similar to: Passing parameter to a function

Hi, This must be an easy one but so far I haven't find a way out... I have a data frame such as: $ v1 : Factor w/ 5 levels $ v2 : Factor w/ 2 levels $ v3 : Class 'difftime' atomic [1:6666] basically v1 and v2 are factors, while v3 is a variable containing the duration of certain activities (values ranging from 11 to 45000 sec, no missing values) How can I get a table

Being italians when writing comments/instructions we use accented letters - like ?, ?, ?, etc.... when running R scripts using such characters I get and error saying: invalid multibyte character in parser I have been looking at the help and searched the r-help archives but I haven't find anything that I could intelligibly apply to my case. Can anyone suggest a fix for this error? Thanks,

Hi, I have been trying to get the label under the total column - i.e. a mean value of columns 2 to 6 - in a barplot I generate with this script: t1 <- tapply(A, B, sum) t1[8] <- mean(t1[2:6]) t1 <- as.table(t1) barplot(t1, ylim=c(0,3000)) mtext("Var1", side = 1, line = 3) mtext("Var2", side = 2, line = 3) I have been trying to use axis(1, at=1:8,

Hi, I first should say I am new to R. I have searched without success the R-archives to see if I could find an answer to what I am about to ask you. My dataset is like: x fine 1 A 2010-12-09 07:57:33 2 B 2010-12-09 08:05:00 3 C 2010-12-08 20:42:00 ... that is: 'data.frame': 3 obs. of 2 variables: $ x : Factor w/ 3 levels "A","B","C":

Dear R-users, I have a factor variable within my data frame which I derive week after week from a POSIXct variable using the cut(var,"weeks") command I have found in the chron package. The levels() command gives me: [1] "2009-03-30 00:00:00" "2009-04-06 00:00:00" "2009-04-13 00:00:00" "2009-04-20 00:00:00" "2009-04-27 00:00:00"

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20110828/d35f51a1/attachment.pl>

Hello R-experts, I would like to know if there is a solution to read files with extension .gsheet directly into R - see http://www.fileinfo.com/extension/gsheet for more info on this file format. Thank you, Luca Mr. Luca Meyer www.lucameyer.com R 2.15.1 Mac OS X 10.8.2 [[alternative HTML version deleted]]

Hello R experts, I have go this data frame: 'data.frame': 1 obs. of 20 variables: $ Anno : chr "PREVISIONI VS TARGET" $ OreTot: num 41 $ GioTot: logi NA $ OrGTot: logi NA $ OreCli: num 99 $ GioCli: logi NA $ OrGCli: logi NA $ OreFor: num -27 $ GioFor: logi NA $ OrGFor: logi NA $ OreOrt: num -18 $ GioOrt: logi NA $ OrGOrt: logi NA $ OreSpo: num -6 $ GioSpo: logi

? stato filtrato un testo allegato il cui set di caratteri non era indicato... Nome: non disponibile URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20110830/7c33d4d0/attachment.pl>

*** APOLOGIZES FOR THOSE READING THE LIST THROUGH NABBLE THIS WAS ALREADY POSTED THERE BUT NOT FORWARDED TO THE LIST FOR SOME UNKNOWN REASON *** I have a dataset that looks like: $ V1: factor with 4 levels $ V2: factor with 4 levels $ V3: factor with 2 levels $ V4: num (summing up to 100 within V3 levels) $ V5: num (nr of cases for each unique combination of V1*V2*V3 levels) Quite new to

Hello, I have a multi-year dataset (see below) with date, a data value and a flag for the data value. I want to find the monthly median for each month in this dataset and then plot it. If anyone has suggestions they would be greatly apperciated. It should be noted that there are some dates with no values and they should be removed. Thanks Emily > print ( str(data$flow$daily) )

Hello! I have a dataset with NA's in some variables (factors), for example: $ P67 : Factor w/ 2 levels "-","+": NA 2 1 NA NA 2 1 1 2 NA ... I need to use 'xtabs' like xtabs(~x$P67) It works well and produces something like this: x$P67 - + 779 1318 but i want to compute NA's too, like this: x$P67 - + NA 779 1318 137 I am trying

Hi I haven't found a way to produce a tabulation from factor data with NA values using xtabs. Please find a minimal example below, it's also on R-pubs [1]. Tested with R 3.1.2 and R-devel r67720. It doesn't seem to be documented explicitly that it's not supported. From reading the code [2] it looks like the relevant call to table() doesn't set the "useNA"

I'm trying to prepare some cross tabs, looking at a number of variables against a variable "connector" which has 2 values: "OD Passenger" and " Connector". When I produce a xtabs one way I have observations under "Connector" but against a different variable "Connector" shows all 0 values. What is wrong? I've looked into the na commands

Hi all, I cannot get xtabs to count NA's like I expect. Below is a sample session, and note that the last two calls to xtabs() yield exactly the same thing. I am running R-2.5.0 -- if there was a bug in xtabs that got fixed, I would love to know about it. If there is a bug tracker somewhere, I can file it too. It isn't my fault that the server is so ridiculously outdated, but I would

Dear all I was willing to use argument 'exclude' in function xtabs to remove some levels of factors (xtabs help page says '"exclude: a vector of values to be excluded when forming the set of levels of the classifying factors"). I tried: > mydata <- data.frame( treatment = c("B", "A", "C", "C", "B",

Hi, xtabs() creates a table of counts. I want a table of proportions -- that is, I want to divide every vector (along a particular dimension) by its sum. The tiny example below does that. The call to xtabs() creates a matrix "A" with dimensions ("x1","x2","y"). I transform "A" using aperm() and aaply() to get the matrix "B". The

Dear list, I am trying to make a contingency table with xtabs but I am getting a 0 where I expect a 'NA'. Here is a simple example: options(stringsAsFactors = FALSE) rn <- LETTERS[1:4] df1 <- data.frame(r07 = rep(rn, each=4), r08 = rep(rn, 4), value = 1:16) xtabs(value ~ r07 + r08, df1) # Delete the combination [A, C] df1 <- df1[-3,] # Set 'value'

I can't figure out the syntax I need to get subset to work. I'm trying to split my dataframe into two parts. I'm sure this is a simple issue, but I'm stumped. I either get all or none of the original "rows". > XTTable <- xtabs( ~ direction_ , SurveyData) > XTTable direction_ EASTBOUND

I'm having a problem reading data to set control totals for a dataframe. I want to adjust a dataframe based on a 2-d table of values, which I get by using : > CurrentX1Sums <- as.matrix(xtabs(~tripid_nu+lineon, data=SurveyData)) > CurrentX2Sums <- apply(CurrentX1Sums, 1, sum) I've created a .csv file with new (target) sums that looks like this: tripid_nu Warner