similar to: if (cond) expr1 expr2 ??

Hi,? I want to label a polygon (circle or polygon) inside. As for example code? library(spatstat) x <- runif(20) y <- runif(20) X <- ppp(x, y, window=disc(0.7)) plot(X) Now I want to label that circle inside . Can some one please help me ?? Thanks.? Regards............. Tanvir Ahamed Stockholm, Sweden???? |??mashranga at yahoo.com

Try text(0.5, 0.5, label = "?text") On Sat, 10 Feb 2018, 16:22 Mohammad Tanvir Ahamed via R-help, < r-help at r-project.org> wrote: > Hi, > I want to label a polygon (circle or polygon) inside. > As for example code > > library(spatstat) > x <- runif(20) > y <- runif(20) > X <- ppp(x, y, window=disc(0.7)) > plot(X) > > Now I want to

Hi,?In your data file, the first row does not have an equal number of column like the rest of the row.Check your data file. Specially 1st row.?? Regards.............Tanvir Ahamed Stockholm, Sweden | mashranga at yahoo.com On Monday, 5 October 2020, 08:11:48 am GMT+2, Mir Md. Abdus Salam <mir.salam at uef.fi> wrote: Dear all, I need urgent help. I am a new user of R. I

Hi,? I have two big data set.? data _1 :? > dim(data_1) [1] 15820 5 > head(data_1) ? ?Chromosome ?????Start????????End????????Feature GroupA_3 1: ? ? ? ????????chr1 521369 ?750000 ????chr1-0001 ? ?????0.170 2: ? ? ? ????????chr1 750001 ?800000 ????chr1-0002 ? ????-0.086 3: ? ? ? ????????chr1 800001 ?850000 ????chr1-0003 ? ?????0.006 4: ? ? ? ????????chr1 850001 ?900000 ????chr1-0004 ?

Dear all, I need urgent help. I am a new user of R. I got the following error anovamine<-read.table("spike cu.txt",header=TRUE) Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : line 1 did not have 9 elements Can anybody please help me to solve this problem why I am getting such kind of error? Thanks [[alternative HTML version deleted]]

Hi, a <- c(1, 4) b <- c(5, 8) a:b [1] 1 2 3 4 5 Warning messages: 1: In a:b : numerical expression has 2 elements: only the first used 2: In a:b : numerical expression has 2 elements: only the first used how to get: c(1:5, 4:8) Thanks.

Hi, I can run the code some days ago . But cant run now.  Problem 1: Output is ok ensembl = useDataset("hsapiens_gene_ensembl",mart=ensembl) utr5 = getSequence(chromosome=3, start=185514033, end=185535839, type="entrezgene",seqType="5utr", mart=ensembl)  Output :                                                                                                5utr

Hi !  Facing problem with " getSequence" commend .  when only biomaRt package loaded the following example working well  >mart <- useMart("ensembl",dataset="hsapiens_gene_ensembl") >seq = getSequence(id="BRCA1", type="hgnc_symbol", seqType="peptide", mart = mart) show(seq) but when i have loaded the seqinr, i got problem

Hello all ,  I have a data frame like this  X1X2X3 11815 22916 331017 441118 551219 661320 771421 now i want to randomly reorder the variable X2  but the row element should be same  as for example  X1X2X3 12916 251219 331017 471421 561320 61815 741118 how can i do that ?? Hint :  this could be helpful :  if X2 is only a vector like this  X2<-c(8,9,10,11,12,13,14) so i can easily reorder

Dear list-subscriber, in the process of writing a general code snippet to extract coefficients in an expression (in the example below: 0.5 and -0.7), I stumbled over the following peculiar (at least peculiar to me:-) ) sorting behaviour of the function all.names(): > expr1 <- expression(x3 = 0.5 * x1 - 0.7 * x2) > all.names(expr1) [1] "-" "*" "x1"

Hi, Is there any equivalent for ifelse (except if (cond) expr1 else expr2) which takes an atomic element as argument but returns vector since ifelse returns an object of the same length as its argument? x = c(1,2,3) y = c(4,5,6,7) z = 3 ifelse(z <= 3,x,y) would return x and not 1 thanks

Hello! I work with: R : Copyright 2006, The R Foundation for Statistical Computing Version 2.3.1 (2006-06-01) On Windows XP Professional (Version 2002) SP2 I think there is a bug in the conditional execution if (expr1) {expr2} else {expr3} If I try: "if (expr1) expr2 else expr3" it works well but when I put the expression expr2 and expr3 between {} I receive an error message

Hi, I would like to use the beanplot() function from the beanplot package. Unfortunately, I can't find out how to suppress the dashed horizontal line, that shows the overall mean. In the help I've found the argument "overallline", but it only allows for "mean" or "median" . I have tried overallline = F, overallline="n", and

This may have been asked before, but is there an elegant way to check whether an variable/argument passed to a function is a "parse tree" for an (unevaluated) expression or not, *without* evaluating it if not? Currently, I do various rather ad hoc eval()+substitute() tricks for this that most likely only work under certain circumstances. Ideally, I'm looking for a isParseTree()

dear Members, Today something weird has happened on my R console. I have attached two screenshots of the same vector in my R console but they differ. Also one of my function returns negative values, even after double checking the code, which should return only positive values.. Whats wrong..? Reinstall R? Thanks for help.... AKSHAY M KULKARNI -------------- next part -------------- A

Dear list # I have a function ff <- function(a,b=2,c=4){a+b+c} # which I programmatically want to modify to a more specialized function in which a is replaced by 1 ff1 <- function(b=2,c=4){1+b+c} # I do as follows: vals <- list(a=1) (expr1 <- as.expression(body(ff))) expression({ a + b + c }) (expr2 <- do.call("substitute", list(expr1[[1]], vals))) { 1 +

If I have this object: x <- c("abc\ndef", "", "ghi") and I write it to a file using `writeLines(x, "test.txt")`, my text editor sees a 5 line file: 1: abc 2: def 3: 4: ghi 5: which is what I'd expect: the last line in the editor is empty. If I use `readLines("test.txt")` on that file, I get the vector

I am more than a little puzzled by your question. In the construct {expr1; expr2; expr3} all of the expressions expr1, expr2, and expr3 are evaluated, in that order. That's what curly braces are FOR. When you want some expressions evaluated in a specific order, that's why and when you use curly braces. If that's not what you want, don't use them. Complaining about it is like

Hello, I have a function for reading a data-frame from a file, which contains E = read.table(file = filename, header = T, colClasses = c(rep("integer",6),"numeric","integer",rep("numeric",8)), ...) Now a small variation arose, where colClasses =

Is it possible to use R as a data-mining tool? Here's the problem I've got. I have a couple of data sets consisting of results from a cDNA microarray experiment - the details about the biology don't really matter here, the same theory applies for any other data-mining task (that's why I thought it'd be more appropriate to post this on r-user). Each of these datasets consists