Displaying 20 results from an estimated 1100 matches similar to: "Theil Kendall line as fit?"
2011 Nov 16
1
Theil decomposition
I came across the package 'ineq' that computes a variety of inequality measures (e.g. gini, theil etc). I want to compute the Theil index (racial segregation) and decompose the total into sub-components (by geog levels). I think the package doesn't report the decomposition (correct me if I'm wrong). Just wonder is that available elsewhere?
K.
2009 Jul 16
1
Theil test help
Hello,
I have a series of questions that I hope will be simple to answer. Basically I would like a code to do the following so that I can compute the distribution free test for the slope of a postulated regression line (Theil test). As I am testing the null hypothesis that slope = 0 against the general alternative the slope does not equal 0, it should be pretty straight-forward.
I have a data
2012 Oct 21
2
help speeding up simple Theil regression function
Hello,
I am working on a simple non-parametric (Theil) regression function and and
am following Hollander and Wolfe 1999 text. I would like some help making
my function faster. I have compared with pre-packaged version from "MBLM",
which isnt very fast either, but it appears mine is faster with N = 1000
(see results below). I plan on running this function repeatedly, and I
generally
2007 Jan 12
2
Magnitude of trend in time series
Hello,
I am analyzing some climate time series data using the Mann Kendall package
and was wondering if there was a way to calculate the trend using Sen's
nonparametric estimator slope in R?
Thank you in advance,
Barry
_________________________
Barry Baker, Ph.D.
Global Climate Change Initiative
The Nature Conservancy
2424 Spruce St., Suite 100
Boulder, CO 80302
Tel: (303)-541-0322
Fax:
2008 Nov 21
1
Bug in Kendall for n<4?
> library(Kendall)
> Kendall(1:3,1:3)
WARNING: Error exit, tauk2. IFAULT = 12 <<<<<<
tau = 1, 2-sided pvalue =1
I believe Kendall tau is well-defined for this case and the reported
value is correct; isn't it a bug to give a warning? (And if, e.g.,
the pvalue is not well-defined in this case, wouldn't it be better to
return NA or NaN or something?) Also,
2009 Oct 20
1
kendall.global
Hi every body:
I need some help with kendall.global. The example in the manual seems not working well, and cannot used with my data, always the same error.
data(mite)
> mite.hel <- decostand(mite, "hel")
>
> # Reproduce the results shown in Table 2 of Legendre (2005), a single group
> mite.small <- mite.hel[c(4,9,14,22,31,34,45,53,61,69),c(13:15,23)]
>
2011 Sep 02
1
Mann Kendall Test for Trend
Hi there,
I'm trying to apply the Mann Kendall test for trend analysis of a time
series. I have downloaded and installed the package Kendall and
subsequently loaded it into the software.
My time series is a .txt file with 2 columns - column 1 is the year (1985 -
2009) and column 2 is the corresponding entry variable.
According to the R guidelines, the call should be:
MannKendall(x)
2004 May 13
1
Bootstrapping kendall cor
Dear R-helpers,
I'm fighting with the following problem :
I want to do bootstrapping on a Kendall correlation with the following code
:
> cor.function <- function(data,i) cor(data[i, 1], data[i,
2],method="kendall")
> boot.ci <- boot.ci(boot.cor <- boot(cbind(x,y),cor.function,
R=1000),conf=c(0.95,0.99))
However, I've got problems because I've got ties
2005 Aug 13
1
R/S-Plus/SAS yield different results for Kendall-tau and Spearman nonparametric regression
Colleagues,
I ran some nonparametric regressions in R (run in RedHat Linux), then
a colleague repeated the analyses in SAS. When we obtained different
results, I tested S-Plus (same Linux box). And, got yet different
results. I replicated the results with a small dataset:
DATA:
37.5
23
37.5
13
25
16
25
12
100
15
12.5
19
50
20
100
13
100
10
100
10
100
16
50
10
87.5
2007 Sep 06
3
kendall test
Hello,
I thougth that there is a function which does the kendall test in R,
I writed on the console apropos("kendall") and I didn't found anything can you tell me how could I do to use the kendall test?
Thanks.
