Displaying 20 results from an estimated 4000 matches similar to: "Selecting ranges of dates from a dataframe"
2010 Dec 05
1
[PATCH 4/5][REPOST][BTRFS-PROGS] Avoid to scan cdrom and floppy
Hi all,
the commands "btrfs filesystem show" and "btrfs device scan" look at the /dev
directory (and it subdirectories) for every block devices.
This is a slow process because floppy and cdrom are also checked. Moreover,
as highlighted by Helmut, if udev is not used, the /dev directory is populated
by high number of non-existant devices, which slow the process.
My patch
2010 Jul 06
1
information reduction-database management question
If you redefine your NAs as below to be detected as some arbitrary large
number, then the code should work through. Any 5's left in your dataset can
be replaced just as easily by NAs again. Not elegant, but effective.
site <- c("s1", "s1", "s1", "s2","s2", "s2")
pref <- c(1, 2, 3, 1, 2, 3)
R1 <- c(NA, NA, 1, NA,NA,NA)
R2
2014 Dec 12
2
Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26.
Anna Crepes: Traubenzucker
+ Feldsalat spezielles Dressing (bringt selbst mit?)
-------- Weitergeleitete Nachricht --------
Betreff: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: Fwd: 26.
Datum: Thu, 11 Dec 2014 15:34:39 +0100
Von: Markus <universe at truemetal.org>
An: universe at truemetal.org
Geschenke Moritz: dunkle Schokolade.
Geschenke Anna: normale Schokolade.
-------- Weitergeleitete
2008 Jul 15
1
code reduction (if anyone feels like it)
# I am sure that I could be more efficient than this but how? Thanks in
advance.
#GPS in Decimal Degrees in the form longitude latitude
RM215 <- matrix(c(-82.1461363, 33.5959109), nrow=1)
SC <- matrix(c(-82.025888, 33.606454), nrow=1)
RM202 <- matrix(c(-81.9906723, 33.5027653), nrow=1)
RM198 <- matrix(c(-81.926823, 33.4634678), nrow=1)
HC <- matrix(c(-81.920505, 33.46192), nrow=1)
2012 Aug 07
2
What is this called? lapply(datum,"[[","ColumnName")
Hello R users
I recently learned how to use this command:
lapply(datum,"[[","ColumnName")
Unfortunately, I don't know how exactly it works, what it's called (in
particular the "[[" part], and what other things you can do with it
(retrieve multiple columns?).
Given datum is a list of dataframes with the same column, but different
number of rows,
2011 Nov 30
2
nls help
Hello,
I have data like the following:
datum <- structure(list(Y = c(415.5, 3847.83333325, 1942.833333325,
1215.22222233333,
950.142857325, 2399.5833335, 804.75, 579.5, 841.708333325, 494.053571425
), X = c(1.081818182, 0.492727273, 0.756363636, 0.896363636,
1.518181818, 0.499166667, 1.354545455, 1.61, 1.706363636, 1.063636364
)), .Names = c("Y", "X"), row.names = c(NA,
2005 Aug 02
3
how to print a data.frame without row.names
Dear All,
is there a simple way to print a data.frame without its row.names?
example:
datum <- as.Date(c("2004-01-01", "2004-01-06", "2004-04-12"))
content <- c('Neujahr', 'Hl 3 K.', 'Ostern')
df1 <- data.frame(datum, content)
print(df1)
datum content
1 2004-01-01 Neujahr
2 2004-01-06 Hl 3 K.
3 2004-04-12 Ostern
Can I get
2007 Dec 12
1
how to shorten elements in a data frame?
I have a data frame ("res$data" in the example below), and I'd like to walk
through it, doing an approx() to interpolate each element in turn based on
the value of the item named "pressure" that is in the data.frame.
I've put some code below. I had hoped that the commented-out "length() <-"
line would let me adjust the lengths of the items, but that has
2012 Oct 18
1
spTransform longlat to utm
Dear all,
I am trying to project my LongLat-maps to a plane.
The ultimate purpose is to do a search of points in vicinity of other points using overlay-commands (sp) with radius in km.
I am applying spTransform (package rgdal) and it gives my some curious results.
An example.
Let's take a point lying somewhere in Germany, zone=32U
x <- 8.968735
y <- 49.454735
After conversion I
2008 Dec 20
2
NA, where no NA should (could!) be!
Hello,
again I'm on my weblog-script... having problems...
