similar to: Kendall v MannKendall Functions

Displaying 20 results from an estimated 3000 matches similar to: "Kendall v MannKendall Functions"

2011 Sep 02
1
Mann Kendall Test for Trend
Hi there, I'm trying to apply the Mann Kendall test for trend analysis of a time series. I have downloaded and installed the package Kendall and subsequently loaded it into the software. My time series is a .txt file with 2 columns - column 1 is the year (1985 - 2009) and column 2 is the corresponding entry variable. According to the R guidelines, the call should be: MannKendall(x)
2007 Sep 06
3
kendall test
Hello, I thougth that there is a function which does the kendall test in R, I writed on the console apropos("kendall") and I didn't found anything can you tell me how could I do to use the kendall test? Thanks. _____________________________________________________________________________ l [[alternative HTML version deleted]]
2011 Mar 21
1
Basic Looping Trouble
Hi all, Forgive me for this basic question. I've been doing some research and haven't been able to figure out how to best do this yet. I have 75 variables defined as vector time series. I am trying to create a script to automate calculations on each of these variables, but I wasn't sure how to go about calling variables in a script. I am hoping to write a loop that calls a list of
2009 May 13
0
Mann-Kendall test
Dear useRs, I've been trying to run a Mann-Kendall test in my data in order to detect trends. I studied the examples given at the Kendall package and I can understand pretty well how it works on time-series data. However, my data consists of values in different sites per year, as I display below;              Year 1 | Year 2 | Year 3 | ... Site 1        x           x          x       ...
2008 Nov 21
1
Bug in Kendall for n<4?
> library(Kendall) > Kendall(1:3,1:3) WARNING: Error exit, tauk2. IFAULT = 12 <<<<<< tau = 1, 2-sided pvalue =1 I believe Kendall tau is well-defined for this case and the reported value is correct; isn't it a bug to give a warning? (And if, e.g., the pvalue is not well-defined in this case, wouldn't it be better to return NA or NaN or something?) Also,
2009 Oct 20
1
kendall.global
Hi every body: I need some help with kendall.global. The example in the manual seems not working well, and cannot used with my data, always the same error. data(mite) > mite.hel <- decostand(mite, "hel") > > # Reproduce the results shown in Table 2 of Legendre (2005), a single group > mite.small <- mite.hel[c(4,9,14,22,31,34,45,53,61,69),c(13:15,23)] >
2004 May 13
1
Bootstrapping kendall cor
Dear R-helpers, I'm fighting with the following problem : I want to do bootstrapping on a Kendall correlation with the following code : > cor.function <- function(data,i) cor(data[i, 1], data[i, 2],method="kendall") > boot.ci <- boot.ci(boot.cor <- boot(cbind(x,y),cor.function, R=1000),conf=c(0.95,0.99)) However, I've got problems because I've got ties
2012 Aug 20
1
Kendall package tau-a, b, and c
Hi all, I would like to ask a question related to Kendall package. I ran Kendall (x,y) and saw the results. But I am not sure which tau values R reported. I have ties in my data set, so I want tau-b. Can anybody tell how Kendall package is calculating tau values? I have looked at the package PDF, but I could not find any useful information. As long as I see from the following link, there
2012 Apr 17
2
Installing Kendall Package
I know this is a dumb question but I'm pulling out what little hair I have left. I download the package and got the following: trying URL ' http://ftp.ussg.iu.edu/CRAN/bin/windows/contrib/2.14/Kendall_2.2.zip' Content type 'application/zip' length 52732 bytes (51 Kb) opened URL downloaded 51 Kb package ‘Kendall’ successfully unpacked and MD5 sums checked The downloaded
2005 Aug 18
2
kendall tau correlation test for ties: Potential error (PR#8076)
Full_Name: Dirk Koschuetzki Version: 2.1.1 OS: source code Submission from: (NULL) (194.94.136.34) Hello, >From the source code (R-2.1.1, file: .../R-2.1.1/src/library/stats/R/) ****************************** cor.test.default <- function(x, y, alternative = c("two.sided", "less", "greater"), method = c("pearson", "kendall",
2023 Dec 01
2
Mann Kendall mutation package?
