Displaying 20 results from an estimated 400 matches similar to: "lme:correlationstructure AR1 and random factor"
2011 Mar 21
0
binary data with correlation
Dear posters,
I have a question concerning binary data analysis. I have presence absence
data of 5 sampling sessions within 3 years, of 12 fields. Each field had 12
traps. I would like to analyse the data with a Generalized Estimating
Equations (GEE) Model in R. For the abundance data I used a gls with the
function:
correlation = corARMA(form = ~ session|trapfield, p = 1, q = 0)
But now I want
2012 Apr 19
2
Gls function in rms package
Dear R-help,
I don't understand why Gls gives me an error when trying to fit a
model with AR(2) errors, while gls (from nlme) does not. For example:
library(nlme)
library(rms)
set.seed(1)
d <- data.frame(x = rnorm(50), y = rnorm(50))
gls(y ~ x, data=d, correlation = corARMA(p=2)) #This works
Gls(y ~ x, data=d, correlation = corARMA(p=2)) # Gives error
# Error in
2006 Mar 04
1
replicated time series - lme?
Dear R-helpers,
I have a time series analysis problem in R:
I want to analyse the output of my simulation model which is proportional
cover of shrubs in a savanna plot for each of 500 successive years. I have
run the model (which includes stochasticity, especially in the initial
conditions) 17 times generating 17 time series of shrub cover.
I am interested in a possible periodicity of shrub
2003 Jul 08
1
Questions about corARMA
Hi,
I'm a new member here in the list. I am a graduate from University of Georgia. Recently in doing analysis using lme on a dataset, I found several questions:
1. How to express the equation when the correlation structure is very complicated. For exmaple, if the fixed is y(t)=0.03x1(t)+1.5x2(t)(I omitted "hat" and others). And the model with corARMA(p=2,q=3) is proper. What will be
2012 May 02
3
Consulta gráfica
Hola,
Por favor, ¿podríais indicarme qué recursos (librerías o ideas) pueden resultar de utilidad para crear un gráfico del estilo del de la figura 3.8 del siguiente link?
http://www.tsc.uvigo.es/BIO/Bioing/ChrLDoc3.html#3.5
Actualmente estoy utilizando funciones muy básicas y la verdad es que no me encuentro muy satisfecha con el resultado.
Muchas gracias.
Eva
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2005 Apr 14
1
lme, corARMA and large data sets
I am currently trying to get a "lme" analyses running to correct for the
non-independence of residuals (using e.g. corAR1, corARMA) for a larger data
set (>10000 obs) for an independent (lgeodisE) and dependent variable
(gendis). Previous attempts using SAS failed. In addition we were told by
SAS that our data set was too large to be handled by this procedure anyway
(!!).
SAS script
2007 Oct 10
2
corMatrix crashes with corARMA structure (PR#9952)
Full_Name: Benjamin Tyner
Version: 2.6.0 RC 2007-10-01 r43043
OS: WinXP
Submission from: (NULL) (171.161.224.10)
platform i386-pc-mingw32
arch i386
os mingw32
system i386, mingw32
status RC
major
2012 Feb 17
2
Error message in gamm. Problem with temporal correlation structure
HELLO ALL,
I AM GETTING AN ERROR MESSAGE WHEN TRYING TO RUN A GAMM MODEL LIKE THE ONE BELOW.
I AM USING R VERSION 2.14.1 (2011-12-22) AND MGCV 1.7-12.
M1 <-gamm(DepVar ~ Treatment + s(Year, by =Treatment), random=list(Block=~1), na.action=na.omit, data = mydata, correlation = corARMA(form =~ Year|Treatment, p = 1, q = 0))
THIS IS THE ERROR MESSAGE
Error in `*tmp*`[[k]] : attempt to
2005 Dec 09
1
R-help: gls with correlation=corARMA
Dear Madams/Sirs,
Hello. I am using the gls function to specify an arma correlation during
estimation in my model. The parameter values which I am sending the
corARMA function are from a previous fit using arima. I have had some
success with the method, however in other cases I get the following error
from gls: "All parameters must be less than 1 in absolute value". None
of
2007 Jul 31
5
Plotting a smooth curve from predict
Probably a very simple query:
When I try to plot a curve from a fitted polynomial, it comes out rather
jagged, not smooth like fitted curves in other stats software. Is there
a way of getting a smooth curve in R?
