similar to: Detect the Warning Message

Hello everyone, I have been working on a code which simply repeatedly appends a number into a vector and write a file. However, it could not be properly implemented when I use it. It works when I run it line by line. I wonder what is the problem and I appreciate anyone who is willing to help. The function and the example code is attached. Any advice is appreciated! Best, Yen

Hello everyone, I know where is wrong. I forget to specify the parameters in my function. Thank you for anyone who was trying to help me! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > It seems that I was not successfully attached the code. Here is the > code. I appreciate any help! > > Best, > Yen > > ?? b88207001 at ntu.edu.tw: > >> Hello

Hello everyone, It seems that I was not successfully attached the code. Here is the code. I appreciate any help! Best, Yen ?? b88207001 at ntu.edu.tw: > Hello everyone, > > I have been working on a code which simply repeatedly appends a > number into a vector and write a file. However, it could not be > properly implemented when I use it. It works when I run it line by

Hello dear uesRs, I am working on modeling both level one and level two heteroscedasticity in HLM. In my model, both error variance and variance of random intercept / random slope are affected by some level two variables. I found that nlme is able to model heteroscedasticity. I learned how to use it for level one heteroscedasticity but don't know how to use it to model the level

Hello, everyone, There's a problem about zero in R and I really need your help. I have a vector shown as x=c(0.1819711,0.4811463,0.1935151,0.1433675), The sum of this vector is shown as 1 in R, but when I type 1-sum(x), the value is not zero, but -2.220446e-16. I can accept that this value is quite small and could be seen as zero, but there would be a problem when it's not really

I would like to estimate the sigma matrix of multinormal distribution through ML. But I don't know how to optimize the parameter sigma. Could any one help me? Thank you so much~ Yen Lee

If you don't get a response it is because you did not read the Posting Guide which indicates that the R-sig-ME mailing list is where this question would have been on-topic. -- Sent from my phone. Please excuse my brevity. On August 16, 2017 6:17:03 AM PDT, b88207001 at ntu.edu.tw wrote: >Hello dear uesRs, > >I am working on modeling both level one and level two

A better place for this post would be on R's mixed models list: r-sig-mixed-models . Cheers, Bert Bert Gunter "The trouble with having an open mind is that people keep coming along and sticking things into it." -- Opus (aka Berkeley Breathed in his "Bloom County" comic strip ) On Wed, Aug 16, 2017 at 6:17 AM, <b88207001 at ntu.edu.tw> wrote: > Hello dear

I'm new to post in R-help and my native language is not English. I apologize if my sentence is not fluent to read. I am doing a simulation study and I need to execute SAS and read a SAS code in R. I try the following code but it doesn't work. system('"c:\\program files\\SAS\\SAS 9.1\\sas.exe" "c:\\syntax.sas"') can anyone give me some help with this?

x["V2"] is more efficient than using drop=FALSE, and perfectly normal syntax (data frames are lists of columns). I would ignore the naysayers, or put a comment in if you want to accelerate their uptake. As I understand it, one of the main reasons tibbles exist is because of drop=TRUE. List-slice (single-dimension) indexing works equally well with both standard and tibble types of data

You could declare a matrix much larger than you intend to use. This works with a few megabytes of data. It is not very efficient, so scaling up may become a problem. m22 <- matrix(NA, 1:600000, ncol=6) It does not work to add a new column to the matrix, as in you get an error if you try m22[ , 7] but convert to data frame and add a column m23 <- data.frame(m22) m23$x7 <- 12 The only

Your desire is not unusual among novices... but it is really not a good idea for your function to be making those decisions. Look at how R does things: The lm function prints nothing... it returns an object containing the result of a linear regression. If you happen to call it directly from the R command prompt and don't assign it to a variable, then the command interpreter notices that

I just like the subroutine to spit out results (Mean, Std.dev, etc.) and also be able to access the results for further processing, i.e., v$Mean v$Std.dev On 3/26/2024 11:24 AM, Richard O'Keefe wrote: > Not clear what you mean by "saved". > If you call a function and the result is printed, the result is > remembered for a wee while in > the variable .Last.value, so

Just FYI, the R interpreter typically saves the last value returned briefly in a variable called .Last.value that can be accessed before you do anything else. > sin(.5) [1] 0.4794255 > temp <- .Last.value > print(temp) [1] 0.4794255 > sin(.666) [1] 0.6178457 > .Last.value [1] 0.6178457 > temp [1] 0.4794255 > invisible(sin(0.2)) > .Last.value [1] 0.1986693 So perhaps if

Thanks. Will try it. Have not tried it but I think the following may work: out$results<-NULL out$results$ei<-ap out$results$vi<-vap All I need is printing by returning out (unless I turn it off). And, retrieve ap and vap as needed as shown above. Guess I need to read more about invisible. On 8/11/2024 10:09 PM, Rui Barradas wrote: > ?s 09:51 de 11/08/2024, Steven Yen escreveu:

"Or use <<- assignment I think. (I usually return, but return can only return one object and I think you want two or more" You can return any number of objects by putting them in a list and returning the list. Use of "<<-" is rarely a good idea in R. -- Bert On Fri, Aug 9, 2024 at 1:53?AM CALUM POLWART <polc1410 at gmail.com> wrote: > > OK. The fact

You could also do dim(x) <- c(length(x), 1) On Sat, Aug 5, 2023, 20:12 Steven Yen <styen at ntu.edu.tw> wrote: > I wish to stack columns of a matrix into one column. The following > matrix command does it. Any other ways? Thanks. > > > x<-matrix(1:20,5,4) > > x > [,1] [,2] [,3] [,4] > [1,] 1 6 11 16 > [2,] 2 7 12 17 > [3,]

Thanks to all. Very helpful. Steven from iPhone > On Jan 14, 2023, at 3:08 PM, Andrew Simmons <akwsimmo at gmail.com> wrote: > > ?You'll want to use grep() or grepl(). By default, grep() uses extended > regular expressions to find matches, but you can also use perl regular > expressions and globbing (after converting to a regular expression). > For example: >

Hello I have a vector: set.seed(123) > n<-3 > x<-rnorm(n); x [1] -0.56047565 -0.23017749 1.55870831 I like to create a matrix with elements containing variances and covariances of x. That is var(x[1]) cov(x[1],x[2]) cov(x[1],x[3]) cov(x[2],x[1]) var(x[2]) cov(x[2],x[3]) cov(x[3],x[1]) cov(x[3],x[2]) var(x[3]) And I like to do it with "apply". Thanks. On 10/4/2024 6:35

I have trouble documenting an R package. In my .Rd file (sixth line below), I have uhat<-m%*%y but when the package is built (successfully), the matrix multiplication part does not show up in the documentation. The line become (missing %*% y) uhat<-m === \examples{ x<-c(1,2,3,4,5) y<-c(1,1,2,2,4) x<-cbind(1,x) m<-mmat(x) uhat<-m%*%y dstat(uhat) } ?-- styen at ntu.edu.tw