similar to: There must be a smarter way

What am I doing wrong here ? And what's the right way to calculate the log differences in a column in a df ? # first 3 rows of 5000 rows y[1:3,] Date Open High Low Close 1 1983-03-30 29.96 30.51 29.96 30.35 2 1983-03-31 30.35 30.55 30.20 30.24 3 1983-04-04 30.25 30.65 30.24 30.39 #equation in question ...why is this giving zeros ? y1 <- 100*log(y[,5]/(lag(y[,5],1))) # first 10

Hello, I'm trying to create a data frame with three columns, one of which is a variable-length list. I tried: df <- data.frame(name = c("a", "b", "c"), type=c(1, 2, 3), rtn = c(list(1,2,3), list(4, 5,6), list(7,8,9, 10) ) ) This would be useful, for example, if the 'rtn' is a variable number of

Hi, I want to compute the lower triangle of a square matrix (optionally, sans diagonal). With for() loops I can do something like this: ## 5 by 5 matrix rtn for (j in 1:5) { for (k in 1:j) { if (j != k) { ## optional rtn[j, k] <- my.func(j, k) } } } I'd like to do this with apply(). Is there some way I can do this kind of 'short-circuit'? Thanks, Mark Wilkinson

Can someone explain me what's going on and why the receiver of this fax guives up saying communication error? Slow carrier up Slow carrier down Slow carrier up <<< CSI: 40 20 20 20 20 20 20 20 34 39 34 35 36 34 39 35 30 20 39 33 2b CSI without final frame tag Remote fax gave CSI as: "+39 059465494 " <<< DIS: 80 00 ee f8 c4 00 DIS with final frame tag In

Hi, I apologize if this has previously been posted. I've just subscribed to the R-help digest. I'm writing a plotting function that uses layout() to plot several different plots on the same device. This function uses plot(), image(), and a custom function that uses text(). Each cell of the layout needs different par() parameters, so what I'd like to do is pass them as lists:

Hi Krzysztof, Sure, please see below. DAG.dump.() before and after, annotated with what I believe the DAG means. I've spent some time debugging the method but it's proving difficult to determine where the logic is misfiring. Disabling the entire combine causes a lot of failing x86-64 tests - I may have to learn an upstream vector ISA to make progress on this. Thank you >From your

Should tablegen detect this as an error, or is it documented as a limitation somewhere that we've missed? In the tablegen-generated file AMDILGenIntrinsics.inc, we have a bunch of if statements comparing strings, many of which are dead, preventing correct recognition of some intrinsics in the their text form. I'm not quite sure what GET_FUNCTION_RECOGNIZER is used for, but if it's

Hi [macOSX 10.4.6; R-2.3.0] I have encountered a difference in behaviour between R-2.2.1 and R-2.3.0 when performing a linear model. Transcript follows for R-2.3.0 (R-2.2.1 worked as expected). How to make R-2.3.0 perform as R-2.2.1 did? > dput(x) c(29.13, 29.88, 30.09, 29.99, 29.74, 29.64, 29.65, 29.7, 30.04, 29.89, 29.96, 29.65, 28.76, 28.41, 28.38, 29.55, 29.76, 29.75, 29.84,

If the source being scanned has "llvm.AMDIL.barrier.global, it will match the first barrier test and return AMDIL_barrier, not AMDIL_barrier_global. On Nov 29, 2012, at 7:19 PM, Chris Lattner <clattner at apple.com> wrote: > Out of curiosity, what is wrong about that? It looks ok to me. > > -Chris > > On Nov 29, 2012, at 6:52 PM, "Relph, Richard"

Out of curiosity, what is wrong about that? It looks ok to me. -Chris On Nov 29, 2012, at 6:52 PM, "Relph, Richard" <Richard.Relph at amd.com> wrote: > Should tablegen detect this as an error, or is it documented as a limitation somewhere that we've missed? > > In the tablegen-generated file AMDILGenIntrinsics.inc, we have a bunch of if statements comparing

Hi all, I looked for a function that would retrieve all(!) names of an arbitrary deeply nested named list. Also, names should optionally be arranged in a way that reflects the list's hierarchy structure (i.e. 'a$a.1$a.1.1' etc.) Also, there should be a recursive index linked to a respective list branch that could be used to index a list by names (as you would do with named vectors,

I am calculating the mean of each column grouped by the variable 'id'. I do this using aggregate, data.table, and plyr. My aggregate results do not match the other two, and I am trying to figure out what is incorrect with my syntax. Any suggestions? Thanks. Here is the data. myData <- structure(list(var1 = c(31.59, 32.21, 31.78, 31.34, 31.61, 31.61, 30.59, 30.84, 30.98, 30.79, 30.79,

Hello, I have a nested named list structure, like the following: x <- list( list( list(df1,df2) list(df3, list(df4,df5)) list(df6,df7))) with df1...d7 as data frames. Every data frame is named. Is there a way to get a specific named element in x? so, for example, x[[c("df5")]] gives me the data frame 5? Thank you in advance! Best, Friedericksen

I am trying to write a loop to forecast realized volatility over successive days for the purpose of VaR prediction using the HAR-RV-CJ model which is as follows: log(RV_t+1) = ?_0 + ?_CD log(CV_t) + ?_CW log(CV_t-5) + ?_CM log(CV_t-22) + ?_JD log(J_t + 1) + ?_JW log(J_t-5 + 1) + ?_JM log(J_t-22 + 1) + e_t where RV is realized volatility, CV is continuous volatility and J is the jump which is

R Help - I'm trying to run a correlation matrix with a covariate of "age" and will at some point will also want to covary other variables concurrently. I'm using the "psych" package and have tried other methods such as writing a loop to extract semi-partial correlations, but it does not seem to be working. How can I accomplish this? library(psych) > set.cor(y =

Was a fix for this ever applied to trunk? On Fri, Nov 30, 2012 at 11:08 PM, Chris Lattner <clattner at apple.com> wrote: > Yes that definitely sounds like a bug, no intrinsically in mainline are a > prefix if another one, or we are getting lucky. > > -Chris > > On Nov 29, 2012, at 7:24 PM, "Relph, Richard" <Richard.Relph at amd.com> > wrote: > >

Yes that definitely sounds like a bug, no intrinsically in mainline are a prefix if another one, or we are getting lucky. -Chris On Nov 29, 2012, at 7:24 PM, "Relph, Richard" <Richard.Relph at amd.com> wrote: > If the source being scanned has "llvm.AMDIL.barrier.global, it will match the first barrier test and return AMDIL_barrier, not AMDIL_barrier_global. > >

Hi, I have a question regarding contrasts in linear models. I have a factor variable age with 4 levels, in the output of the linear model I want a coefficient for each level of age. I have made sure that age is a factor but am unsure how to put age into the model to ensure the model knows it is a factor an dto display all levels. I have tried doing fit<-lm(y~C(age)+sex.....) (the dot

Guys, I have been a trying to send a fax using spandsp/app_rtxfax/asterisk. I'm trying to send a (3 page) fax, and all I'm receiving is a single blank page (and I've tried it with 2 fax machines). As some background, I'm using asterisk with an E1 connection through a Sangoma WAN card -- all of this has been working with voice for over 6 months. The software is all working too

Guys, [Forgive this repost -- my original posting doesn't seem to have shown up in the list (yet)] I have been trying to send a fax using spandsp/app_rtxfax/asterisk. I'm trying to send a (3 page) fax, and all I'm receiving is a single blank page (and I've tried it with 2 fax machines). As some background, I'm using asterisk with an E1 connection through a Sangoma WAN card