What I'm doing at the moment (for the sake of example) is:
> x <- c(1,2,3,4,5,6,7,8,9,10)
> y <- c(10,9,8,7,6,6.5,7,8,9,10)
> b <- data.frame(cbind(x,y))
>
2006 Jan 05
1
Problem with nlme version 3.1-68
Dear All:
I updated my R program as well as associated packages yesterday. Currently
my R version is 2.2.1 running under WINXP SP-2.
When I tried to list (summary) an nlme object that I developed before, I got
the following error message:
[ Error in .C("ARMA_constCoef", as.integer(attr(object, "p")),
as.integer(attr(object, :
C entry point "ARMA_constCoef"
2004 Jul 30
1
lme: problems with corARMA
Trying following example from Pinheiro and Bates in order to fit an
ARMA(1,1) model:
library(nlme)
fm1Ovary.lme<-lme(follicles~sin(2*pi*Time)+cos(*pi*Time),data=Ovary,random=p
dDiag(~sin(2*pi*Time)))
fm5Ovary.lme<-update(fm1Ovary.lme,corr=corARMA(p=1,q=1))
I get follwing error message:
Error in "coef<-.corARMA"(`*tmp*`, value = c(62.3428455941166,
62.3428517930051 :
2008 Mar 04
1
Plot with two different coloured regression lines and legend
It is a trivial problem, but in the book I couln`t figure out how to put
different colours at different regression lines
plot(bif,abund,type="n", xlab= "number_bifurcations", ylab="abundances")
sbif<-split(bif,stage)
sabund<-split(abund,stage)
points(sabund[[2]],sbif[[2]],pch=16, col="red")
for(i in 1:2) abline(lm(sabund[[i]]~sbif[[i]]))
Thanks in
2005 Jun 10
1
Problems with corARMA
Dear all
I am tryiing to fit the following lme with an ARMA correlation structure:
test <- lme(fixed=fev1f~year, random=~1|id2, data=pheno2,
correlation=corARMA(value=0.2, form=~year|id2), na.action=na.omit)
But I get the following error message:
Error in getGroupsFormula.default(correlation, asList = TRUE) :
"Form" argument must be a formula
I have used this same form
2008 May 02
1
Errors using nlme's gls with autocorrelation
Hi,
I am trying out a generalized least squares method of forecasting that
corrects for autocorrelation. I downloaded daily stock data from Yahoo
Finance, and am trying to predict Close (n=7903). I have learned to use
date functions to extract indicator variables for Monday - Friday (and
Friday is missing in the model to prevent it from becoming full rank). When
I run the following code...
2006 Dec 06
1
Questions about regression with time-series
Hi,
I am using 2 times series and I want to carry out a regression of Seri1
by Serie2 using structured (autocorrelated) errors.
(Equivalent to the autoreg function in SAS)
I found the function gls (package nlme) and I made:
gls_mens<-gls(mening_s_des~dataATB, correlation = corAR1())
My problem is that I don’t want a AR(1) structure but ARMA(n,p) but the
execution fails :
2006 Nov 20
1
My own correlation structure with nlme
Dear all,
I am trying to define my own corStruct which is different from the
classical one available in nlme. The structure of this correlation is
given below.
I am wondering to know how to continue with this structure by using
specific functions (corMatrix, getCovariate, Initialize,...) in order to
get a structure like corAR1, corSymm which will be working for my data.
Thanks in advance.
2004 Apr 22
1
lme correlation structure error
Hi there fellow R-users,
I am trying to follow an example of modelling a serial correlation structure
in the textbook "Mixed Effects Model in S and Splus".
However, I am getting some very odd results. Here is what I am trying to
run:
library(nlme)
data(Ovary)
fm1<-lme(follicles~sin(2*pi*Time)+cos(2*pi*Time),data=Ovary,random=pdDiag(~s
in(2*pi*Time)))
### The example is fine up
2005 Jul 13
1
crossed random fx nlme lme4
I need to specify a model similar to this
lme.formula(fixed = sqrt(lbPerAc) ~ y + season + y:season, data = cy,
random = ~y | observer/set, correlation = corARMA(q = 6))
except that observer and set are actually crossed instead of nested.
observer and set are factors
y and lbPerAc are numeric
If you know how to do it or have suggestions for reading I will be
grateful.
eal
ps I have
2006 Nov 06
1
question about function "gls" in library "nlme"
Hi:
The gls function I used in my code is the following
fm<-gls(y~x,correlation=corARMA(p=2) )
My question is how to extact the AR(2) parameters from "fm".
The object "fm" is the following. How can I extract the correlation parameters
Phi1 and Phi2 from "fm"? These two parametrs is not in the "coef" componenet of "fm".
Thanks a