similar to: fraction with timelag

Dear all, I would like to ask your help concerning an error message I get. I have the following struct str(CRagentInTime[[1]]) List of 2 $ timelag: int 0 $ CRagent:List of 50 ..$ :List of 3 .. ..$ CRmap: num [1:256, 1:256] NA NA NA NA NA NA NA NA NA NA ... .. ..$ xy : num [1:2] 10 177 .. ..$ sr : num [1:49] -94.9 -92.8 -79.5 -97.6 -78.4 ... and I wanted to select all the sr fields

Dear list, First my information: platform i386-pc-linux-gnu arch i386 os linux-gnu system i386, linux-gnu status major 2 minor 3.1 year 2006 month 06 day 01 svn rev 38247 language R version.string Version 2.3.1 (2006-06-01) Now my question: How is it possible that a command in an R script is not

Hello, I am trying to create subsets of grouped data (by area size), and use the area size as part of the output name. The code below works for area (xout) 1 and 50, the other files are given NA for an area. A simple example: xout <- c(1,5,10,25,50,100) for(i in xout) { print(paste("Areal_Ppt_",xout[i],"sqmi.txt", sep="")) } [1] "Areal_Ppt_1sqmi.txt"

I have this code: Link.find(params[:id]).toggle!(''active'') Before it, its timestamp is: 2005-11-20 20:45:48.741973-07 After: 2005-11-20 20:45:48-07 Why does Rails take it upon itself to truncate the seconds fraction? How can I get Rails to not change it? Thanks, csn __________________________________________________ Do You Yahoo!? Tired of spam? Yahoo! Mail has the best

Hi, After performing a multiple linear regression, I am looking for an R package that can calculate the fraction [a] a partitioning of variation. This fraction measures the proportion of variance of y explained by the explanatory variable x1 (for example) when other variables (x2, x3 ...) are held constant. Thank you in advance for your help -- View this message in context:

Dear all,   I have the following written example > coords <- "51°30'48.58\"N" > > as.integer(strsplit(coords, "°")[[1]][1]) [1] 51 > as.integer(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][1]) [1] 30 > as.numeric(strsplit(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][2],

Hello I like to call to 2 providers provider X = IAX provider Y = SIP exten => _06.,1,Dial(IAX2/X/${EXTEN},30,r)&(SIP/${EXTEN}@Y.Y.Y.Y) exten => _06.,2,Hangup Provider X is working but provider Y never shows up. What's wrong ?? How can I get provider Y working a fraction earlier the provider X Thanks Sjaak

I have used packages rpart, mvpart and tree for classification and regression trees. I want to calculate fraction of null deviance explained by each node and variable in the tree. For instance, at the first split, this would be (1 - (sum of residual deviance in each of the two leaves)/deviance at the root). In the subsequent splits, this formula is slightly different. There probably is a function

Hi, On Thu, Mar 5, 2015 at 2:18 PM, SellBuy Sammamish <sellbuysam at gmail.com> wrote: > Friends, > > My name is Igor, I am new to this forum. > > I have a peculiar problem with my OGG/Speex implementation: I encode a short > PCM stream in OGG/Speex, but the result can not be read by VLC and MediaInfo > reports that the file is too short (240ms). In reality the file

subject: trimmed mean in R seems to round the trimming fraction to r-help at stat.math.ethz.ch. Consider the following example of 10 numbers. 10% trimmed mean is correct but you can see that the result is the same for many trimming fractions till 0.20! For example 13% trimmed mean should use interpolation of second and eighth ordered observation. R does not seem to do this. The correct 13%

Hi all, I would like to plot part of the emperical CDF. Suppose the variable is x, I just need the part when x>1,therefore, I am using the following codes. tail <- x>1 plot(ecdf(x[tail]), do.points=FALSE, verticals=TRUE) The "x" value starts from 1, but the yaxs still begins from 0, not the corresponding value when "x" is 1. How can I make it match? Could anyone

Dear R users I wonder if there is a quick way to calculate the ratio/fraction of a list/data frame. For example, if I have a data frame with two fields: "Index" and "A". I would like to know the fractions of A's within the same "Index". That is, for Index =1, three fractions will be "1/(1+2+3)=0.17", "2/(1+2+3)=0.33", and

Hi, Dear Greg, Sorry to bother you again. I have several questions about the 'gbm' package. if the train.fraction is less than 1 (ie. 0.5) , then the* first* 50% will be used to fit the model, the other 50% can be used to estimate the performance. if bag.fraction is 0.5, then gbm use the* random* 50% of the data to fit the model, and the other 50% data is used to estimate the

I am trying to find the important factors from a two level fraction factorial design (2^{8-4}) I have studied the companion of vikneswaran but would really like a basic example of how to do this: (adapted to 8 factors): mydata<-read.table("myfile.txt", header=T) summary(aov(resp ~ A*B*C*D*E*F*G*H, data = mydata)) However i can't figure out how the input files are supposed to

Dear All, I would like to know how to do the following: 1. suppose I have x values from the ordered from 0, 0.5, 1, and would like to label these three points on the x-axis. 2. However, R labels them as 0.0, 0.5, 1.0. But I wan5 them to be 0, .5, 1, since the former way uses limited space of a multi-subgrap plot by adding extra zeros Thank you, Chee [[alternative HTML version deleted]]

Dear list, I understand that to raise matrix A to power (-1/2) we should use something like this: eigen(A)$vectors%*%diag(1/sqrt(eigen(A)$values))%*%t(eigen(A)$vectors) [from previous discussions: http://r.789695.n4.nabble.com/matrix-power-td900335.html] But this will only do it for negative sqrt of the matrix not for other fraction powers like (-3/2). Seeing that these things be can done

Hi all, I've got a matrix of fractional data that is all positive and greater than zero that I would like to "loosely" classify, for lack of a better word. It looks something like this : 1.07 1.11 1.27 1.59 0.97 0.76 2.23 0.98 0.71 0.88 1.19 1.02 What I'm looking for is a way to round these numbers to the nearest 0.25, i.e. the above matrix would be

hello i am a new user of R I wonna run a double exponential function with nonlinear quantile regresion model the double exponential function is Y=( ab1978*ab1979*ab1980*ab1981*ab1982*ab1983*ab1984*ab1985*ab1986*ab1987*ab1988*ab1989* ab1990* ab1991*ab1992*ab1993*ab1994* 6670*ab7175*ab7680*ab8185*ab8690*ab9193*abgg*abgf*abgu*abgj*abgd*abfg*abff*abfu*abfj*abfd*abug*abuf*abuj*abud*

Dear R-devel, The following line crashes R > approx(1, 1, 0, method='const', rule=2, f=0, yleft=NULL, ties='ordered')$y Process R:2 exited abnormally with code 5 at Tue Jul 21 14:18:09 2009 > version _ platform i386-pc-mingw32 arch i386 os mingw32 system i386, mingw32 status major 2 minor 9.1 year

Buenos días: Después de más de 20 años en SAS, ahora igual me toca trabajar en R. Y la transición es muy dura: la "lógica" de los dos lenguajes es, para mi, totalmente diferente. Disculpen si lo que pregunto es una obviedad, pero llevo todo el día con esto y no logro encontrar la respuesta adecuada con google. Estoy intentado crear una función que realice una descriptiva simple de