_____________________________________________________________________________
l
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2005 Aug 18
2
kendall tau correlation test for ties: Potential error (PR#8076)
Full_Name: Dirk Koschuetzki
Version: 2.1.1
OS: source code
Submission from: (NULL) (194.94.136.34)
Hello,
>From the source code (R-2.1.1, file: .../R-2.1.1/src/library/stats/R/)
******************************
cor.test.default <-
function(x, y, alternative = c("two.sided", "less", "greater"),
method = c("pearson", "kendall",
2012 Aug 20
1
Kendall package tau-a, b, and c
Hi all,
I would like to ask a question related to Kendall package. I ran Kendall
(x,y) and
saw the results. But I am not sure which tau values R reported. I have
ties in
my data set, so I want tau-b. Can anybody tell how Kendall package is
calculating tau values? I have looked at the package PDF, but I could
not find
any useful information. As long as I see from the following
link, there
2011 Mar 21
1
Kendall v MannKendall Functions
Hi,
I am running a correlation analysis on a temporal dataset. I was wondering
if you would receive the same tau and p values running the function:
MannKendall(x), where x is the dependant variable that changes with time
as you would running:
Kendall(d,x), where x is the exact same dataset as the x entered into
MannKendall and d is the date on which the observation was made (assuming
that
2009 May 13
0
Mann-Kendall test
Dear useRs,
I've been trying to run a Mann-Kendall test in my data in order to detect trends.
I studied the examples given at the Kendall package and I can understand pretty well how it works on time-series data.
However, my data consists of values in different sites per year, as I display below;
Year 1 | Year 2 | Year 3 | ...
Site 1 x x x ...
2012 Apr 17
2
Installing Kendall Package
I know this is a dumb question but I'm pulling out what little hair I have
left. I download the package and got the following:
trying URL '
http://ftp.ussg.iu.edu/CRAN/bin/windows/contrib/2.14/Kendall_2.2.zip'
Content type 'application/zip' length 52732 bytes (51 Kb)
opened URL
downloaded 51 Kb
package ‘Kendall’ successfully unpacked and MD5 sums checked
The downloaded
2023 Dec 01
2
Mann Kendall mutation package?
Hello - does anyone know whether there are any packages for Mann-Kendall
mutation tests in R available? The only one I could find online is this
MK_mut_test: Mann-Kendall mutation test in Sibada/sibadaR: Sibada's
accumulated R scripts for next probably use to avoid reinventing the wheel.
(rdrr.io) <https://rdrr.io/github/Sibada/sibadaR/man/MK_mut_test.html> but
there doesn't seem to
2008 May 05
0
kendall tau a,b,c
hi,
i have 2 lists of ranks for which i'd like to compute kendall tau.
there are ties in the ranks which (to the best of my knowledge) means i
cant use tau a but rather b or c.
how does R handle that? are ties automatically detected (using
corr.test()) and is tau b/c computed instead of tau a?
also kendall does not work when values in list 1 do not occur in list 2
(and vice versa) - how does
2008 Feb 13
4
FreeBSD: Changing UNIX password - Password Chat?
I can't get my Samba PDC (FreeBSD 7,0-BETA3) changing UNIX passwords
from Windows clients (Ctrl-Alt-Del).
I now have the password chat debug active and I have loglevel 100.
I am not certain about the syntax in the password chat. But if I from
a console try to change the password of a given user (here testuser1),
I see these lines:
mflserver3# /usr/bin/passwd testuser1
Changing local password
2004 Mar 03
1
cor(..., method="spearman") or cor(..., method="kendall") (PR#6641)
Dear R maintainers,
R is great. Now that I have that out of the way, I believe I have
encountered a bug, or at least an inconsistency, in how Spearman and
Kendall rank correlations are handled. Specifically, cor() and
cor.test() do not produce the same answer when the data contain NAs.
cor() treats the NAs as data, while cor.test() eliminates them. The
option
use="complete.obs" has
2013 Feb 28
1
PCA with spearman and kendall correlations
Hello,
I would like to do a PCA with dudi.pca or PCA, but also with the use of Spearman or Kendall correlations
Is it possible ?
Otherwise, how can I do, according to you ?
Thanking you in advance
Eric Bourgade
RTE
France
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