an argument. The arguments to this function are two elements of the list which is

I have the following xyplot figure: http://img577.imageshack.us/img577/686/filesizeresults12000000.png The data are organized in a matrix file as follows: Type Elements Chromosome Time bedGz 12000000 chr1 14.240 bedGz 12000000 chr2 7.949 bedGz 12000000 chr3 5.103 bedGz 12000000 chr4 5.290 bedGz 12000000 chr5 5.161 ... The x-axis labels in the Chromosome column are ordered

Hi there! I need some assistance here with vector orderings. I have a set of q vectors of length p, grouped by rows in a matrix A, q?p, that I need to order lexicographically (http://en.wikipedia.org/wiki/Lexicographical_order). I also have another matrix B, p?r, and a vector c, that should be ordered according to the order of A. So far, I was doing ordering <-

Hi all, I have some email addresses that I would like to sort in reverse lexicographic order so that addresses from the same domain will be grouped together. How might that be done? Murray -- Dr Murray Jorgensen http://www.stats.waikato.ac.nz/Staff/maj.html Department of Statistics, University of Waikato, Hamilton, New Zealand Email: maj at waikato.ac.nz

There appears to be an issue with the decreasing=TRUE option on the order() function that indicates either a bug or perhaps a design flaw (potentially flawed because I would suggest the majority of users would expect different behaviour). # demonstration of problem: x <- c(2,1,3,4,5) order(x) order(x, decreasing=TRUE) order(x) correctly reports the order as: 2 1 3 4 5 I expected the result

## While in R v. 2.3.1 (the mid-July patch for Windows) ## on a Windows XP machine, this call to order() works fine... order(1:10,decreasing = TRUE) ## [1] 10 9 8 7 6 5 4 3 2 1 ## ...however, the argument name 'decreasing' ## must be typed in toto (note the missing 'g' ## in the following): > order(1:10,decreasin = TRUE) ## Error in order(na.last, decreasing, ...) :

Hi all I have a large dataframe with (among others) a categorical variable of 52 levels and would like to create a barplot with the bars ordered in decreasing frequency of the levels. I belive it is referred to as a pareto plot. Consider a subset where I keep only the categorical variable in question. # Example: v1 = c("aa", "cc", "bb", "bb",

Dear all, Trying to solve a problem I had (see thread "putting NAs at the end" ) I've noticed a difference in system time requirements between using apply and sort (or order) to order each row or column of a matrix compared to a vectorized function I wrote. Using apply is much faster when the number of loops (number of rows or columns to order) is low BUT much slower when number of

I suggest gzipped XML. Feel free to suggest something that isn't XML if you dislike it that much. Anyhow, as a practical matter, Vorbis-style metadata lacks a Really Good Way to have the same data in multiple languages. Or at least a widely-agreed upon way. So, howzabout... <data> <title xml:lang='en'>Mars, the Bringer of War</title> <title

Is there any built-in way to lexicographically compare two vectors of the same length in R? The textbook algorithm could be coded as follows: lex.cmp <- function (vec1,vec2) { for (j in 1:length(vec1)) { if (vec1[j] < vec2[j]) { return(-1) } if (vec1[j] > vec2[j]) { return(1) } } return(0) } Thanks, Gabriel

Dear R-users, is there some way how to pass various colnames to the following code for sorting data.frames? mydf.ordered<-with(mydf, mydf[order(colname1,colname2, colnameX, decreasing = TRUE), ]) I was trying something like Afunction<-function (mydf,colnames,decreasing=T){ mydf.ordered<-with(mydf, mydf[order(colnames, decreasing = decreasing), ]) } but it didnt work please

Hi Dimitris, thank you for your reply, > does the following work in your data: > > levs <- unique.default(Names) > factor(Names, levs[order(unique.default(Weights))]) your solution is really shorter, but has two issues to be meant here: 1. "unique.default" is applied twice, what might be a bit expensive for strings. 2. your solution brings an implicit

Hello, I have a data.frame which I would like to sort with the primary key decreasing while the secondry key is increasing e.g. x <- data.frame(One=c(1,1,1,2,2,3,4,5),Two=c(2,3,1,2,3,3,3,3)) I would like to order it so it looks like this: One Two 8 5 3 7 4 3 6 3 3 4 2 2 5 2 3 3 1 1 1 1 2 2 1 3 i.e. primarily decreasing in the 1st column but if there is a

Hi all Here is a rather naive implementation of the SEPA algorithm for generating lexical permutations: lexperm3 <- function(x, n=length(x)) { perms <- list() k <- 1 perms[[k]] <- x k <- k + 1 for (y in 1:(factorial(n)-1)) { i <- n-1 while (x[i] > x[i+1] && i > 0) { i <- i - 1 } # i is largest index st x[i] > x[i+1] j <- n #

I've found the need to compute a version of order(x,y) where I want the sort order for *increasing* x and *decresing* y ... something we could imagine could be provided in the future as order(x,y, decreasing = c(FALSE, TRUE)) i.e., using a 'vectorized' decreasing argument. {No, I'm not volunteering right now!} I've found the following R-level solution and like to quiz

System: Red Hat Enterprise Linux Server release 6.5 (Santiago) I?ve installed zlib 1.2.11 on the home folder of a Red Hat HPC as part of the process for installing R base 3.4.0. I get this error even after successful install of zlib checking for inflateInit2_ in -lz... no checking whether zlib support suffices... configure: error: zlib library and headers are required I?ve checked R

Hi all, I want to order a series that is included on the second column in MCT.csv. I do but R doesn?t order, could be because is a csv? I have prove MCT<-read.csv("MCT.csv") a<-order(MCTor[,2],2,decreasing = FALSE) a<-order(MCTor[,2],1,decreasing = FALSE) or the same with sort but didn?t worked. It is suposed that a will have the ordered on ascending or descending

Hi all, I have a large data frame and would like to make a barplot of a categorical variable with the bars sorted in order of decreasing frequency. # Example: v1 = c(1.2, 1.4, 0.9, 1.0, 1.1, 1.0) v2 = c("aa", "cc", "bb", "bb", "cc", "bb") v3 = c(8, 10, 11, 9, 9, 10) df = data.frame(v1=v1, v2=v2, v3=v3) # How can I tell ggplot to sort

Hi All, I want to give ranks to elements in a column so I used: total_list$field1.rank <- rank(total_list$field1,ties.method="min") But this gives me the rank in increasing order. How do I get the ranks in decreasing order? I know decreasing = FALSE is not a legal argument here. Thanks. Jiong The email message (and any attachments) is for the sole use of the intended recipient(s)