This code:
===========================
weblog <- read_weblog("web.log")
weblog_by_date <- split(weblog, weblog$date)
#for ( i in names(weblog_by_day) ) { print(i); print(weblog_by_day$i) }
for ( datum in names(weblog_by_date) )
{
print(datum)
selected <- weblog_by_date[[datum]]
res_size_by_host <-
2004 Nov 03
3
cut POSIX results in NA - bug?
Dear all
I try to make hourly average by cut() function, which almost works
as *I* expected. What puzled me is that if there is only one item at
the end of your data it results in NA.
Example will explain what I mean
datum<-seq(ISOdate(2004,8,31), ISOdate(2004,9,1), "min")
cut(datum[1370:1381],"hour", labels=F)
[1] 1 1 1 1 1 1 1 1 1 1 1 NA
2009 Sep 25
2
synchronisation of time series data using interpolation
Readers,
I have data with different time stamps that I wish to plot (for example):
data set 1
time(hh:mm:ss),datum
01:00:00,500
01:00:15,600
01:00:30,750
01:00:45,720
01:01:00,700
01:01:15,725
01:01:30,640
01:01:45,710
data set 2
time,datum
01:00:12,20
01:01:01,55
01:01:55,22
The time interval in data set 1 does not change, but the time interval
in data set 2 does change, such that for a
2020 Oct 20
1
sp:gIntersection warning message about projection
Hi,
I am using in my workflow gIntersection from sp package. Part of my
relevant sessionInfo is:
R version 4.0.3 (2020-10-10)
Platform: x86_64-w64-mingw32/x64 (64-bit)
Running under: Windows 10 x64 (build 17763)
attached base packages:
[1] stats graphics grDevices utils datasets methods base
other attached packages:
[1] CircStats_0.2-6 boot_1.3-25 MASS_7.3-53 stringr_1.4.0
2008 Nov 27
2
Troubles with the format of dates
Dear useRs,
I'm struggling again with date-related stuff: I am using R to draw water levels at certain measuring
stations. My data comes as a tab-delimited text file and looks like this:
DATUM P1 P2
...
2006-11-16 425.21 423.99
2006-12-15 425.12 423.97
2007-01-16 425.16 424.06
...
(measurements started in July 2004 and still continue on a monthly or bi-weekly basis)
This
2012 May 23
3
barplot
Hey,
I am trying to create barplot of abundances over time (in days). The period
is over 171 days, so I don't want to have all labels there but only the
first day of the month. I couldn't find anything like this on the forum yet.
Mostrly it's about year to year data.
This is the relevant part of my table:
datum month abundance
26/03/11 March 1
27/03/11 March 0
28/03/11 March 1
2017 Jun 05
2
[newbie] trouble with global variables and CreateLoad/Store in JIT
Since the getelementptrs were implicitly generated by the CreateStore/Load
I'm not sure how to get access to them.
So I hacked the assignment to be done thrice: once using a manual
decomposition into two GEPs and stores, once using the "big" CreateStore,
once via the setGlobal function, printing addresses and memory contents at
each point to the degree that I have access to them.
2007 Jul 16
3
Errors in data frames from read.table
Hello, all.
I am working on a project with a large (~350Mb, about 5800 rows) insurance claims dataset. It was supplied in a tilde(~)-delimited format. I imported it into a data frame in R by setting memory.limit to maximum (4Gb) for my computer and using read.table.
The resulting data frame had 10 bad rows. The errors appear due to read.table missing delimiter characters, with multiple data
2009 Feb 26
8
beginners question
hi group,
I am making a little rails app to experiment with rails. It consists
of one model, item, that represents an item on a todo list.
A todo item has a description, a state (finished or not) and a due
date.
After changing the scaffold screens a bit, I wanted to be able to
have no due date. I tried to do this by making a radio button; if ''no
date'' is selected, the date
2011 Jul 06
1
accessing names of lists in a list
After importing multiple files to data.frames in R, I want to rename all
their columns and do other operations with them. The data.frame names are
not continuous like 1, 3, 4, 6.
I could not find a way of creating a list of the data.frames and loop this
and ended up putting them into a list first:
# get all objects
all.obj = sapply(ls(), get)
# get data frames
dfrs = all.obj[sapply(all.obj,
2005 Oct 13
3
aggregate slow with many rows - alternative?
Hi,
I use the code below to aggregate / cnt my test data. It works fine,
but the problem is with my real data (33'000 rows) where the function
is really slow (nothing happened in half an hour).
Does anybody know of other functions that I could use?
Thanks,
Hans-Peter
--------------
dat <- data.frame( Datum = c( 32586, 32587, 32587, 32625, 32656,
32656, 32656, 32672, 32672, 32699 ),