similar to: Populate a list / recursively set list values to NA

HI all, I'm new to R. Say I have a multi-layered list called newlist. ############ > str(newlist) List of 2 $ :List of 5 ..$ : num [1:8088] NA 464 482 535 557 ... ..$ : num [1:8088, 1:2] NA 464 482 535 557 ... ..$ : num [1:8088, 1:3] NA 464 482 535 557 ... ..$ : num [1:8088, 1:4] NA 464 482 535 557 ... ..$ : num [1:8088, 1:5] NA 464 482 535 557 ... $ :List of 3 ..$ : num

Hello! # I have a list with several data frames: mylist<-list(data.frame(a=1:2,b=2:3), data.frame(a=3:4,b=5:6),data.frame(a=7:8,b=9:10)) (mylist) # I want to grab only one specific column from each list element neededcolumns<-c(1,2,0) # number of the column I need from each element of the list # Below, I am doing it using a loop: newlist<-NULL for(i in 1:length(mylist) ) {

I have a list containing 48 objects (each with 30 rows and 4 columns, all numeric), and wish to produce 4 boxplot series (with 48 plots in each) , one for each column of each object. Basically I want a boxplot from boxplot(mylist[[]][,i]) for i in 1:4. It seems that I can create a boxplot of length 48 from the entire list, but I don't seem able to subscript to return 4 boxplots from the list

like this, the list is below, I want to remove the last one . not using newlist[-2], but using the function detect its component is numeric(0) and then remove it from the list. newlist [[1]] [1] 2 3 [[2]] [1] numeric(0) [[3]] [1] 7 [[alternative HTML version deleted]]

Hello, thank you all for your patience and time I am essentially trying to get disorganised data into long form for linear modelling. I have 2 dataframes "rec" and "book" Each row in "book" needs to be pasted onto the end of several of the rows of "rec" according to two variables in the row:" MRN" and "COURSE" which match. I have

Hi, I have a question about applying a function recursively through a list. Suppose I have a list where the different elements have different levels of recursion: > test.list<-list("I"=list("A"=c("a", "b", "c"), "B"=c("d", "e", "f"), "C"=c("g", "h", "i")), +

Hi all, I have the following code: set.seed(1) x1 <- matrix(sample(1:12), ncol=3) x2 <- matrix(sample(1:12), ncol=3) x3 <- matrix(sample(1:12), ncol=3) X <- list(x1,x2,x3) tt <- matrix(round(runif(5*4),2), ncol=4) Is there a way I can construct a new list where newlist[[i]] = tt[i,] %*% X[[i]] without using a for loop? Each element of newlist will be 3 x 1 vector. Thanks -- Tina

R-helpers: I'm trying to build a package, but I'm a bit new to the whole S3/S4 methods concept. I'm trying to add a new definition of the zoo function "as.yearmon", but I'm getting the following error when it gets to this point during a package install: *** R CMD INSTALL STARStools * installing to library

Hello Everyone,   This is my first attempt to do something in R. As a precursor to a Willingness to Pay analysis, I want to conduct a Mixed Conditional Logit analysis but am unsure how to proceed because of some nesting within my data.   Below is some data and code that illustrate what I’m trying to do. The data are based on responses to a conjoint survey obtained during pilot testing. In the

Hello, I'm trying to get postfix and mailman going on CentOS 5.4. I had this working previously, six to eight months ago, and shut it down since the need for use was no longer there. I've now reactivated mailman and set up a list. The software versions I'm using are httpd 2.2.14, postfix 2.3.3, and mailman 2.1.9. All the services are started, the list is created, and email is sent to

This is a minor release of Shorewall. WARNING: This release introduces incompatibilities with prior releases. See http://www.shorewall.net/upgrade_issues.htm. Changes are: a) There is now a new NONE policy specifiable in /etc/shorewall/policy. This policy will cause Shorewall to assume that there will never be any traffic between the source and destination zones. b) Shorewall no longer

hello , i''m currently trying to set-up Traffic Shapping with Shorewall and I have strong feelings that I found a bug. I may be mistaken, but I tried everything and can''t get it to work. I''ve turned ON TC_ENABLED=Yes and CLEAR_TC=Yes when i start shorewall ( shorewall start ), i get this message : Setting up Traffic Control Rules... TC Rule "2 eth1 0.0.0.0/0 tcp

Hi all .., I have a list of 7000 dataframes with similar column headers and I wanted to add a new column to each dataframe based on a certain condition which is the same for all dataframes. When I extract one dataframe and apply my code it works very well as follows :- First suppose this is my first dataframe in the list > OneDF <- Mylist[[1]] > OneDF ID Pdate

my list al is as below: mylist=list(c(2,3),5,7) > mylist [[1]] [1] 2 3 [[2]] [1] 5 [[3]] [1] 7 How could I get the following FOUR lists: First one [[1]] [1] 3 [[2]] [1] 5 [[3]] [1] 7 Second one [[1]] [1] 2 [[2]] [1] 5 [[3]] [1] 7 Third One [[1]] [1] 2 3 [[2]] [1] 7 Last one [[1]] [1] 2 3 [[2]] [1] 5 Do I have to use 'for' loops? Please give me sone suggestions! Thank you

1. I have a list of lm (linear model) objects. Is it possible to select, through subscripts, a particular element (say, the intercept) from all the models? I've tried something like this: List[[1:length(list)]][1] All members of the list are similar. My goal is to have a list of the intercepts and lists of other estimated parameters. Is it better to convert to a matrix? How to do this? 2.

I am getting the following message when Shorewall stops can anybody shed any light on this message and where I should be looking? Thanks root@bobshost:~# shorewall stop Loading /usr/share/shorewall/functions... Processing /etc/shorewall/params ... Processing /etc/shorewall/shorewall.conf... Loading Modules... Stopping Shorewall...Processing /etc/shorewall/stop ... IP Forwarding Enabled

I would like to use grep and gsub to manipulate a vector to make the names used consistent, i.e. reduce a level or two. However, here is what I found when I attempted to use grep and gsub: > tmp_test<-c("House 1 Plot Plus +100","House 2 Plot Plus +100","House 3 Plot Plus -100","House 4 Plot Plus -100","House 1 Plus +100","House 2

I am trying to continuously evaluate online created data files using R-algorithms. Is there any simple way to let R iteratively check for new files in a given directory, load them and process them? Any help would be highly appreciated. Best, A. [[alternative HTML version deleted]]

Dear R-users, How can I detect a NULL in a recursive list? For a regular list I could use lapply: > lapply(list(x=NULL), is.null) $x [1] TRUE However that doesn't work for structures like list(list(x=NULL)). I tried rapply but it treats NULL as a list and discards them: > rapply(list(a=1, b=list(x=NULL)), is.null) a FALSE Any suggestion? Thank you for your help, Vadim Note:

for a simple example: x <- list() x[["a"]] <- list(a=c(1,2,3),b=c(3,4,5)) x[["b"]] <- list(a=c(6,7,8),b=c(9,10,11)) lapply(x,sum) this fails w/ Error in FUN(X[[1L]], ...) : invalid 'type' (list) of argument Just wondering if I have overlooked something obvious. one can also do: lapply(x,lapply,sum) but that assumes that you already know how many levels