similar to: Repeaded sampling

Displaying 20 results from an estimated 5000 matches similar to: "Repeaded sampling"

2012 May 22
3
pad leading zeros in front of strings
Dear All, This question sounds very simple but I don't know where I am wrong. I just want to pad leading zeros in some string, for example, "123" becomes "00123". What is wrong if I do following? > sprintf("%05s", "123") [1] " 123" It didn't return "00123", instead it padded with 'blank'. Thank you for your help
2011 Feb 25
7
R in different OS
Hi All, I have two Rs, one has been installed in Windows system and another one has been installed under UNIX system. Is there any environmental variable or function to tell me which R I am using? The reason that I need to know it is under different system, the data path could be different. I want to do something like if it is R under Windows path =
2011 Aug 30
1
locate the needed columns
Hi All, I have a data frame, whose colnames like "A.x, B.x, C.x, A.y, B.y, C.y". There could be many columns like this pattern. I want to compare data in columns A.x with A.y, B.x with B.y and C.x with C.y etc. Suppose my data frame is d, names(d) = c("A.x", "B.x", "C.x", "A.y", "B.y", "C.y"); If I want to D1 =
2012 Apr 10
1
re-install a package
Hi All, I have a self-cooked package and save it to a zip file after running make, say named xxx.zip. After installing it to R by running "Install packages from local zip files" under Packages menu in R (Windows), I realized I needed to change some source codes and re-make it. My question is that if I need re-install that package or R would automatically update the R
2011 Mar 10
1
aggregate by part of a field
Hi All, I have a data frame like a = data.frame(date = c(20081201, 20081202, 20081201), product = c("a b c d e", "a b c g h t", "d e h a c e h g"), sales = c(1, 2, 3)) Now I want to aggregate the sales by part of the a$product. 'Product' is the product name, a string separated by a space. The key in my aggregate function is
2008 Jan 07
3
Seeking a more efficient way to find partition maxima
Hi. Suppose I have a vector that I partition into disjoint, contiguous subvectors. For example, let v = c(1,4,2,6,7,5), partition it into three subvectors, v1 = v[1:3], v2 = v[4], v3 = v[5:6]. I want to find the maximum element of each subvector. In this example, max(v1) is 4, max(v2) is 6, max(v3) is 7. If I knew that the successive subvector maxima would never decrease, as in the example,
2013 May 02
2
Self-developed package -- installation
Hi All, I have a question about package installation in R. We have developed a package, say 'ABC'. We have installed it in two machines, A and B by running 'Install Package(s) from local zip file'. Everything was fine. Right now, suppose that package got damaged in machine A and our zipped file is gone, My question is that may I directly copy ../library/ABC from machine B to
2012 May 03
2
apply one list to another one
Hi All, Suppose I have the following codes: x = data.frame(A = rnorm(20), B = rnorm(20), C = rnorm(20)) a = list() a[["1.1"]] = x a[["1.2"]] = x b = list() b[["1.1"]] = c("A", "B") b[["1.2"]] = c("B", "C") Now I want to apply b to a like this, for each element of 'a', only select the corresponding columns
2009 Apr 17
1
matching subvectors in vector sets
Hi, I've got a list of ~20000 elements that look like this: [1] "A00096:A00096:A00096:A00096:A02178:A02178:A07776" [2] "A00046:A00076:A01101:A04146:A05671:A07169" [3] "A00038:A00932:A02185:A02370:A02818:A02818:A02818:A02818:A04732:A07142:A07142" [4] "A00096:A01352:A01352:A02023:A05001:A05001:A07776" [5]
2007 Feb 01
3
Can this loop be delooped?
Hi. I have the following code in a loop. It splits a vector into subvectors of equal size. But if the size of the original vector is not an exact multiple of the desired subvector size, then the first few subvectors have one more element than the last few. I know that the cut function could be used to determine where to break up the vector, but it doesn't seem to provide control over
2011 Mar 24
2
apply mean to a three-dimension data
Hi All, Suppose I have data like [[alternative HTML version deleted]]
2012 Jul 09
1
install.packages
Hi All, I have two questions regarding install.packages(). Q1: may I run it in non-interactive mode, which means just install the packages I want rather than letting me to choose which mirror etc? Q2: I ran a R code in batch mode, for example, R CMD BATCH a.r In a.r, I have some statements like packages = library()$result[, "Package"]; f(! "plyr" %in% packages) {
2012 Oct 26
1
backward stepwise model selection
Hi All, I know in R there is function named 'step', which does the stepwise regression and choose the model by AIC. However, if I want to choose a model per this logic: 1. Run a full model (linear regression, f = lm(y ~., data = ZZZ), for example) 2. Pick up the variable with biggest p value, delete it from the module and get a new regression model. 3. Repeat step 2
2011 Apr 21
3
line type lty
Hi All, Does somebody know how to know the detail of the line types? For example, lty = 1, means what kind of line?, lty = 2, means what kind of line? Thanks. HXD [[alternative HTML version deleted]]
2013 Jan 24
1
how to read a website with Chinese Character
Hi all, I am planning to parse some information on a website which includes lots of Chinese characters. Does someone know how to read/display Chinese in R? Thanks. url = "http://www.teec.org.cn/html/renwujieshao/" x = readLines(url) I tried encoding = 'UTF-8' already but it didn't help. My R version is $platform [1] "i386-pc-mingw32" $arch [1] "i386"
2012 Jul 11
1
Variance Inflation factor
Hi All, I need to calculate VIF (variance inflation factor) for my linear regression model. I found there was a function named vif in 'HH' package. I have two questions: 1) I was able to install that package in my R under windows. But while trying to install that package in UNIX, I got error: Package HH is not available. Does somebody know why? 2) Does
2011 Feb 16
1
speed up the code
Hi All, The following is a snippet of my code. It works fine but it is very slow. Is it possible to speed it up by using different data structure or better solution? For 40000 runs, it takes 8 minutes now. Thanks a lot fun_activation = function(s_k, s_hat, x_k, s_hat_len) { common = intersect(s_k, s_hat); if(length(common) != 0) { index = match(common, s_k);
2011 Mar 10
3
Fw: random sampling steps in R with replacement
Please note is with replacement From: taby gathoni <tabieg@yahoo.com> To: R help <r-help@r-project.org> Sent: Thursday, March 10, 2011 11:53 AM Subject: [R] random sampling steps in R Dear all, Could someone assist me in random sampling steps/code in R? I have a main sample of 42 males and 165 females and I want to come up with about 1000 samples of 20 males and 20 females from
2012 Nov 06
2
R and SPSS
Hi group: I have a data set, which has severe colinearity problem. While running linear regression in R and SPSS, I got different models. I am wondering if somebody knows how to make the two software output the same results. (I guess the way R and SPSS handling singularity is different, which leads to different models.) Thanks. [[alternative HTML version deleted]]
2011 Feb 08
1
help on stepfunction
Dear members, I would like a help for extracting the values from a step function (stepfun). >From help(stepfun) we have the following example: Y0<-c(1.,2.,4.,3.) y0<-c(1.,2.,3.,4.) sfun<-stepfun(1:3,y0,f=0) plot(sfun) Now, suppose instead I was given the object (*sfun*, say) from which I wanted to extract the values generated by the function *stepfun*. More precisely, I want to