similar to: Stucked with as.numeric function

Hi List, I''m trying to get my ListCtrl to work. Currently I''ve managed to fill my ListCtrl with items, but I think it''s not the most beautiful way: class MyList < Wx::ListCtrl def initialize(parent, *args) super(parent, :style => Wx::LC_REPORT|LC_HRULES ) create_layout fill_list end def create_layout self.insert_column(0, "Name")

Hi, In some cases the number of arguments passed as ... must be determined inside a function, without evaluating the arguments themselves. I use the following construct: dotlength <- function(...) length(substitute(expression(...))) - 1L # Usage (returns 3): dotlength(1, 4, something = undefined) How can I define a method for length() which could be called directly on `...`? Or is it an

Dear R Core Team, I learnt approx. two years ago in this mailing list that one can use the following "trick" to get a (dotted pair)list of the ellipsis arguments inside a function: `substitute(...())` Now my problem is that I can not find any occurrence of this call within the R source - the most frequent solution there is `substitute(list(...))[-1L] ` I would like to know if: 1)

Hello, can anybody tell me a easy way to change the mode of an "aggregate list" to "numeric"? I found a solution but I looks cruel. Thank's Felix PS: In the past you have asked what I am doing. I have to evaluate measures of two gauges of our university. The aim is to get an answer which one is better. > mode(MEAN) [1] "list" > mode(MEASURE) [1]

Hello I have around 200 PDF-documents, containing data i want organized in R as a dataframe. The PDF-documents look like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver.jpeg or like this; http://www.nabble.com/file/p21667074/PRRS-billede%2Bmed%2Bfarver%2B2.jpeg So i want to pull out the data in coloured boxes it become organized like this (just in R instead of

And the related: > f = function() stop(return("lol")) > f() [1] "lol" I have a feeling all of this is just return() performing correctly though. If there are already R CMD CHECK checks for this kind of thing (I wasnt sure but I'm hearing from others there may be/are) that may be (and/or may need to be) sufficient. ~G On Fri, Nov 20, 2020 at 3:27 PM D?nes T?th

hello, this is my script: #1) read in data: daten<-read.table('K:/Analysen/STRUCTURE/input_STRUCTURE_tab_excl_5_282_559.txt', header=TRUE, sep="\t") daten<-as.matrix(daten) #2) create empty matrix: indxind<-matrix(nrow=617, ncol=617) indxind[1:20,1:19] #3) compare cells to each other, score: for (s in 3:34) { #walks though the matrix colum by colum, starting at

Without having dug into the details, it could be that one could update the parser by making a 'return' a keyword and require it to be followed by a parenthesis that optionally contains an expression followed by end of statement (newline or semicolon). Such a "promotion" of the 'return' statement seems backward compatible and would end up throwing syntax errors on:

Benjamin, You happened to send a link which points to the OP's own package :) I think Jiefei would like to know how one can "officially" determine if an arbitrary ALTERP object belongs to a class that he owns. Regards, Denes On 10/19/20 10:22 AM, Benjamin Christoffersen wrote: > It seems as if you can you use the ALTREP macro as done in this > package:

hallo, i have a problem by writing a csv file the first colum is filled with index numbers from 1 to n. i have to unique two csv files once a week while one file is always the same. can anybody tell me, how to write the dataset into a csv file without the first row of the indexnumbers. x[,-1] does not wok as it eliminates the first "interesting" colum. col.names is not accepted by r

Hi everybody How do I do to calculate the median and average of a colum of time data like this: "8:50:10". I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com.

Hi I have found a little problem with an R script. I am trying to merge some data and am finding something unusual going on. As shown below I am trying to assign (MatchedValues[Value2,Value]) to (ClusteredData[k,Value]) which are two separate dataframes. 1) By the following command you can see that the value im transferring is 481844.03 > MatchedValues[Value2,Value] [1] 481844.03 6618

Hi, For some reason do.call on anova fails if the models are named lmer objects. Consider the following example: library(lme4) models <- list( lmer(Reaction ~ Days + (1| Subject), sleepstudy), lmer(Reaction ~ Days + (Days | Subject), sleepstudy)) # # models is an unnamed list, do.call works (although with warning): do.call(anova, models) # # after labeling the models, do.call gives an

Hi I want to set a variable to either 1 or 0 depending on an value of a dataframe and then add this as a colum to the dataframe. This could be done with a loop but as we are able to do questions on a complete row or colum without a loop it would be sweet if it could be done. for example: table: Name Age Joel 24 agust 17 maja 40 and so on... And what I want to do is a command that

Dear R-Core Team, I found an unexpected behaviour in utils::removeSource (also present in r-devel as of today). --- # create a function which accepts NULL argument foo <- function(x, y) { if (is.null(y)) y <- "default foo" attr(x, "foo") <- y x } # create a function which utilizes 'foo' testSrc <- function() { x <- 1:3 x <- foo(x,

Hi You wrotte me in R help and I´m very gratefull. I couldn´t reply because an illness. I writte this to see if you can help to solve. I´m a begginer (I´m 20 years old ) but I´m trying to learn more about this program also I´m learning Octave. I need to create a matrix in R whose values depends on the values of other matrix. You see: I have a first "R" matrix whose first row and

Hello, I have a problem with reading a csv-file. One colum of the inputfile consists of characters and numbers. After reading the csv-file I create a new dataframe by dividing the values of that colum into more colums (then a colum contains just characters or numbers) but the numbers are converted to factors. How can I create the new dataframe without having the numbers converted to factors?

Thank Denes for the clarification, glad to see my package got one citation from my own question:) Also, thank Benjamin for sending many useful documents. Actually, the question is related to the SharedObject package that Benjamin has pointed to. I wanna avoid sharing an object that has already been shared, so I need to check whether an object is an ALTREP that is defined in my package. Since the

AFAIK there is no hashing utility in base R which can create hash digests of arbitrary R objects. However, as also described by Henrik Bengtsson in [1], we have tools::md5sum() which calculates MD5 hashes of files. Calculating hashes of in-memory objects is a very common task in several areas, as demonstrated by the popularity of the 'digest' package (~850.000 downloads/month). Upon

Hi all: Can someone help me count the number of rows with values in colum "a" only. assume the name of my dataframe is "weekly" I was trying i<- nrows(weekly$a) i but returns 7 when it should be 4. Thanks a b c d 27.000 27.000 1.569 0.013 160.000 27.000 1.632 0.013 146.000 27.000 1.830 0.015 70.000 27.000 2.475 0.019