similar to: integration

Hi, everyone, I need to use a C library. But since I have little experience in C, I want to call this C library in R and program the rest in R. Does anyone know how to do this? Thanks, Cindy [[alternative HTML version deleted]]

Hi, All, I have an n by m matrix with each entry between 1 and 15000. I want to know the frequency of each pair in 1:15000 that occur together in rows. So for example, if the matrix is 2 5 1 6 1 7 8 2 3 7 6 2 9 8 5 7 Pair (2,6) (un-ordered) occurs together in rows 1 and 3. I want to return the value 2 for this pair as well as that for all pairs. Is there a fast way to do this avoiding loops?

Hi, All, If I have a symmetric matrix, how can I get the negative square root of the matrx, ie. X^(-1/2) ? Thanks, Cindy [[alternative HTML version deleted]]

Hi, All, I have a dataset with binary response ( 0 and 1) and some numerical covariates. I know I can use logistic regression to fit the data. But I want to consider more locally. So I am wondering how can I fit the data with 'loess' function in R? And what will be the response: 0/1 or the probability in either group like in logistic regression? Thank you, Cindy [[alternative HTML

Hi, I have a very basic question about install packages from CRAN on unix. I only installed on Windows before. Should I use the command install.package? The error message I got is syntax error near unexpected token `"mvtnorm"' Is it because I didn't set the path? Which path should I specify? Thanks, Cindy [[alternative HTML version deleted]]

Hi, I have a R package, which is a .tar.tar file. And it is said to be source code for all platforms. And the author said it should install on any system (but he didn't know about Windows). I am wondering if I can use this package in Windows R. Thank you, Cindy [[alternative HTML version deleted]]

Hi, I want to generate random samples from truncated normal say Normal(0,1)Indicator((0,1),(2,4)). It has more than one intervals. In the library msm, it seems to me that the 'lower' and 'upper' arguments can only be a number. I tried rtnorm(1,mean=0,sd=1, lower=c(0,2),upper=c(1,4)) and it didn't work. Can you tell me how I can do truncated normal at more than one intervals?

Hello, everyone, I have a matrix like following: school value A .1 A .2 A .15 A .2 B .3 B .5 C .3 C .3 C .4 C .5 C .6 C .9 C 1 I want to get the mean 'value' for each 'school', but each school has different length. Is there any way to do this fast? Because my

Hi, All, I want to fit a normal mixture model. Which package in R is best for this? I was using the package 'mixdist', but I need to group the data into groups before fitting model, and different groupings seem to lead to different results. What other package can I use which is stable? And are there packages that can automatically determine the number of components? Thank you, Cindy

Tena koe Simon plot(1:10, 1:10, type='n') polygon(c(2,3,6,8), c(2,5,5,3), density=20, angle=90) polygon(c(2,3,6,8), 5+c(2,5,5,3), density=20, angle=0) I don't understand your problem. Perhaps if you "provide[d] commented, minimal, self-contained, reproducible code" it would help. HTH .... Peter Alspach -----Original Message----- From: R-help [mailto:r-help-bounces at

The angle is not based on the polygon edges, but it can seem that way if you do not use the asp=1 argument in your plot. Try this example, > plot(1:10, 1:10, type='n') > x <- c(1, 3, 5, 3) > y <- c(3, 5, 3, 1) > polygon(x, y, angle=0, density=10) > polygon(x, y + 4.5, angle=45, density=10) > polygon(x + 4.5, y + 4.5, angle=90, density=10) > polygon(x + 4.5, y,

Thanks for the question. Here is a sample of the code for my plot: Top = c(34, 39, 42, 45, 46, 41, 41, 40, 43, 38, 33, 33) Bottom = c(24, 29, 32, 36, 32, 34, 32,41, 40, 39, 29, 24) plot(1,1, col = "white", xlim = c(1.3,11.7), ylim = c(0,80), axis = FALSE, xaxt = "n") axis(1, at = c(1:12)) polygon(c(c(1:12),c(12:1)), c(top, bottom), col =

Hello all, I'm sorry if my question seems basic. Im studying a responses (Yes,No) in a survey and, thanks to GLM I obtain the following relation with my variables : (Yes,No)~ ?0 + Age We note this this certain type of (Yes,No) response is linked to age (p<0.05 in glm) . After that we calculated : model1=glm(cbind(Yes,No) ~ Age + Times + Type, family=binomial) summary(model1)

Dear Lenny, You can do this by using Age as an offset factor. dataset$wAge <- dataset$Age * 1.02 glm(cbind(Yes,No) ~ offset(wAge) + Times + Type, family=binomial, data = dataset) Best regards, ir. Thierry Onkelinx Statisticus / Statistician Vlaamse Overheid / Government of Flanders INSTITUUT VOOR NATUUR- EN BOSONDERZOEK / RESEARCH INSTITUTE FOR NATURE AND FOREST Team Biometrie &

Dear Thierry, Thanks a lot for this answer, I mean i want to obtain such model *Behavior1 = ?0+?1*Age* , the purpose is to obtain *?1*. I want to be sure that the odds value could be the ?1. Or how to calculate it ? Thanks again for your precious help. Lenny <http://www.avg.com/email-signature?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail>

Hi, I'm looking the best way to fill irregular polygons with patterns, Something like the function grid.pattern do, but my case is with irregular polygons. Whit this script I can get it, but I'm looking for an "elegant" solution.. library(grid) grid.polygon(x=c(0.2, 0.8, 0.6, 0.6, 0.8, 0.2), y=c(0.2, 0.2, 0.3, 0.5, 0.7,0.7), gp=gpar(fill="grey",

I would like to see R packages arranged by topic. CRAN Task Views are at http://lib.stat.cmu.edu/R/CRAN/src/contrib/Views/ , but I'd like something more detailed. For example, the IMSL Fortran library, version 4 is easy to navigate and has procedures arranged according to following topics: Basic Statistics Regression Correlation Analysis of Variance Categorical and Discrete

When I type library() to see what is installed the following list in RED comes up. Packages in library '/home/jason/R/i686-pc-linux-gnu-library/2.13': abind Combine multi-dimensional arrays aplpack Another Plot PACKage: stem.leaf, bagplot, faces, spin3R, and some slider functions biglm bounded memory linear and

Dear R users, I have created a Loess surface in R, in which x is relative longitude by miles, y is relative latitude by miles, and z is population density at the neighborhood level. The purpose is to identify some population centers in the region. I'm wondering if there is a way to determine the coordinates (x,y) of each center, so I can know exactly where they are. Let me use the

I am trying to use the angle option in polygon to create polygons filled with horizontal and vertical lines. The polygons I am crating are irregular and it the angle function appears to set the angle of the shading perpendicular to the polygon sides rather than perpendicular to the axes. Is there any way to set the angle relative to the axes rather than relative to the polygon sides?