Hello - does anyone know whether there are any packages for Mann-Kendall mutation tests in R available? The only one I could find online is this MK_mut_test: Mann-Kendall mutation test in Sibada/sibadaR: Sibada's accumulated R scripts for next probably use to avoid reinventing the wheel. (rdrr.io) <https://rdrr.io/github/Sibada/sibadaR/man/MK_mut_test.html> but there doesn't seem to
2011 Mar 09
1
Theil Kendall line as fit?
I found some code to compute a Kendall-Theil slope estimate and want to add it to a scatter plot. Is there a way to make it appear like a regression fit instead of a line that extends from the edges of the plot? I would like to have the OLS appear as a dotted line and the KT a solid line but as it is the KT line is longer. -- View this message in context:
2013 Feb 28
1
PCA with spearman and kendall correlations
Hello, I would like to do a PCA with dudi.pca or PCA, but also with the use of Spearman or Kendall correlations Is it possible ? Otherwise, how can I do, according to you ? Thanking you in advance Eric Bourgade RTE France [[alternative HTML version deleted]]
2011 Mar 22
1
Looping Problem
Hi all, I am trying to write a script that will automate the task of running a Kendall's Tau correlation test on 75 time series that I am interested in. The code I have written is: for(i in 1:length(gagehandles)){ dates<-get(paste(gagehandles[i],"_amsd",sep="")) q<-get(paste(gagehandles[i],"_amsq",sep="")) taup<-Kendall(dates,q)
2004 Mar 03
1
cor(..., method="spearman") or cor(..., method="kendall") (PR#6641)
Dear R maintainers, R is great. Now that I have that out of the way, I believe I have encountered a bug, or at least an inconsistency, in how Spearman and Kendall rank correlations are handled. Specifically, cor() and cor.test() do not produce the same answer when the data contain NAs. cor() treats the NAs as data, while cor.test() eliminates them. The option use="complete.obs" has
2006 Sep 13
2
kendall's w
Hi, I try to calculate Kendall's W coefficient and I have a bizarre error. little.app.mat<-matrix(c(1,3,4,2,6,5,2,4,3,1,5,6,3,2,5,1,5,4),nrow=3,byrow=TRUE) print(kendall.w(little.app.mat[-1,])) >>> Kendall's W for ordinal data >>> W = 0.7753623Error in if (is.na(x$p.table)) { : argument is of length zero
2008 Jun 27
1
Yule Kendall resistant measure of skewness
Dear R Users, Is anyone aware of a package which calculates the Yule Kendall resistant (to errors,outliers) measure of skewness ? An easy calculation to perform, but was just wondering if a package exists (as the contents of that package would probably include other cool things I would also be interested). Thanks, Tolga Generally, this communication is for informational purposes only and it
2009 Dec 13
2
O(N log N) Kendall Tau
I've noticed that the implementation of Kendall's Tau in R is O(N^2). The following reference describes how it can be done in O(N log N): A Computer Method for Calculating Kendall's Tau with Ungrouped Data William R. Knight Journal of the American Statistical Association, Vol. 61, No. 314, Part 1 (Jun., 1966), pp. 436-439 http://www.jstor.org/pss/2282833 I'm interested in
2005 Aug 13
1
R/S-Plus/SAS yield different results for Kendall-tau and Spearman nonparametric regression
Colleagues, I ran some nonparametric regressions in R (run in RedHat Linux), then a colleague repeated the analyses in SAS. When we obtained different results, I tested S-Plus (same Linux box). And, got yet different results. I replicated the results with a small dataset: DATA: 37.5 23 37.5 13 25 16 25 12 100 15 12.5 19 50 20 100 13 100 10 100 10 100 16 50 10 87.5
2006 Sep 12
1
Kendall's tau-c
Hello, I can't find a package which calculates Kendall's tau-c. There is the package Kendall, but it only calcuates Kendall's tau-b. Here is the example from ttp://www2.chass.ncsu.edu/garson/pa765/assocordinal.htm. cityriots <- data.frame(citysize=c(1,1,2,2,3,3), riotsize=c(1,2,1,2,1,2), weight=c(4,2,2,3,0,4)) cityriots <- data.frame(lapply(cityriots,function(x)