Displaying 20 results from an estimated 2000 matches similar to: "Finding indexes of minum and maximum elements of an array"
2012 Dec 10
3
equivalent of group command of the egen function in Stata
Dear R listers,
I am trying to create a new variable that uniquely identifies groups of
observations in a dataset. So far I couldn't figure out how to do this in
R. In Stata I would simply type:
egen newvar = group(dim1, dim2, dim3)
Please, find below a quick example to show what I am dealing with:
I have a dataset with 4 variables:
var <- runif(50) ## a variable that I want to group
2011 Aug 17
1
multinomRob - error message
Hi,
I would like to use the multinomRob function to test election results.
However, depending on which independent variables I include and how
many categories I have in the dependent variable, the model cannot be
estimated.
My data look like this (there are 68 observations):
> head(database)
RESTE09 GAUCHE09 PDC09 PLR09 UDC09 MCG09 RESTE05 GAUCHE05 PDC05
D1 1455
2012 Feb 25
5
which is the fastest way to make data.frame out of a three-dimensional array?
foo <- rnorm(30*34*12)
dim(foo) <- c(30, 34, 12)
I want to make a data.frame out of this three-dimensional array. Each dimension will be a variabel (column) in the data.frame.
I know how this can be done in a very slow way using for loops, like this:
x <- rep(seq(from = 1, to = 30), 34)
y <- as.vector(sapply(1:34, function(x) {rep(x, 30)}))
month <- as.vector(sapply(1:12,
2010 Nov 08
1
unknown dimensions for loglm
Dear R-help community,
I am working with multidimensional contingency tables and I am having
trouble getting loglm to run on all dimensions without typing out each
dimension.
I have generated random data and provided output for the results I want
below:
d1.c1 <- rnorm(20, .10, .02)
d1.c2 <- rnorm(20, .10, .02)
d2.c1 <- rnorm(20, .09, .02)
d2.c2 <- rnorm(20, .09, .02)
d3.c1 <-
2012 Dec 07
1
points3d and ordirgl
Hello all, I have been using the function ordirgl to plot 3D dynamic
ordinations. The ordirgl function works just fine. IN fact, I was even
able to write a function that allows me to identify points in the 3D plot:
identify.rgl<-function(env_var,ord,dim1,dim2,dim3)
{
tmp<-select3d(button="left")
tmp.keep<-tmp(ord[,dim1],ord[,dim2],ord[,dim3])
2010 Jan 20
1
Change an array into a dataset of four variables, dim1, dim2, dim3 and its elements
Hi,
See my example below.
a<-array(1:12,c(2,3,2))
> a
, , 1
[,1] [,2] [,3]
[1,] 1 3 5
[2,] 2 4 6
, , 2
[,1] [,2] [,3]
[1,] 7 9 11
[2,] 8 10 12
I want to get a result something like
dim1 dim2 dim3 elements
1 1 1
1 2 1
1 3 2
2 1 2
I tried the data.frame and expand.grid functions,
2004 Jul 16
1
labels for 3d Plots
High!
How can I add variable labels (rownames for instance) to a plot created
with ‚clouds’ ( clouds(dim3~dim1*dim2)) – package lattice?
Thanks in advance!
Martina Renninger
[[alternative HTML version deleted]]
2010 Nov 17
2
Numerical integration
Hi!
I was wondering if there are any other functions for numerical integration,
besides 'integrate' from the stats package, but which wouldn't require the
integrand to be vectorized. Oh, and must be capable of integrating over
(-inf,+inf).
Thanks in advance,
Eduardo Horta
[[alternative HTML version deleted]]
2011 Jan 03
7
Saving objects inside a list
Hello there,
any ideas on how to save all the objects on my workspace inside a list
object?
For example, say my workspace is as follows
ls()
[1] "x" "y" "z"
and suppose I want to put these objects inside a list object, say
object.list <- list()
without having to explicitly write down their names as in
object.list$x = x
object.list$y = y
object.list$z = z
Is
2010 Feb 10
2
system.time provides inaccurate sys.child (PR#14210)
Full_Name: Manuel L?pez-Ib??ez
Version: R version 2.6.2 (2008-02-08)
OS: linux-gnu
Submission from: (NULL) (164.15.10.156)
This is only relevant for CPU intensive child processes. Otherwise, the problem
is not obvious.
