similar to: Plotting 2 Lines on the Same Chart

Howdy. Been running into a bit of trouble with plotting. Seems that axes=F is not "working". Whenever I plot (either a dataframe or xts/zoo series) and I set axes=F along with xlab/ylab="" I still get the default axes printed in my chart. Consider this: #Create some sample data, both 50 units of blah series2 = c(1:50) series1 = rep(25:74) testdf1 = as.data.frame(series1)

I'm having trouble returning a rolling n period highest value for a data set. For each day I want to calculate the highest value over the last 3 days. I am using the following packages: zoo, xts, quantmod and TTR. Thanks, Jason GLD.Close 2010-10-01 128.91 2010-10-04 128.46 2010-10-05 130.99 2010-10-06 131.81 2010-10-07 130.37 2010-10-08 131.66 2010-10-11

Hello everybody, I have two series of intervals, and I'd like to output the shared regions. For example: series1<-cbind(Start=c(10,21,40,300),End=c(20,26,70,350)) series2<-cbind(Start=c(25,60,210,500),End=c(40,100,400,1000)) > series1 Start End [1,] 10 20 [2,] 21 26 [3,] 40 70 [4,] 300 350 > series2 Start End [1,] 25 40 [2,] 60 100 [3,]

Dear List, I would be pleased if someone can help me with the following issue: I'm about to plot two time series in one plot via ts.plot which looks like: ts.plot(series1, series2, main=main, xlab=xlab, ylab=ylab, col=c("green", "red", "blue"), lwd=2) The problem is, that R automatically sets the x axes labels in 5-year-intervalls. Every

Hello users, I've noticed a problem when creating a stacked column plot when a column contains a negative and a positive value. e.g. series1<-c(-1,-2, 3, 4, 5) series2<-c( 5, -4,-3,-2, 1) data<-rbind(series1,series2) barplot(as.matrix(data), beside=FALSE) In these cases (i.e. first, third and fifth columns) the plotting is not handled correctly. Compare this output with that

Dear R heleprs   Suppose I have following data   Scenarios combination_names     series1    series2 Sc1 MAT2 GAU1 7.26554 8.409778 Sc2 MAT2 GAU2 7.438128 8.130275 Sc3 MAT3 GAU1 8.058422 8.06457 Sc4 MAT1 GAU2 8.179855 8.022071 Sc5 MAT3 GAU2 8.184033 8.191831 Sc6 MAT3 GAU2 7.50312 8.232425 Sc7 MAT1 GAU2 7.603291 8.200993 Sc8 MAT1 GAU1 8.221755 8.380097 Sc9 MAT3 GAU2 7.904908

uugh : i promise that this will be my last question of the day. i hate to constantly bother this group but it takes me time to get familar with all of these functions, tricks and and manipulations. i appreciate everyone's patience. i used too splus a lot but i've gotten rusty. i have a matrix of say 200 rows and 600 columns. i have a function "getprofit" that takes two series

I'm new to R and have searched for help and consulted the the pdf manuals, but I can't seem to figure out how to plot more than one series on the same graph. I've tried using multiple par(new=TRUE) statements such as >plot(series1, ci.type="line", col="red", lwd=2, ci.lty=0, ci.col="red") >par(new=TRUE) >plot(series2, ci.type="line",

I've created a dataframe containing multiple ACF lists through the command rev.acf<-apply(rev.matrix, 2, acf, na.action=na.contiguous, lag.max=12, plot=FALSE) where rev.matrix is an n by t matrix containing n time series in columns. I'd now like to pull out only the ACF information and store it in a seperate n by 12 matrix. So far the only way I can work out to access this is

Hi you guys: I have been wondering if there is any way to change the labeling in plot.ts( ), for example , if I plot two sequences, i always got y labels as "series1", "series2", I tried to use ylab=c((expression(mu_1)),(expression(mu_2))), but it doesn't work. thanks in advance for any help best.

Dear R users, I have 3 columns in a zoo object. I want to plot all of them in one screen but I want the first two to be in "lines" format and 3rd one to be barplot. Regards Vikram [[alternative HTML version deleted]]

I have a data set with quarterly time series for several variables. The time index is recorded in column 1 of the dataframe as a character vector "Q1 1961", "Q2 1961","Q3 1961", "Q4 1961", "Q1 1962", etc. I want to produce line plots with ggplot2, but it seems I need to convert the time index from character to date class. Is that right? If so, how

Price 2010-10-11 99 2010-10-12 101 2010-10-13 102 2010-10-14 103 2010-10-15 99 2010-10-18 98 2010-10-19 97 2010-10-20 101 2010-10-21 101 2010-10-22 101 I have this dataset and I only want to return instances when the Price is > 100. If I use the code: Price > 100 then it will evaluate each entry as "TRUE" or "FALSE". What is the code

Using Achim's d this also works to generate z where FUN is a function used to transform the index column and format is also passed to FUN. z <- read.zoo(d, index = "time", FUN = as.yearqtr, format = "Q%q %Y") On Sun, Jan 28, 2018 at 4:53 PM, Achim Zeileis <Achim.Zeileis at uibk.ac.at> wrote: > On Sun, 28 Jan 2018, phil at philipsmith.ca wrote: > >> I

Hi all, I'm a newbie to R and it has been very helpful to use your website. Unfortunately I've been struggling with my code now for two days so I wanted to ask few questions. I've been trying to create nice graphs to put into a pdf sheet but I'm having little problems with all the packages I've been using. So what I want to accomplish is create one pdf sheet with three graphs

On Sun, 28 Jan 2018, phil at philipsmith.ca wrote: > I have a data set with quarterly time series for several variables. The > time index is recorded in column 1 of the dataframe as a character > vector "Q1 1961", "Q2 1961","Q3 1961", "Q4 1961", "Q1 1962", etc. I want > to produce line plots with ggplot2, but it seems I need to

Dear Group, I have the following data matrix which is a timeseries. > dput(tData) structure(list(A = c(0.2, 0.13, 0.05, 0.1, 0.02, 0.18, 0.09, 0.06, 0.13), B = c(0.15, 0.06, 0.09, 0.02, 0.03, 0.12, 0.01, 0.15, 0.06), C = c(-0.1, 0, -0.07, -0.06, -0.05, -0.05, -0.06, -0.08, -0.07), D = c(-0.15, -0.05, -0.1, -0.03, -0.13, -0.04, -0.1, -0.04, -0.15), E = c(-0.17, -0.16, -0.08, -0.07, -0.09,

Hi, I found the thread http://r.789695.n4.nabble.com/Matrix-as-input-to-xyplot-lattice-proper-extended-formula-syntax-td896948.html I used Gabor's approach and then tried to assign the plot to a variable (see below). But a Quartz device is opened... why? I don't want to have anything plot/printed, I just would like to store the plot object. Is there something like "plot =

Hi, I have three time series and I would like to plot them on the same graph such that two of them share left y-axis and the third uses right y-axis. rm(list=ls()) library(zoo) x1 <- read.csv(file="120322DBCdata.csv", header=TRUE) x1date<-as.yearqtr(1979)+seq(0,nrow(x1)-1)/4 x1zoo<-zoo(x1, x1date, frequency=4) x1zoodata<-cbind(x1zoo$D4GDP, x1zoo$D4NE,

Dear list, I would like to create a time series plot in which the paths of several individuals are stacked above each other, with the x-axis being the total observation period of three years ( 1.1.2004 to 31.12.2007) and the y-axis being some defined range[min,max]. My data consist of Date/Time information and the paths of 45 individual as the distance from the location of release. An example