similar to: time question

Hi all I am a relatively new R user so please excuse this question if it has been covered some where else, just tell me where to find it. I have a simulation model that out puts dates in a standard dd/mm/yy format R reads this as a factor and I cant find anything that will allow me to convert them to a date. In S+ I have used a chron() function that required you to specify the format of the

On the help page "DateTimeClasses {base}" it says: "One can add or subtract a number of seconds or a difftime object from a date-time object, but not add two date-time objects." However, > x<-Sys.time(); y<-Sys.time()+3600 > diff<-y-x > x; y; diff [1] "2005-11-23 19:58:20 GMT" [1] "2005-11-23 20:58:20 GMT" Time difference of 1 hours

I have a frame which contains 3 columns: "date" "defectnum" "state" And I want to get the most recent state change for a given defect number. date is POSIXct. I have tried: aggregate(ev$date, by=list(ev$defectnum), max) Which appears to be working except that the dates seem to come back as integers (presumably the internal representation of POSIXct). When I

Hello R List - I have to import Excel files (either as .csv files or using RODBC) into R (2.4.1, Windows) and operate on dates and times (e.g. find minutes between times, change dates to days of week or analyze by weeks of year). The help files for format.Date, strptime, as.POSIX, DateTimeClasses, etc. etc. are informative but perhaps a little terse. I have googled unsuccessfully for a more

When I use barchart (with default formatting options), I get bars whose lengths/heights are not proportional to their value. For example: http://drop.io/wbagm6s/asset/capture-png Many of the values in this chart are 1; however, because the blue bars extend to the left of the "0" tick mark, those bars appear to represent higher numeric values. Is there a way to make the length of the

I know that this is correct: library(chron) x = dates("01-03-04", format="d-m-y", out.format="day mon year") print(x) It gives me the string "01 Mar 2004" which is correct. I also know that I can say: print(day.of.week(3,1,2004)) in which case he says 1, for today is monday. My question is: How do I combine these two!? :-) I have a

This is mostly a RFC [but *not* about the many extra packages, please..]: Noticing to my chagrin how my students work in a project, googling for R code and cut'n'pasting stuff together, accumulating this and that package on the way all just for simple daily time series (though with partly missing parts), using chron, zoo, lubridate, ... all for things that are very easy in base R *IF*

What is the recommended class for time of day (independent of calendar date)? And what is the recommended way to get the time of day from a POSIXct object? (Not a string representation, but a computable representation.) I have looked in the man page for DateTimeClasses, in the Time Series Analysis Task View and in Spector's Data Manipulation book but haven't found these. Clearly I can

Can anyone please shed any light on why R DateTimeClasses give weird times for when daylight saving time information changes, and which aren't consistent with the OS? Example: Expected result: in New Zealand DST stopped (NZDT -> NZST) at 03:00 NZDT on 2010-04-04, as confirmed by the OS time zone info (OS X 10.8.2): zdump -v /etc/localtime /etc/localtime Sat Apr 3 13:59:59 2010 UTC

> (1) Create a top-level help page with a title like "Date and Time > Classes" to give a brief but general overview. This would mean the > existing DateTimeClasses would need a new title. I wanted to modify my first suggestion. Perhaps a better idea would be to reference an external document giving an overview of the subject. I couldn't find a discussion of POSIXct/POSIXlt

I find that after subsetting (you may prefer "conditional selection") a data frame and assigning it to a new object, the str(new object) reflects the original data frame, not the new one: A <- rnorm(20) B <- factor(rep(c("t", "g"), 10)) C <- factor(rep(c("h", "l"), 10)) D <- data.frame(A, B, C) str(D) # reports correctly E <-

Hi Rowland, Perhaps I misled you with my wording. Each user has just one email address, which was not migrated across. From where I'm sitting that looks like a very serious bug. regards, John On 31/08/15 19:07, Rowland Penny wrote: > On 31/08/15 07:27, John Gardeniers wrote: >> I've been running through a bunch of tests after migrating from >> Samba > 3 to Samba 4

Times from seq.POSIXt come out wrong in AEST timezone around Feb 29 every leap year before 1970 (on Windows XP). According to help(DateTimeClasses), this is handled by "our own C code". > x <- as.POSIXct("1968-02-27") # tz="AEST" > x.gmt <- as.POSIXct("1968-02-27", tz="GMT") > data.frame( GMT=seq(x.gmt, by="day",

Hi, In short, I would like to know if there is any way to convert a numeric into a date, similar to how strptime() can convert a string to a date time class? There are some functions, etc. which don't work well with dates, and tend to force them into numerics. I understand that the number it spits back is the number of seconds since the beginning of 1970 (see the first few sentences

Hello eveybody, I've been looking for a way to share trunks between two asterisk servers. I guest I have to use Dundi, but I've not found the exact method yet. I need a way to allow users registered in one server to use the another server's trunks in the case the first server's trunks were busy and vice versa. Is this possible? Thank you so much, any comment will be useful.

I am a beginner in R with a background in SAS. Are there built-in R methods of reading dates for calculating elapsed days between two calendar dates? If so, are there any examples I can browse? Thanks in anticipation. John Byrne. Lecturer in Information Systems. Australian Catholic University.

Hi all, I need a periodic timer running at ideally at 125 microseconds and at least 500 microseconds. I''ve just found the VCPUOP_set_periodic_timer, however there is a comment saying "periods less than one millisecond may not be supported". I will be running on an x64 machine. Is this supported? If not, is there any alternate means of generating a fast interrupt? Regards.

On Wed, 28 Aug 2013 14:00:10 -0700 Kent Overstreet <kmo at daterainc.com> wrote: > On Wed, Aug 28, 2013 at 01:25:50PM -0700, Andrew Morton wrote: > > On Wed, 28 Aug 2013 12:55:17 -0700 Kent Overstreet <kmo at daterainc.com> wrote: > > > > > Fixup patch, addressing Andrew's review feedback: > > > > Looks reasonable. > > > > >

On Wed, 28 Aug 2013 14:00:10 -0700 Kent Overstreet <kmo at daterainc.com> wrote: > On Wed, Aug 28, 2013 at 01:25:50PM -0700, Andrew Morton wrote: > > On Wed, 28 Aug 2013 12:55:17 -0700 Kent Overstreet <kmo at daterainc.com> wrote: > > > > > Fixup patch, addressing Andrew's review feedback: > > > > Looks reasonable. > > > > >

On the documentation page for DateTimeClasses, in the Examples section, there are the following two lines: format(.leap.seconds) # the leap seconds in your time zone print(.leap.seconds, tz = "PST8PDT") # and in Seattle's The second line (using print) seems to ignore the tz argument, and prints the dates in my time zone, while: format(.leap.seconds, tz =