similar to: Vioplot / list help

Hi, I have a list of vectors and am trying to coerce them into something that vioplot will take as groups of data to be plotted independently. Can someone nudge me into the right direction? Thanks, Joh

I am trying to make horizontal violin plots. I have tried both vioplot and simple.violinplot, but both of them seem to not be willing to take the horizontal option. Is this correct, or am I just bungling it somehow? For instance, for vioplot (from the example shown, with the horizontal modification): > vioplot(bimodal,uniform,normal, horizontal=TRUE) Error in median(data) : need numeric data

Hi I am using violin plots (type of boxplots) and  I am trying to increase the font size in the plots. It looks like that the violin plots do not work as "normal" plots as the cex parameters are ignored. You can have a loot at the code below require('vioplot') data1<-rnorm(100) data2<-rnorm(10) data3<-rnorm(1000) vioplot(data1,data2,data3,cex.lab=2,cex.axis=2)

Dear all I am trying to make a graphic with the "vioplot" package. I use the following code: library(vioplot) x1 <- GSMrxDL x2 <- WIFI x3 <- UMT vioplot(x1, x2, x3, ylim=c(0, 10), names=c("GSMrxDL", "WIFI", "UMT"), col="gold") title("NIS Strahlung", xlab="Sender", ylab="V/m") Now I want to scale the y-axis

Hi,? I have made violin plot with both ggplot2 and vioplot package with same data.? The results and code are as follows.? ################### ?Loading data? data.melt <- dget("https://gubox.box.com/shared/static/rirth0eym114afwyjxwe128sjzipzdym.txt") ################### ?Violin plot by library(vioplot) library(vioplot) data.use_11<- data.melt$value[data.melt$ident == 0]

I have been using the package vioplot to make boxplot/densityplots. Now I am looking for a variation of this, and I was wondering if someone could give me any tips on how to do what I want. I have nine groups of values, each group containing two sets of numbers which show the difference between two values, such as this: Start dev Stop dev -1 10 5 -2 0

Hi First post and a relative R newbie.... I am using the vioplot library to produce some violin plots. I have an input CSV with columns off irregular length that contain NAs. I want to strip the NAs out and produce a multiple violin plot automatically labelled using the headers. At the moment I do this Code:? ds1 = read.csv("http://www.lecturematerials.co.uk/data/spelling.csv")

Dear Rgurus, To my knowledge the best way to visualize the distribution of a discrete variable X is plot(table(X)) The problem which I have is the following. I have to discrete variables X and Y which distribution I would like to compare. To overlay the distribution of Y with lines(table(Y)) gives not satisfying results. This is the same in case of using density or histogram. Hence, I am

Dear list, How can I add the mean and standard deviation to each of the boxplots using the example provided in the boxplot function? boxplot(len ~ dose, data = ToothGrowth, boxwex = 0.25, at = 1:3 - 0.2, subset = supp == "VC", col = "yellow", main = "Guinea Pigs' Tooth Growth", xlab = "Vitamin C dose mg",

Hello R-helpers, I would like to calculate least square means after having built a GLM with quasipoisson errors. In my model the dependent variable is continuous, I have one continuous independent variable and one categorical independent variable (that is the variable for which I would like to calculate the least square means). I've looked around for the command to calculate the least

Hi, Is it possible to produce box-and-whisker plots given that I have the median, interquartile and 5/95th centile values, but not the data from which they come? It seems that it ought to be possible to coerce bxp to do what I want, but I can't quite see how. Thanks, Matthew -- Matthew Vernon, Research Fellow Ecology and Epidemiology Group, University of Warwick

I am creating boxplots from a dataframe and would like to add to the standard output a marker representing the value from a particular row in the dataframe. .....And I apologize if the solution is as trivial as it seems it should be. Thanks for any assistance. Keith

Hi, I've spent a while scrabbling around at this problem, to no avail. I'm sure there /should/ be a simple answer... I have a large (14 million rows) data set, with two columns. Each row contains the number of times an individual moved, and the distance that individual moved in total. I would like a figure where the colour indicates the density of points, rather like this one my

Dear List, I have a set of distributions recorded at an equal interval of time and I would like to plot them as series of horizontal histograms (with the x-axis representing time, and y-axis representing the bins) since the distribution shifts from unimodal to multimodal in several occasions. What I would like to see is something close to a violinplot, but I do not want a kernel density

Hi, I would like to use the beanplot() function from the beanplot package. Unfortunately, I can't find out how to suppress the dashed horizontal line, that shows the overall mean. In the help I've found the argument "overallline", but it only allows for "mean" or "median" . I have tried overallline = F, overallline="n", and

Is it possible to force beanplot not to use a log scale? I want to be able to create multiple beanplots of different data on the same specified y-axis. When I try to force a ylim, I get the following... > beanplot(reg5vel,ylim=(c(0,12000))) log="y" selected Warning message: In plot.window(xlim = c(0.5, 7.5), ylim = c(0, 12000), log = "y") : nonfinite axis limits

Hi all, Since two days I am trying to find a solution to be able to create beanplots for my data. When I call the beanplot function the following error appears: > beanplot(y1 ~ x1, log="", what=c(1,1,1,0), ylim=c(0,1)) > Error in bw.SJ(x, method = "dpi") : sample is too sparse to find TD What is really strange: I have 32 different vectors and the problem occurs for

Hi there, I have a set of data that looks like this: As1988<-c(1254.0, 22.0, 4.2, 1081.0, 35.0, 6.0, 1772.0, 192.0, 7.6) The mean of this (as calculated by R) is: 485.9778 The median of this (as calculated by R) is: 35 If I then make a beanplot(As1988), I find that the beanline (average) is now 77.68561 while the beanline (median) is 35.39739 (using the locator function to check the

Dear Helpful R Users, I am graphing some data using the beanplot, but I am having trouble getting the output I desire. I have five tanks (A-E) and 2 groups for each tank grp1 or grp2, except tank C where there is only grp1. (I only changed the grouprep to "C grp1" for the example) When I plot them, I would like A B C(only grp1 - half of the bean plot) then D and E (as full beans).

Hi, boot.ci fails to check if the "type" argument is valid or not. This tripped me up when I had a script that called boot.ci(type="normal",...) repeatedly - only later when I tried to do some further analysis did I realise I'd got nothing useful back from boot.ci. It strikes me that this behaviour is probably incorrect, and that boot.ci should stop if the