Displaying 20 results from an estimated 7000 matches similar to: "Integration with variable bounds"
2018 Mar 11
4
subsetting comparison problem
Hello All,
I am facing a unique problem and am unable to find any help in R help pages
or online. I will appreciate your help for the following problem:
I have 2 data-frames, samples below and there is an expected output
R Dataframe1:
C1 C2 C3 C4...... CN
R1 0 1 0 1
R2 1 0 1 1
R3
2018 Mar 12
0
subsetting comparison problem
> On Mar 11, 2018, at 3:32 PM, Neha Aggarwal <aggarwalneha2000 at gmail.com> wrote:
>
> Hello All,
> I am facing a unique problem and am unable to find any help in R help pages
> or online. I will appreciate your help for the following problem:
> I have 2 data-frames, samples below and there is an expected output
>
> R Dataframe1:
> C1 C2
2003 Nov 24
2
Questions on Random Forest
Hi, everyone,
I am a newbie on R. Now I want to do image pixel classification by random
forest. But I has not a clear understanding on random forest. Here is some
question:
As for an image, for example its size is 512x512 and has only one variable
-- gray level. The histogram of the image looks like mixture Gaussian Model,
say Gauss distribution (u1,sigma1), (u2,sigma2),(u3,sigma3). And a
2011 Oct 05
2
cuhre usage ?? multidimensional integration
my=function(x){
len=1
for(i in 1:len){
y[i]=x[i]
}
g=1
w=NULL
t=NULL
for(i in 1:len)w[i]=x[i+len]
for(i in 1:len)t[i]=x[i+2*len]
for(i in 1:len)g=g*dnorm(y[i])*dnorm(w[i])*dnorm(z[i])
return(g)
}
cuhre(6,1,my,rep(-100,6),rep(100,6))
Error in crff(match.call(), integrand, "cuhre", libargs, ...) :
Additional argument not expected in the integrand function
function change to
2011 Jan 27
2
help for a loop procedure
Hello everybody!
I’m trying to define the optimal number of surveys to detect the highest
number of species within a monitoring season/session.
To do this I want to run all the possible combinations between a set of
samples and to calculate the total number of species for each combination of
2, 3, 4 …n samples events, so that at the end I will be able to define which
is the lowest number of
2005 Aug 08
2
zaphfc syslog flooding
Hi,
my zaphfc is flooding my syslog with two messages (even without asterisk
running). Is this "normal"?:
--------------------------------------------------
zaphfc: bchan rx fifo not enough bytes to receive! (z1=1360, z2=1353,
wanted 8 got 7), probably a buffer overrun.
zaphfc: dropped audio (z1=2712, z2=2695, wanted 8 got 17, dropped 9).
With Asterisk running (asterisk -vvvvvgc)
2011 Dec 06
2
configuring a package for own personal needs
Hi All,
There is a function in package "R2Cuba" called Cuhre that I need to use. It
keeps spitting out a new-line which I really dont want it to do. So I was
wondering what is the best way of configuring the package. I tried copying
and pasting the code into Cuhre2 and getting rid of the newline command BUT
that didn't work since it seems to have some private functions which I do
2011 Dec 02
1
R2Cuba package, failed with message ‘Dimension out of range’
Hi All,
I get the message failed with message ‘Dimension out of range’ when using
cuhre in package R2Cuba. Does anyone know what this mean? Or would I need
to email the package author?
The funny thing is it does give a result and comparing it to
"adaptIntegrate" in package cubature, the two numbers are very close.
Thanks,
Sachin
[[alternative HTML version deleted]]
2007 Mar 27
7
Replacement in an expression - can't use parse()
Dear all,
Suppose I have a very long expression e. Lets assume, for simplicity, that it is
e = expression(u1+u2+u3)
Now I wish to replace u2 with x and u3 with 1. I.e. the 'new'
expression, after replacement, should be:
> e
expression(u1+x+1)
My question is how to do the replacement?
I have tried using:
> e = parse(text=gsub("u2","x",e))
> e =
2006 Nov 21
2
Symbolic derivation using D in package stats - how do I properly convert the returned call into a character string?
Dear all,
I am using the function 'D' in the 'stats' package to perform symbolic
derivation.
This works very well and it is much faster than e.g. Mathematica (at
least for my purposes).
First, I would like to thank the development team for this excellent
function.
However, I run into trouble in some cases, particularly when I am to do
some operations on long expressions
2009 Feb 05
1
optimal control, maximization with several variables?
