similar to: A question on Statistics

Dear all, I admit this is not anything to do R and even with Statistics perhaps. Strictly speaking this is a math related question. However I have some reasonable feeling that experts here would come up with some elegant suggestion to my question. Here my question is: What is sum of all Integers? I somewhere heard that it is Zero as positive and negative integers will just cancel each other out.

Hi all, in R I have?Sys.timezone() function to get the current working Time zone. However I want to have a vector to get the list of all available time zones, like say, LETTERS gives me all letters. Is there any function like that? Thanks in advance,

Dear all R users, I am wondering is there any procedure exists on R to fetch data directly from "http://www.ncdex.com/Market_Data/Spot_price.aspx" and save it in some time series object, without filling any field in that website. Can somebody point me whether it is possible? Thanks and regards, [[alternative HTML version deleted]]

Hi, I have a dataset that has 2 groups of samples. For each sample, then response measured is the number of success (no.success) obatined with the number of trials (no.trials). So a porportion of success (prpop.success) can be computed as no.success/no.trials. Now the objective is to test if there is a statistical significant difference in the proportion of success between the 2 groups of

Hi, Virsh destroy is always failing with below error. [host:~]$ virsh destroy XYZ--2 error: Failed to destroy domain XYZ--2 error: Requested operation is not valid: domain is not running [host:~]$ virsh list --all Id Name State ---------------------------------------------------- - XYZ--2 shut off [host:~]$ host:~]$ libvirtd --version

Hi, I am neither a statistician nor a user of R. I am a programmer trying to provide my users (both statisticians and R users) data in a format that works best for them. What is a data frame? Is source data easier to work with in this format or a csv file? Or yet another format? Thanks for your time. Bruce [[alternative HTML version deleted]]

Any advice on which package I can use for calculating effect sizes for two dependent samples? compute.es seems only to consider independent samples. Thanks in advance Steve Powell [[alternative HTML version deleted]]

Hi, everybody, I just want to pass arguments to a function as below: range <- c(0.1, 0.5) runif(1, range) But it doesn?t work. Does anyone have any suggestions to offer? Thanks. Lisa -- View this message in context: http://r.789695.n4.nabble.com/Arguments-of-a-function-tp3387643p3387643.html Sent from the R help mailing list archive at Nabble.com.

Hi all, I am new user in R, I am trying to to use paste function to concatenate strings which has been fetched from database table(postgres database), the following are my code: when i do: > sqlFetch(channel,'transactions') outputs are following(only parts, there are around 200 transactions in total) orderid productname price quantity discount 1 T10248 potato 1.80

Hi, let's say I have a simple ANOVA model with 2 factors A (level A1 and A2) and B (level B1 and B2) and their interaction: aov(y~A*B, data=dat) It turns out that the interaction term is not significant (e.g. P value = 0.2), but if I used glht() to compare A1 vs. A2 within each level of B, I found that the comparison is not significant when B=B1, but is very significant (P<0.01) when

Hi list. I'm trying to plot a graph "by" factors. Exactly, the x axis are my depths (as.factor), my left y axis are my transects (also as.factor) and I want to plot the mean and standard deviation (three samples per factor combination) of my SW (numeric) variable. The second y axis (at the right) will, probably, need to be displayed several times (for both left y axis

Hi all, I added the following line on the "Renviron.site" file: R_LIBS=C:\Program Files (x86)\R\library And when I start R and run: .libPaths() I don't see this path. On windows XP it worked for me. I am now using windoes 7 (64 bit) with R 32. Is there a reason this shouldn't work? Thanks, Tal ----------------Contact

Hi, I have a data.frame that has a categorical variable, for which I would like to look at the distribution of levels of this variable, based on a grouping of two other variables. As an example: x <- data.frame(obs=sample(c('low', 'high'),100, replace=TRUE), grp1=sample(1:10, 100, replace=TRUE), grp2=runif(100)) cut.grp1 <- cut(x$grp1, 3) cut.grp2 <- cut(x$grp2, 3)

Hi R experts I am just wondering if something is already available (or easily adaptable) to do the following. I am planning to build linear models for all possible combinations of terms, so for example if the terms are sent into a function as this string " X1 + X2 + X3 + X4 + X1:X2" I would want to build models for all possible combinations of these 5 terms, e.g. m1 <- lm( y ~

Thanks Bill. Do you and others think that a link to this guide (or another)should be included in the Posting Guide and/or R FAQ? -- Bert On Tue, May 17, 2011 at 4:07 PM, <Bill.Venables at csiro.au> wrote: > Amen to all of that, Bert. ?Nicely put. ?The google style guide (not perfect, but a thoughtful contribution on these kinds of issues, has avoiding attach() as its very first line.

I have a dataset where I have missing times (11:00 and 16:00). I would like the outputs to include the missing time so that the final time vector looks like "realt" and has the previous time's value. Ex. If meas at time 15:30 is 0.45, then the meas for time 16:00 will also be 0.45. meas are the measurements and times are the times at which they were taken. meas<-runif(18)

I am a beginner in R, so please don't step on me if this is too simple. I have two data sets datax and datay for which I created a qqplot qqplot(datax,datay) but now I want a line that indicates the perfect match so that I can see how much the plot diverts from the ideal. This ideal however is not normal, so I think qqnorm and qqline cannot be applied. Perhaps you can help? Ralf

Colleagues Assume that I have a vector containing some text strings, some of which contain a particular character. I could like to apply "toupper" to the text before the character. For example (in this case, "|" is the particular character): ORIGINAL: TEXT <- c("aaaa", "bbb|cc", "|ddd") AFTER APPLICATION OF toupper: TEXT <-

I use the following code to create two data.frames d1 and d2 from a list: types <- c("integer", "character", "double") nlines <- 10 d1 <- as.data.frame(lapply(types, do.call, list(nlines)), stringsAsFactor=FALSE) l2 <- lapply(types, do.call, list(nlines)) d2 <- as.data.frame(l2, stringsAsFactors=FALSE) I would expect d1 and d2 to be the

Dear List, how can I obtain the value of r suqared for a non-linear model? For linear models it can be found in the summary() of the model but for non-linear models I just don't know. Please help! Anna