similar to: read.xls -> rotate data.frame

Hi, This might seem like a simple question but at the moment I am stuck for ideas. The columns of my matrix in which some data is stored are of this form: X1 Y1 X2 Y2 X3 Y3 ... Xn Yn with n~100. I would like to look at just the X values (i.e. odd column numbers). Is there an easy way to loop round extracting only these columns? Any help would be appreciated.

Dear all, I have two coordinates vectors, say X and Y of length n. I want to generate for each couple of coordinates X1,Y1 X2,Y2 X3,Y3....Xn,Yn a random coordinate which is located in a square define as X +/- dx and Y +/- dy. I saw the runif function which can generate for just one value at a time what I want : runif(1, X - dx, X + dx) for X and runif(1, Y - dy, Y + dy) for Y. I would like

From: xxgreat@hotmail.com To: r-help-bounces@r-project.org Subject: compare a vector and a row of a matrix Date: Sun, 26 Sep 2010 23:23:52 +0800 Hi Everyone: I am trying to compare a vector and rows of a matrix for example > xn <- c(1,2,4,4,5,5,5,6) >yn <- c(1,2,5,7,1,2,3,1) >mtrx <- cbind(xn, yn) when I tried, say, > c (1,4), the result was TRUE, TRUE.

Full_Name: Jonathan Lees Version: 1.8.1 OS: GNU/Linux 2.4.20-20.8smp #1 SMP Submission from: (NULL) (152.2.75.114) I am having trouble with the postscript output of images. They have lines on them that are not supposed to be there. I have noticed this on numerous trials of printing various images. I looked at the postscript and I see that it appears to plot each individual block - so perhaps

This is a covariance calculation question so nothing to do with R but maybe someone could help me anyway. Suppose, I have two random variables X and Y whose means are both known to be zero and I want to get an estimate of their covariance. I have n sample pairs (X1,Y1) (X2,Y2) . . . . . (Xn,Yn) , so that the covariance estimate is clearly 1/n *(sum from i = 1 to n of ( X_i*Y_i) ) But,

suppose I have two sets of vectors: x1,x2,...,xN and y1,y2,...,yN. I want N correlations: cor(x1,y1), cor(x2,y2), ..., cor(xN,yN). my sets of vectors are arranged as data frames x & y (vector=column): x <- data.frame(a=rnorm(10),b=rnorm(10),c=rnorm(10)) y <- data.frame(d=rnorm(10),e=rnorm(10),f=rnorm(10)) cor(x,y) returns a _matrix_ of all pairwise correlations: cor(x,y)

Hello, Can anyone give me some suggestion in term of calculating the sum below. Is there a function in R that can help doing it faster? x1, x2, ...xn where xi can be 0 or 1. I want to calculate the following: sum{ beta[a+sum(xi), b+n-sum(xi) ]* [ (1-x1)dnorm(0,1)+x1dnorm(2,1) ]* [ (1-x2)dnorm(0,1)+x2dnorm(2,1) ]* ...* [ (1-xn)dnorm(0,1)+xndnorm(2,1) ] } The sum in the beginning is over all

I am trying to send a manuscript to a journal. One of the figures build by R is in the right orientation and 4 are rotated clockwise 90 deg in the preview. I used the right click save to PS option and I used the command line postscript("c:/temp/fig04.eps",bg="transparent",onefile = TRUE ,pointsize=20,paper = "letter",height=8,width=8,horizontal=FALSE,family =

Hi all, I am currently compiling R to RISC-V64 CPU and I think I have discovered a NA propagation failure. How R implements NA (not available) and NaN (not-a-number) is explained in detail here: https://stat.ethz.ch/pipermail/r-devel/2014-February/068380.html. In short, according to my understanding of R's convention, any calculation involving NA but no NaN should result in NA (called NA

Is there any function to show the points like this example of SPSS? http://biostatistic.de/temp/reg.jpg The point size should represent the number of data at this point. with regards Knut Krueger

Dear R-users, I've been using R for a while and I am very satisfied! Unfortunately, I still have not figured out an efficient and general way to construct and use lags of time series, especially when I need to work with different packages. Let me give an example. I have two time series x and y and I want to estimate a variaty of distributed lags models and run different tests

Hi, I am attempting to write code which will read in my data which is of this form: X1 Y1 X2 Y2 .... Xn Yn 0 0 0 0 0 0 1 0 1 255 1 0 2 255 2 0 2 255 3 0 3 0

Is there any possibility to get high resolution plots in a windows xp system? I tried it with the device function png(filename = "c:/r/highresplot%d.png",pointsize=12, res=900) but when I try to set: width = 480, height = 480 or pointsize = 12, the text is not scaled in the same way as the plots. with regards Knut Krueger http://www.biostatistic.de

Hi to all I need a string like temp <- paste("m1","m2","m3",sep=",") But i must know how many items are in the string,afterwards the other option would be to use a vector temp <- c("m1","m2","m3") No problem to get the count of items but I must get afterwards the string "m1,m2,m3" No problem to build the

Hi to all, test <- data.frame("X"=c(1:4),"Y"=c(5:8),"Z"=c(8:11)) test <- test[,-2] Is there a way to specify the col name "Y" to delete instead the number? Kind regards Knut

Dear R list, For some reason I am unable to access neither search.r-project.org, nor http://finzi.psych.upenn.edu/ so I cannot search the archives for a possible answer (I Googled for this but didn't find anything). Is it possible to draw barplots using a texture instead of colors, for a black and white printer? TIA, Adrian -- Adrian Dusa Arhiva Romana de Date Sociale Bd. Schitu

If there is a helpfile open (f.e ?glm) and it is the top window, then an exception error occurs (closing RGUI) when I hit the open file button. If the helpfile is not the top window (of the RGUI) I am able to open a new script without any error. The RGUI is not closing complete there is a blank screen left which I have to close with the X Button or Taskmanager Windows XP Home - German Version

Hi to all, I am just looking for more efficient ways ;-) is there a better way instead a loop to decrease x if greater y test <- c(1,3,5,7,9) decrease if greater 1 to test2 <- c(1,2,4,6,8) Kind regards Knut

. I am looking for a histogram or box plot with the adding normal distribution curve I think that must be possible, but I am not able to find out how to do. Regards Knut

Hi to all I found an formular of an ** ***p-Value Calculator for the Chi-Square test* *http://www.danielsoper.com/statcalc/calc11.aspx* *with the formula* *http://www.danielsoper.com/statkb/topic11.aspx* *what's the gamma function of this formula in r?* *df=5* *ch2=25.50878* *the following code does not give the result <0.001 for the values above * *p=