similar to: using lapply

I am using getSymbols function from quantmod package to get price data from internet. Currently I have: my.ticker <- "IBM" getSymbols(my.ticker,src="google") This creates an xts object named my.ticker which contains historical price data for IBM. How can I call and manipulating this xts object using my original string my.ticker? I want to do: colnames(my.ticker) <-

Hi All Is there who knows to define multi line comment? ( in Java we can define by /* and */ ) Best Regards Kushan Jayathilake --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk-/JYPxA39Uh5TLH3MbocFFw@public.gmane.org To

OS X R 4.3.3 Colleagues I have created objects using the Surv function in the survival package: > FIT.1 Call: survfit(formula = FORMULA1) n events median 0.95LCL 0.95UCL SUBDATA$ARM=1, SUBDATA[, EXP.STRAT]=0 18 13 345 156 NA SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=1 13 5 NA 186 NA SUBDATA$ARM=2, SUBDATA[, EXP.STRAT]=2 5

Hi Dennis, look at the help page for summary.survfit, the Value n.event. G?ran On 2024-05-15 22:41, Dennis Fisher wrote: > OS X > R 4.3.3 > > Colleagues > > I have created objects using the Surv function in the survival package: >> FIT.1 > Call: survfit(formula = FORMULA1) > > n events median 0.95LCL 0.95UCL >

Terry - your example didn't demonstrate the problem because the variable that interacted with strata (zed) was not a factor variable. But I had stated the problem incorrectly. It's not that there are too many strata terms; there are too many non-strata terms when the variable interacting with the stratification factor is a factor variable. Here is a simple example, where I have

Terry - your example didn't demonstrate the problem because the variable that interacted with strata (zed) was not a factor variable. But I had stated the problem incorrectly. It's not that there are too many strata terms; there are too many non-strata terms when the variable interacting with the stratification factor is a factor variable. Here is a simple example, where I have

Dear R contributors, I have a problem in selecting in an efficient way, rows of a data frame according to a condition, which is a part of a row name of the table. The data frame is made of 64 rows and 2 columns, but the row names are very long but I need to select them according to a small part of it and perform calculations on the subsets. This is the example: X Y "Unique to

Terry Therneau has been very helpful on r-help but we can't figure out what change in R in the past months made extra columns appear in model.matrix when the terms object is subsetted to remove stratification factors in a Cox model. Terry has changed his logic in the survival package to avoid this issue but he requires generating a larger design matrix then dropping columns. A simple

(Re-)read the discussion of indexing (both `[` and `[[`) and be sure to get clear on the difference between matrices and data frames in the Introduction to R document that comes with R. There are many ways to create numeric vectors, character vectors, and logical vectors that can then be used as indexes, including the straightforward way: df[ c( "Unique to strat ", "Unique

Hi All, I am looking for help in rotating species titles produced using the strat.plot( ) function in the rioja package. This function produces a stratigraphic plot of paleoenvironmental data. Currently the titles of each species are plotted vertically while they are typically plotted at a 45 degree angle in other programs. Does anyone have any idea of how to rotates these titles? Below is an

Dear Helpers   I have a sample frame and i have sampled from it using three methods and now i want to calculate the statistics but i only get the population parameters.   H <- matrix(rnorm(100, mean=50000, sd=5000)) sampleframe=data.frame(type=c(rep("H",100)),value=c(H)) sampleframe   str=strata(sampleframe,c("type"),size=c(20,), method="srswor")

Thanks a lot, so simple so efficient! I will study more the grep command I did not know. Thanks! Francesca Pancotto > Il giorno 19 ott 2017, alle ore 12:12, Enrico Schumann <es at enricoschumann.net> ha scritto: > > df[grep("strat", row.names(df)), ] [[alternative HTML version deleted]]

Quoting Francesca PANCOTTO <f.pancotto at unimore.it>: > Dear R contributors, > > I have a problem in selecting in an efficient way, rows of a data > frame according to a condition, > which is a part of a row name of the table. > > The data frame is made of 64 rows and 2 columns, but the row names > are very long but I need to select them according to a small

Samba shares work for windows 7 and Server 2008, but XP and Server 2000 recieve the following error when trying to map samba shares: "The trust relationship between this workstation and the primary domain failed." tail -f /var/log/messages Apr 10 07:38:03 samba01 smbd[23581]:?? connect_to_domain_password_server: unable to open the domain client session to machine ad1.strat.com. Error

Yo no conozco ningún paquete para hacer esto aunque probablemente exista. De todas maneras las cuentas de este tipo de calculos no suelen ser complicadas. Personalmente le recomendaría pasarse por una biblioteca y adquirir el siguiente libro donde explica con todo lujo de detalles, en castellano y simpliciddad como hacer estos calculos

Dear R users, I tried to fit a cox proportional hazard model to get estimation of stratified survival probability. my R code is as follows: cph(Surv(time.sur, status.sur)~ strat(colon[,13])+colon[,18] +colon[,20]+colon[,9], surv=TRUE) Error in if (!length(fname) || !any(fname == zname)) { : missing value where TRUE/FALSE needed Here colon[,13] is the one that I want to stratify and the

While sm4.6ll<-fit.mult.impute(Surv(agesi, si)~partner+ in.love+ pubty+ FPA+ strat(gender),fitter = cph, xtrans = dated.sexrisk2.i, data = dated.sexrisk2, x=T,y=T,surv=T, time.inc=16) runs perfectly using Hmisc, Design and mice under R11 run via Sciviews-K, with library(Design) library(mice) ds2d<-datadist(dated.sexrisk2) options(datadist="ds2d")

Hallo, I modified a code given by Andrija, a contributor in the list  to achieve two objectives: create 1000 samples from a list of 207 samples with each of the samples cointaining 20 good and 20 bad. THis i have achievedcalcuate AUC each of the 1000 samples, this i get an error. Please see the code below and assist me. > data<-data.frame(id=1:(165+42),main_samp$SCORE,

I have a plot created with strat.plot() from package rioja. When the plot is created with scale.percent=FALSE, each x axes is labeled at 0 and its maximum. However, when scale.percent=TRUE, the x axes are not labeled. I need to use scale.percent=TRUE and I need labels for the x axes. I have been able to add labels to the x axes with mtext but it is very tedious to find the correct

i am working on the project to analyze hedge fund performance, i would appreciate that if you guys could spare some time helping me out with the R code. Thanks. The senario is: i applied BOXPLOT() to plot the performance of all hedge funds with 7 strategies. And right now in this boxplot I need to plot the points of 30 individual hedge funds from my portfolio. And I applied POINTS() and