similar to: creating list of lists

Hello, Below is a function (test.map) that permits drawing the same map using three different devices. The "pdf" device doesn't clip polygons to the plot region as I see it does by both the native device (in my case "Quartz") and the "png" device. test.map("pdf") # produces "test-map.pdf" with no clipping test.map("png") #

I'm attempting to run a rather complex routine that involves a few loops, and even some use of foreach and doMPI. I just added another external loop and now get this error message. Error in { : task 3 failed - "NA/NaN argument" Is there a way to debug what is causing this error or where? I really have no idea what "task 3" is? Thanks Jim

Hello, I am working with a database system from which I can retrieve these kinds of user defined fields formed as XML ... <udf:field unit="uM" type="Numeric" name="facs.Stain final concentration">5</udf:field> You can see in the above example that "field" is defined in the namespace "udf", but that the "udf" namespace is

Hi, I have one xml file. <Class> <Node1 code ="1"> First node </Node1> <Node2 code ="1"> Second node </Node2> <Node3 code ="1"> Third node </Node3> <Node1 code ="2"> Fourth node </Node1> </Class> for (i in 1:xmlSize()) { print(Class[i]) # how can i filter Node1 ? } by

The cubic regression of my model is significant and I want to plot a line that best fits. It's not abline() function, because it has a curve. Please, how can I plot it? --- Fernando Andreacci Biólogo Fone +55 47 9921 4015 fandreacci@gmail.com [[alternative HTML version deleted]]

Hi I need to know how to make pch symbols like pch=3 (+) or pch=4(x) or even the border of squares or triangles thicker without changing the size. I have a lot of symbols of different colors but you can't see the colors clearly and I don't want to change the symbol. Thanks! -- View this message in context: http://r.789695.n4.nabble.com/How-to-make-pch-symbols-thicker-tp4648295.html

What is wrong with the following? x <- 1:2 if(x[1] > 0) { if(x[2] > 0) { print("1 & 2 > 0") } else { print("1 > 0") } } else { if(x[2] > 0) {

Dear R Community, I recently switched to a Mac (10.6.5), and have installed Textwrangler to run code to R. However, I can't install the syntax highlighting file because I can't find the directory: "~Users/username/Library/Application Support/TextWrangler/Language Modules/". Is there a different location I can place the syntax highlighting file? Scott [[alternative HTML

I need to construct a custom XML reader, the files I'm working with are in funky XML format: <str name="author">Paul H</str> <str name="country">USA</str> <date name="created_date">2010-02-16</date> I want to read the file so it looks like: author = Paul H country = USA created_date=2010-02-16 Does any one know how to

I'm trying to upload a file using RCURL:s ftpUpload() to a ftp-server using the following command: > ftpUpload("'VERY.ODD.FILE.NAME(+1)'",to="ftp://x.x.x.x/","' VERY.ODD.FILE.NAME(+1)'",userpwd="USER:PASSWORD") OK 0 The file I'm trying to upload is a very simple text-file but with a bit weird filename. Note the ' on each

Is there a way to convince R to create a character vector without using the quotes? This works ex1 <- c("first","second") but when I try this it doesn't ext <- as.character(c(first,second)) it complains. I have many variables to put into character vectors so dispensing with the quotes would be useful. Thanks Jim =============================== Dr. Jim Maas

Hi, is there a function or an easy way to convert a variable with continuous values into a categorial variable (with x levels)? here is what I mean: I want to transform x: x <- c(3.2, 1.5, 6.8, 6.9, 8.5, 9.6, 1.1, 0.6) into a 'categorial'-variable with four levels so that I get: [1] 2 2 3 3 4 4 1 1 so each element is converted into its rank- value / categorial-value (in

Wanting a commandline solution (for a problem detailed @ http://mailman.unidata.ucar.edu/mailing_lists/archives/netcdfgroup/2012/msg00279.html ) I turned to Rscript, and whacked out the q'n'd https://github.com/TomRoche/GEIA_to_netCDF/blob/master/netCDF.stats.to.stdout.r However it wasn't as quick as hoped, because I spent quite a bit of time figuring out how to pass the arguments.

i want to plot values with frequency on a logarithmic x axis. similar to this example that i found in the web: http://www.usspeaker.com/jensen%20p15n-graph.gif I would like to convert long numbers to si prefix notation like in the example (200000 to 200k, 35000000 to 3.5 M) Of course i could create labels by hand, but i have many files so i need some automatic function. Has anyone done that

Hello, I'm attempting to read information from an XML into a data frame in R using the "XML" package. I am unable to get the data into a data frame as I would like. I have some sample code below. *XML Code:* Header... Data I want in a data frame: <data> <row BRAND="GMC" NUM="1" YEAR="1999" VALUE="10000" /> <row

I'd like to save some calculation outputs as a pdf, to incorporate with others in a document. I've tried pdf("filename") name_of_object_to_output dev.off() but it doesn't seem to work, appears that this pdf function is for graphics? Is there a way to output numerical objects to pdf? Thanks J Dr. Jim Maas University of East Anglia

I'm trying to work out the simplest way to remove the upper and lower quantiles, in this case upper and lower 25% from an array. I can do it in two steps but when I try it in one, it fails. Is there something simple missing from my syntax or are there other simple elegant way to accomplish this? Thanks J > i <-1:20 > i2 <- i[i<quantile(i,.75)] > i3 <-

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

I'm attempting to sort a 3 dimensional array that looks like this > x , , 1 [,1] [,2] [1,] 9 9 [2,] 7 9 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2] [1,] 2 1 [2,] 3 2 Such that it ends up like this .... > y , , 1 [,1] [,2] [1,] 2 1 [2,] 3 2 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2]