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What is plot.new? and how can i get it to work so i can load other data? > library(splancs) > area = 6*4 > lambda = 1.5 > N = rpois(1,lambda*area) > u = runif(N,-2,4) > v = runif(N,0,4) > plot(u,v,asp=1) > h = chull(u,v) > h = c(h,h[1]) > plot(u[h],v[h],"1",asp=1) Error in plot.xy(xy, type, ...) : invalid plot type '1' >

Dear all, I want my PhD thesis which I hand in tomorrow to look even nicer: Does polymap in the splancs library not allow horizontal plotting of y-labels? I have tried polymap(studyarea, xlab = "x (m)", ylab = "y (m)", las = 1) but it doesn't change the labels? Mayby some function in library(spatstat) support las? Thanks! Sincerely, Tord

Dear All, Please see the short script at the end of the email, which I assembled looking for bits and pieces on the web. It essentially does what I need: it plots several countries as a color-coded map. I just would like to fine-tune a bit the final image, in particular (1) Select my own colors for "painting" the countries (i.e. associate manually a color to every level) (2) Be

Dear All, Please consider the snippet at the end of the email. I often download some maps (in the R format) from http://www.gadm.org/ However, when I run (typically more than once) a variation of the script below (based on http://bit.ly/1b3W0Aa ), I often get Error in load(url(paste("http://gadm.org/data/rda/", fileName, "_adm", : cannot open the connection In

The R-1.2.1 builds have gone fairly smoothly on most of my UNIX architectures, but there were many warnings reported by the picky SGI compiler that could be eliminated in future releases. Generally, I have found the SGI compilers very helpful in ferreting out portability problems, unused and/or obsolete variables, unexpected datatype coercions, etc., and they compile faster than any other

Hi, I would need some help with the splans package in R. I am using a Shapefile (downloadable at) http://rapidshare.com/files/215206891/Redlands_Crime.zip and the following execution code setwd("C:\\Documents and Settings\\Dejan\\Desktop\\GIS\\assignment6\\DataSet_Redlands_Crime\\Redlands_Crime") library(foreign) library(splancs) auto_xy<-read.dbf("Auto_theft_98.dbf")

I am intersted in time-space clustering of local industry. I made the point file, polygons and time table then run 'stkhat' function in Splancs, but it generates only time k function. I noticed that it has only one ks value. ... Can anybody help me?. thanks in advance. countiespt <- read.table('d:/dissertation/dailynew/jun10/countiespt_ok.txt', sep=",")

Patches item #14375, was opened at 2007-10-02 13:12 You can respond by visiting: http://rubyforge.org/tracker/?func=detail&atid=220&aid=14375&group_id=35 Category: None Group: None Status: Open Resolution: None Priority: 3 Submitted By: Christopher Bludau (count_cb) Assigned to: Nobody (None) Summary: bigdemo/wxScrolledWindow - paint bug with scrolled window Initial Comment: I found

Hi all, I get two different results when using sum() and the switch na.rm. The result is correct when na.rm=FALSE. Linux Redhat 7.3, R version 1.6.1. I've had no luck searching the mail archives, so I was hoping somebody could explain/check this one for me. I will need to apply the function to missing data, simple as it is. Code: x<-matrix(runif(20,0,5)%/%1,4,5) # random matrix

Hi All, After a lengthy battle just to get the package installed, I am not able to actually use Rgraphviz to generate any plots. I tried just using the sample code in the documentation (http://www2.warwick.ac.uk/fac/sci/moac/people/students/peter_cock/r/rgraphviz/) and I get the following: *> > library(Rgraphviz) > test.matrix<-matrix(rep(c(0,1,0,0), 9), ncol=6, nrow=6) >

Hello, I am using the following code to create ppp files from csv data and map shape files, but I am getting some errors which I have been unable to fix by searching them online: library(spatstat) library(maps) library(maptools) NYC2<-readShapePoly("nybb.shp") # this is a map of the NYC boroughs without waterways and no census tract divisions (but it does include lines separating

DeaR comRades: I have a 2D spatial binomial process as shown in the data and code below. I am plotting the number of trials and the number of successes in the spatial binomial experiments and would like to draw the spatial cells were the trials and successes were counted, i.e. a partial grid in the plot only for those cells where there is a number. The cells are 2x2 km cells. The count of Trials

Hi, I noticed the following problem with xy.coords() in R 2.2.1-patched (version info at the foot of this email) and R 2.3.0 unstable (subversion no: r37123): > xy.coords(x = matrix(1:20, ncol = 2)) Error in xy.coords(x = matrix(1:20, ncol = 2)) : argument "y" is missing, with no default > xy.coords(x = matrix(1:20, ncol = 2), y = NULL) $x [1] 1 2 3 4 5 6 7 8 9

Dear, I am trying to visualise a time-progressing line (it's supposed to represent spread patterns) using brew package and Google Earth. The idea is to have a function which takes start and end point geographic coordinates, as well as number of intervals to chop the path up, and returns the collection of points segmenting this line. Unfortunately my calculations fail for large distances,

SUMMARY: Specific problem: I'm regridding biomass-burning emissions from a global/unprojected inventory to a regional projection (LCC over North America). I need to have boundaries for Canada, Mexico, and US (including US states), but also Caribbean and Atlantic nations (notably the Bahamas). I would also like to add Canadian provinces and Mexican states. How to put these together? General

Dear all,   I have the following written example > coords <- "51°30'48.58\"N" > > as.integer(strsplit(coords, "°")[[1]][1]) [1] 51 > as.integer(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][1]) [1] 30 > as.numeric(strsplit(strsplit(strsplit(coords, "°")[[1]][2], "'")[[1]][2],

Hello! My code below creates a data frame and a plot for it. However, I can't figure out how to add a legend that is not ON the plot itself, but outside of it (e.g., to the right of my graph or below it). I tried something: I put a line par(xpd=T, mar=par()$mar+c(0,0,0,4)) right before my plot command), but that screwed up all my gridlines - they covered all graph and do not coincide with

Hello, everybody! I have a code below that creates a data set and then a stacked bar chart based on that data set. No need to look at it - just notice please that my horizontal axis is a date varible (x=my.data$date). I have a question about the last 2 lines of this code: grid(nx=NULL,ny=NULL,col = "lightgray", lty = "dotted",lwd = par("lwd")) axis(1, las = 2) Could

Hello! The code below works - if you run it you'll see a stacked area chart generated based on the data example. I only have one understanding question about the legend location (the very last snippet of code): legend(par()$usr[2], mean(par()$usr[3:4]), rev(order.of.vars), xpd=T, bty="n", pch=15, col=all.colors[rev(order.of.colors)]) I see that par()$usr[2] = 14763.72

Hi, I have a problem that concerns combination of the package Maptools and Splancs I have 2 shapefiles that i want to manipulate (one of type point and one polygon).I import them in R using Maptools but then i can't estimate a quartic Kernel using Splancs. The package doesn't recognize the shapes (invalid points and poly argument).I don't know if this is an easy task but i have