Dear all,
I would like to solve the following problem, which can be done with optimal control theory or dynamic programming:
max(x,y) a*u1+b*u2+c*f1(u2) s.t. 0<u1<x, 0<u2<f2(x,u2), x'=f3(u1,u2,x)
which can be rewritten if optimal control theory should be applied as
H=a*u1+b*u2+c*f1(u2)+lambda*(x') s.t. 0<u1<x, 0<u2<f2(x,u2)
The maximum principle
2012 Dec 06
1
Anomalous outputs from rbeta when using two different random number seeds
Hi, in the code below, I am drawing 1000 samples from two beta
distributions, each time using the same random number seed.
Using set.seed(80) produces results I expect, in that the differences
between the distributions are very small.
Using set.seed(20) produces results I can't make sense of. Around half of
the time, it behaves as with set.seed(80), but around half of the time, it
behaves
2016 Dec 07
4
You have not permission to view content of this location
OS: CentosOS 7
I have installed samba + openldap + smbldap-tools + pam by:
yum --enablerepo=extras install -y epel-release
yum install -y smbldap-tools
yum install -y samba openldap openldap-clients openldap-servers migrationtools
yum install -y nss-pam*
I know that smbldap-tools is a dead project, but I'm interested in it and would like research on it.
I create users and
2011 Sep 11
3
(no subject)
Dear all,
Can anyone take a look at my program below?
There are two functions: f1 (lambda,z,p1) and f2(p1,cl, cu).
I fixed p1=0.15 for both functions. For any fixed value of lambda (between
0.01 and 0.99),
I solve f1(p1=0.15, lambda=lambda, z)=0 for the corresponding cl and cu
values.
Then I plug the calculated cl and cu back into the function f2.
Eventually, I want to find the lambda value
2012 Mar 13
1
Two dimensional integration
Dear R Members,
I want to know a fast R function to do multidimensional integration. I used
the function 'cuhre' in R2cuba library. But it takes painful time to get the
answer.
I would be thankful if anyone could help me out to solve this problem
Thanks
Niroshan
--
View this message in context: http://r.789695.n4.nabble.com/Two-dimensional-integration-tp4468282p4468282.html
Sent
2013 May 16
2
A function that can modify an object? Or at least shows principles how to modify an object?
Hi, If I have an R object UUU, where the second element is U2, based on
"g" column of my.table
my.table of UUU is:
mmm ggg gindex map Info
aaa123 U1 1 1 1
aaa124 U1 1 2 1
bbb1378 U2 2 1 1
bbb8888 U2 2 2 0
bbb1389 U2 2 3
2020 Apr 29
1
grid 4.0 generates wrong results when adding two complex units by sum()
Hi,
In grid 4.0, adding two complex units by `sum()` seems to give wrong results.
In the following example, `u1 + u2` gives the correct result, but `sum(u1, u2)` also `sum(unit.c(u1, u2))` give the wrong results.
```
library(grid)
u1 = 0.4*sum(unit(1, "inch"), unit(1, "mm"))
u2 = 0.1*sum(unit(1, "inch"), unit(1, "mm"))
u1
# [1] 0.4*sum(1inches, 1mm)
2006 Jul 08
2
String mathematical function to R-function
hello
I make a subroutine that give-me a (mathematical)
function in string format.
I would like transform this string into function ( R
function ).
thanks for any tips.
cleber
#e.g.
fun_String = "-100*x1 + 0*x2 + 100*x3"
fun <- function(x1,x2,x3){
return(
############
evaluation( fun_String )
############
)
True String mathematical function :-( :-(
> nomes
[1]
2012 Apr 24
2
Some Help Needed
Dear all,
I need to do some calculation where the code used are below. I get
error message when I choose k to be large, say greater than 25.
The error message is
"Error in integrate(temp, lower = 0, upper = 1, k, x, rho, m) :
the integral is probably divergent".
Can anyone give some help on resolving this. Thanks.
Hannah
m <- 100
alpha <- 0.05
rho <- 0.1
F0
2009 Nov 09
3
How to transform the Matrix into the way I want it ???
Hi, R users,
I'm trying to transform a matrix A into B (see below). Anyone knows how to
do it in R? Thanks.
Matrix A (zone to zone travel time)
zone z1 z2 z3 z1 0 2.9 4.3 z2 2.9 0 2.5 z3 4.3 2.5 0
B:
from to time z1 z1 0 z1 z2 2.9 z1 z3 4.3 z2 z1 2.9 z2 z2 0 z2 z3 2.5 z3 z1
4.3 z3 z2 2.5 z3 z3 0
The real matrix I have is much larger, with more than 2000 zones. But I
think it should