similar to: identical values not so identical? newbie help please!

I am fairly new to log-linear modelling, so as opposed to trying to fit modells, I am still trying to figure out how it actually works - hence I am looking at the interpretation of parameters. Now it seems most people skip this part and go directly to measuring model fit, so I am finding very few references to actual parameters, and am of course clear on the fact that their choice is irelevant for

I'm trying to import a table into R the file is about 700MB. Here's my first try: > DD<-read.table("01uklicsam-20070301.dat",header=TRUE) Error: cannot allocate vector of size 15.6 Mb In addition: Warning messages: 1: In scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : Reached total allocation of 1535Mb: see help(memory.size) 2: In scan(file, what,

i appologise for the trivialness of this post - but i've been searching the forum wothout luck - probably simply because it's late and my brain is starting to go.. i have a frequency table as a matrix: orig<-matrix(c(40,5,30,25), c(2,2)) orig [,1] [,2] [1,] 40 30 [2,] 5 25 i basically need a random sample say 10 from 100: [,1] [,2] [1,] 5 2 [2,] 0 3 i

There must be a very basic thing I am not getting... I'm working with some entropy functions and the convention is to use log(0)=0. So I wrote a function: llog<-function(x){ if (x ==0) 0 else log(x) } which seems to work fine for individual numbers e.g. >llog(0/2) [1] 0 but if I try whole vectors or tables: p<-c(4,3,1,0) q<-c(2,2,2,2) llog(p/q) I get this: [1] 0.6931472

Hi! This is going to be a real newbie question, but I can't figure it out. I'm trying to plot densities of various functions of chi-square. A simple chi-square plot I can do with dchisq(). But e.g. chi.sq/degrees of freedom I only know how to do using density(rchisq()/df). For example: plot(1, type="n", xlab="", ylab="", xlim=c(0,2), ylim=c(0,7)) for (i

OK, this is really weird! here's an example code: t1<-c(1,2,3,4) t2<-c(4,2,4,2) plot(t1~t2, xlab="exp1", ylab="exp2") dev.copy2eps(file="test.eps") that all seems fine... until you look at the eps file created, where for some weird reason, if you scroll down to the end, the code reads: /Font1 findfont 12 s 0 setgray 214.02 18.72 (e) 0 ta -0.360 (xp1) tb

Hi everyone! This is a ridiculously simple problem, I just can't seem to find the solution! All I need is something equivalent to sum(is.na(x)) but instead of counting missing values, to count empty cells (with a value of 0). A naive attempt with is.empty didn't work :) Thanks! Maja Oh, and if the proposed solution would be to make all the empty cells into missing cells, that is

Hi! I have a dataset with three columns -the first two refer to x and y coordinates, the last one are odds ratios. I'd like to plot the data with x and y coordinates and the odds ratio shown as a fourfold plot, which I prefer to do using the stars function. Unfortunately the stars option in symbols is not as cool as the stars function on its own, and now i can't figure out how to do it!

I like Tante Maja. I will call them and see if we can flood them. ;-) I suggest dinner at 18:00? Best, Tobias On Sun, Mar 26, 2017, at 04:08 PM, Bekket McClane via llvm-dev wrote: > Hi, I’m one of the poster session authors, I’m also currently in > Saarbruken > All three places sound nice to me, but I’m not familiar with this town so > maybe you can pick the place? > About the

Hi everyone, I want to highlight something in a plot. So I want to write a text with a yellow background. I tried to make use of text(x,y,"hallo",bg="yellow") but that does not work. I know I am a handful. Sorry! Maja! --

Is there a way to automate fitting and assessing loglinear models for several nominal variables . . . something akin to step or drop1 or add1 for linear or logistic regression? Thanks. --Chris -- Christopher W. Ryan, MD SUNY Upstate Medical University Clinical Campus at Binghamton 40 Arch Street, Johnson City, NY 13790 cryanatbinghamtondotedu "If you want to build a ship, don't drum

Hello, I'm planning to start using R. Before getting into it, I'd like to ask a couple of questions. Does R carry out loglinear model analysis? That is, will it provide the chi-squared goodness of fit test statistic for a given hierarchical loglinear model? Maybe even do a model selection procedure (like Brown's two-step procedure, or forward/backward selection)? Thanks

I’m going to travel with another person, so 2 people in total Cheers, Hsu > Tobias Grosser <tobias.grosser at inf.ethz.ch> 於 2017年3月26日 下午4:16 寫道： > > We have a table reserved at Tante Maja, 18:00 for 15 people. I am travel > with 5 other people, so 10 more spots are open. Please let me know > within 30 minutes if you want a spot, such that I can confirm the >

Hi I want to set a variable to either 1 or 0 depending on an value of a dataframe and then add this as a colum to the dataframe. This could be done with a loop but as we are able to do questions on a complete row or colum without a loop it would be sweet if it could be done. for example: table: Name Age Joel 24 agust 17 maja 40 and so on... And what I want to do is a command that

Hi, I've heard some people are in Saarbrucken and would like to go for a dinner together. I've found some places that should be good for groups: Old Murphys https://goo.gl/maps/aPXjfwJGSgS2 Tante Maja https://goo.gl/maps/yF9Gij5qPoN2 Vapiano https://goo.gl/maps/knK9edHPE1y Is someone interested in meeting this evening (probably after 5:30)? Piotr -------------- next part

Hi all: Here's a question about result of loglinear analysis. There're 2 factors:area and nation.The raw data is in the attachment. I fit the saturated model of loglinear with the command: glm_sat<-glm(fre~area*nation, family=poisson, data=data_Analysis) After that,I extract the coefficients: result_sat<-summary(glm_sat) result_coe<-result_sat$coefficients I find that all the

On Sun, Mar 26, 2017, at 04:23 PM, Piotr Padlewski via llvm-dev wrote: > Hey Tobias, > 4 spots for me and my folks. Thanks for taking care Tobias! OK. We are down at 2 spots (maybe a little bit more) Piotr 4 spots Tobias 5 spots Bekket 2 spots Alex 2 spots 13 out of 15 spots taken. Let me know if you wanna join. I can try to get some more spots. Best, Tobias Best, Tobias

Hello everyone, I've a problem and dont know how to solve. This is my first posting and it would be fantastic if you could help me. I want to divide n objects in k classes and need an output with all (n+1)(n+2)/2 possibilities. For example n=4, k=3: That would be: 4 0 0 3 1 0 3 0 1 2 2 0 2 1 1 2 0 2 1 3 0 1 2 1 1 1 2 1 0 3 0 3 1 0 2 2 0 1 3

Dear netters, Sorry for cross-posting this question. I am sure R-Help is not a research methods discussion list, but we have many statisticians in the list and I would like to hear from them. Any function/package in R would be able to deal with the problem from this researcher? ---------- Forwarded message ---------- From: Heidi Bertels Date: Tue, Jun 5, 2012 at 4:31 PM Subject: How to best

Hello everybody, I've a question about "autoregressive Regressionmodels". Let Y[1],.....,Y[n], be a time series. Given the model: Y[t] = phi[1]*Y[t-1] + phi[2]*Y[t-1] + ... + phi[p]*Y[t-p] + x_t^T*beta + u_t, where x_t=(x[1t],x[2t],....x[mt]) and beta=(beta[1],...,beta[m]) and u_t~(0,1) I want to estimate the coefficients phi and beta. Are in R any functions or packages for