similar to: Printing data.frame data: alternatives to print?

Well, do you have a patch that enables the new pass manager that we can land then? To be more serious: 1) I don't even know how to run those passes using the new pass manager even if it where enabled by default. I guess that I'm supposed to use -passes. Is there a syntax description for that option somewhere? How do I for example run -die? 2) "Use the new pass manager" does

Hi all, I have the following two function f1 and f2. f1 <- function(lambda,z,p1){ lambda*(p1*exp(-3*z-9/2)+(0.2-p1)*exp(4*z-8))-(1-lambda)*0.8} f2 <- function(p1,cl, cu){ 0.8*(pnorm(cl)+(1-pnorm(cu)))/(0.8*(pnorm(cl)+(1-pnorm(cu)))+p1*(pnorm(cl+3)+(1-pnorm(cu+3)))+(0.2-p1)*(pnorm(cl-4)+(1-pnorm(cu-4))))}-0.05 First fix p1 to be 0.15. (i) choose a lambda value, say lamda=0.6, (ii)

Hi, I'd like to unsubscribe from the list. Thanks Neyra ________________________________ De: "r-help-request@r-project.org" <r-help-request@r-project.org> Para: r-help@r-project.org Enviado: sáb, octubre 30, 2010 5:30:07 AM Asunto: R-help Digest, Vol 92, Issue 31 Send R-help mailing list submissions to r-help@r-project.org To subscribe or unsubscribe via the

Hello Everyone, *Question: *How do you calculate the sum of squares for a two-way _unbalanced_ ANOVA? *What I have done:* I have found many useful tutorials online for running a balanced two-way ANOVA but I haven't had much luck for running a unbalanced two-way ANOVA. From what I have read, the trouble with running an unbalanced two-way ANOVA, is that things get tricky when calculating

It is not uncommon to want to coarsen a factor by grouping levels together. I have found one way to do this in R: > sites [1] F A A D A A B F C F A D E E D C F A E D F C E D E F F D B C Levels: A B C D E F > regions <- list(I = c("A","B","C"), II = "D", III = c("E","F")) > library(Epi) > region <-

Hi Björn, 1) The pass pipeline syntax is documented here: https://github.com/llvm-project/llvm/blob/master/include/llvm/Passes/PassBuilder.h#L378 -die is not implemented, since the new pass manager does not support BasicBlock passes. But you can use dce instead: "-passes=dce" 2) I don't have a qualified answer here, but if I recall correctly, the trouble to correctly update the

I am wondering how to interpret the parameter estimates that lm() reports in this sort of situation: y = round(rnorm(n=24,mean=5,sd=2),2) A = gl(3,2,24,labels=c("one","two","three")) B = gl(4,6,24,labels=c("i","ii","iii","iv")) # Make both observations for A=1, B=4 missing y[19] = NA y[20] = NA data.frame(y,A,B) nonadd = lm(y ~

Hi All, I have two files. 1. with only one column 2. data matrix I need to compare first columns of both files and print the rows from second file for the overlapping entries. I have solutions for awk and sed, but I need how to do it in R. Thanks Regards Anchal -- Anchal Sharma, PhD Postdoctoral Fellow 195, Little Albany street, Cancer Institute of New Jersey Rutgers University NJ-08901

If I run: opt -globals-aa -die -inline -debug-pass=Details foo.ll -S then I will get this pass structure: Target Library Information Target Transform Information Target Pass Configuration Assumption Cache Tracker Profile summary info ModulePass Manager CallGraph Construction Globals Alias Analysis FunctionPass Manager BasicBlockPass Manager Dead Instruction

I'm interested in plotting a y with an x factor as the combination of 2 factors and colour with respect to a third, which the code below does with interaction.plot(). However, this is because I redefine the x to be 1 factor. Is there a way of getting it to plot without redefining it, and ideally to not join up the lines BETWEEN levels a and b, but just join those between after and before for

I'm not sure about the old pass manager, but I think the new pass manager solves this issue. See llvm::updateCGAndAnalysisManagerForFunctionPass where it updates the call graph to be in sync with edges deleted by function passes. So I suspect the right fix is to use the new pass manager. -- Sanjoy On Mon, May 7, 2018 at 7:32 AM, Björn Pettersson A via llvm-dev <llvm-dev at

This is just my curiousity working. Suppose I write: f1 <- function(x) x + 1 f2 <- function(x) 2 * f1(x) f2(10) # 22 f1 <- function(x) x - 1 f2(10) # 18 This is quite obvious. But is there any way to define f2 in such a way that we "freeze" the definition of f1? f1 <- function(x) x + 1 f2 <- function(x) # put something here 2 * f1(x) # probably put something else here

There's a StackOverflow question https://stackoverflow.com/q/22024082/2554330 that references this text from ?missing: "Currently missing can only be used in the immediate body of the function that defines the argument, not in the body of a nested function or a local call. This may change in the future." Someone pointed out (in https://stackoverflow.com/a/58169498/2554330)

I am exploring the result of clustering a large multivariate data set into a number of groups, represented, say, by a factor G. I wrote a function to see how categorical variables vary between groups: > ddisp <- function(dvar) { + csqt <- chisq.test(G,dvar) + print(csqt$statistic) + print(csqt$observed) + print(round(csqt$expected)) + round(csqt$residuals) + } > > x

I'm using specify.model for the sem package. I can't figure out how to represent the residual errors for the observed variables for a CFA model. (Once I get this working I need to add some further constraints.) Here is what I've tried: model.sa <- specify.model() F1 -> X1,l11, NA F1 -> X2,l21, NA F1 -> X3,l31, NA F1 -> X4,l41, NA F1 -> X5, NA, 0.20

Someone can help me? I tried several things and always don't converge # Model library(sem) dados40.cov <- cov(dados40,method="spearman") model.dados40 <- specify.model() F1 -> Item11, lam11, NA F1 -> Item31, lam31, NA F1 -> Item36, lam36, NA F1 -> Item54, lam54, NA F1 -> Item63, lam63, NA F1 -> Item65, lam55, NA F1 -> Item67, lam67, NA F1 ->

I have a question related to scoping. Suppose we have 2 functions: f1 = function(i){i = 1} f2 = function(n){ i = length(n) f1(i) } In other words, I would like i=1 regardless of n. Is this possible without having f1 in the body of f2? Thanks in advance!

Hi. I have defined a function, f1, that calls another function, f2. Inside f1 an intermediate variable called nm1 is created; it is a matrix. f2 takes a matrix argument, and I defined f2 (schematically) as follows: f2<-function(nmArg1=nm1,...){nC<-ncol(nmArg1); ... } so that it expects nm1 as the default value of its argument. f1 is defined (schematically) as:

Hi. I have tried to use Package "SEM". As a learning, I try to convert a program running well of EQS which is as follows to SEM: ### EQS ### /SPECIFICATION CAS=100; VAR=5 MAT=COR; ANA=COR; /EQUATIONS V1=*F1+E1; V2=*F1+E2; V3=*F1+*F2+E3; V4=**F1+*F2*E4; V5=*F2+E5; /VAR E1 TO E5=*; F1*1.0; F2=1.0; /COV E1,E2=*; F1,F2=*: /PRINT FIT ALL; /MATRIX ...... /END This is the converted SEM

... can be used to represent unknown number of parameters passed into a function. For example, I write a function g. g calls another function f1. For example f1 could be different random number generation function. when f1=rnorm(), it has 3 parameters n, mean and standard deviation. when f1=rexp(), it has 2 parameters n and rate. g can be defined as g <- function(f1, ...) { f1(...) }