Therefore, we need a CPU intensive program like this one:
/************************************/
/*** Compile with: gcc -o timer-test -O0 timer-test.c -lm */
#include
2010 Dec 13
2
Integration with LaTex and LyX
Hello,
Are there any packages which allow for a good integration between R and
LaTex / LyX? I'm interested mainly in automatic (automagic?) imports of
plots/graphics.
Thanks in advance and best regards,
Eduardo de Oliveira Horta
[[alternative HTML version deleted]]
2003 Sep 25
1
apply on a 4D array
I am trying to multiply a 3D array of 4x4x4 by the 4 3D arrays of a 4D array
with dimensions 4x4x4x4 (the last dimension being the one that I want to
split by).
(4x4x4 array)
> hiaAry
, , a1
i1 i2 i3 i4
h1 9.5936098 6.001040 0.08772 0.3138600
h2 1.2003500 1.454570 2.79248 0.0000000
h3 0.1346500 0.201220 0.39256 0.5464000
h4 0.0109000 0.012270 0.16417 0.2766900
,
2001 Dec 31
2
Extracting/setting elements from/in a matrix/array
Dear all,
I had to extracts/set elements from/in a matrix. Let say I have two
vectors dim1 and dim2 of indices in the respective two dimensions of a
matrix: I want to extract all the corresponding elements. I the case of a
nxn matrix, dim1 <- 1:n and dim2 <- 1:n would extract the diagonal.
I know one way would be to use the functions 'row' and 'col', but the
matrixes I
2003 Jul 30
6
reverse array indexing
Hi,
Suppose I have a multidimensional array:
tmp <- array(1:8, c(2,2,2))
is there a function out there that, given a one-dimensional array index,
will
return the separate indices for each array dimension?
for instance, tmp[8] is equivalent to tmp[2,2,2]. I'd like to derive the
vector (2,2,2)
from the index 8.
thanks,
Brad Buchsbaum
2006 Jun 02
2
basic array question
I have a large array and would like to extract from it the row and
column indices just of values for which a particular boolean condition
is true. I assume there's a simple way to do this, but I haven't
figured it out yet. Any help would be appreciated.
Tim
2010 Nov 16
2
Vectors out of lists?
Hello there
I have a list, Y, and each component of that list is a real-valued function
(that is, Y[[i]](u) returns a number).
I was wishing to build the mean function and the first thing I thought of
was
Ybar<-function(u){
mean(Y[[1:n]](u))
}
but obviously this doesn't work, since Y[[1:n]] is not allowed at all.
Any elegant suggestions? I really would like to avoid something like
2010 Apr 22
3
using which to select range of values
Hi all,
I would like to get the array index for a range of values, say 0 < x <
1.5. I'm wondering if there is an alternative for the following which
I've done
x0 <- rnorm(100)
x1 <- ifelse(x0 > 0 & x0 < 1.5,"t","f")
x2 <- which(x1=="t",arr.ind=TRUE)
x0[x2]
Thanks.
--
Muhammad
2010 Nov 27
3
Two time measures
Hello!
I have a csv file of intra-day financial data (5-min closing prices) that
looks like this: (obs - the dates are formated as day/month/year, as is
usual here in Brazil)
Date;Time;Close
01/09/2009;10:00;56567
01/09/2009;10:05;56463
01/09/2009;10:10;56370
##(goes on all day)
01/09/2009;16:45;55771
01/09/2009;16:50;55823
01/09/2009;16:55;55814
##(jumps to the subsequent day)
2008 Sep 10
1
Return dimension index from array with n-dimensions
Hi,
I have been dealing with some problems finding a fast way of getting to
know in what dimension a specific value is located out of an array (like
the 'which' function for a vector returns its position).
Unable to find anything about this on the internet I wrote a function
myself.
Could you please comment if such a function already exists, and if not,
please feel free to comment the
2011 Jan 05
3
Adding lines in ggplot2
Hello,
this is probably a recurrent question, but I couldn't find any answers that
didn't involve the expression "data frame"... so perhaps I'm looking for
something new here.
I wanted to find a code equivalent to
> x=sqrt(1:10)
> y=log(1:10)
> plot(1:10, x, type="lines", col="darkgreen")
> lines(1:10, y, col="red")
to use with