similar to: get the rows so that there is no redundant element in a certain column

Dear Helpers: If you know how to fit a Weibull model using R, you are my savior for my project. The hazard ramda is specified as t^alpha * (1+a*dose*exp(-b*dose)). Or, can we modify the Cox model to capture the proportional part above? Here t is the survial time, dose is a subject received in a exposed group. Thank you a lot. Boshao

Dear Helpers:   I spend more than half a day to solve this problem in R:   Let x be a vector of a string of 0s and 1s, such as x<-c(0,0,1,1,0,0,0,0,1,1,0,0,0,0). It can be a very long vector. How to sub vectors of 0s? In the above example, I would like get the vectors (0,0), (0,0,0,0), (0,0,0,0). I can use which(x==0) to get the index of the 0 elements, but I don't know how to get the

Hi, everyone I am trying to estimate 3 parameters for my survival function. It's very complicated. The negative loglikelihood function is: l<- function(m1,m2,b) -sum( d*( log(m1) + log(m2) + log(1- exp(-(b + m2)*t)) ) + (m1/b - d)*log(m2 + b*exp(-(b + m2)*t) ) + m1*t - m1/b*log(b+m2) ) here d and t are given, "sum" means sum over these two vairables. the parameters

Dear Everyone in list: I am writing some codes to automate the process of fitting linear models where the names of variables of models are produced and stored in character vectors. But I have problems to pass the vectors to the lm( ) because I don't know how to strip the quotation marks automatically. Here are the codes of the example of lm( ): ## Annette Dobson (1990) "An Introduction

Hi, Let say I have this matrix: > mat<-matrix(cbind(rnorm(20),rnorm(20)), ncol = 2) And I want to rescale values of column [,1] and [,2] using values from row 1 to 5, such that the values of row 1:5 should be rescale to the same amplitude (kinda like take the z-score of population from row 1:5). column 1 and 2 are two different samples need to be compared. I hope I made myself clear

I would like to remove rows from the following data frame (df) if there are only two specific elements found in the df$ch character string (I want to remove rows with only "0" & "D" or "0" & "d"). Alternatively, I would like to remove rows if the first non-zero element is "D" or "d".

Hi all, I Try use shorewall rules with time element but its never works, the rules look like this HTTPS(REJECT) loc net:69.63.181.11,69.63.181.12,69.63.184.142,69.63.187.17,69.63.187.19 localtz&timestart=20:00&timestop=20:10&weekdays=Mon,Tue,Wed,Thu,Fri This rules for block https access to facebook site at working hours & day My system is Debian lenny, shorewall 4.4.4.2 kernel

? Wed, 14 Feb 2024 14:43:12 -0800 Jennifer Bryan <jenny.f.bryan at gmail.com> ?????: > But in r-devel on macOS, this is silent no-op, i.e. "hello, world" > does not print: > > > R.version.string > [1] "R Under development (unstable) (2024-02-13 r85895)" > > con <- pipe("cat") > > writeLines("hello, world", con) I

Now I am trying to use LLVM to write a simulator and take LLVM as IR to dynamic translate machine code, I encounter some issues when try to write some IR to express writting a value to the reigster. The situation is described as the following description. write_reg is my function for writing "v" to the register indicated by "index". ptr_gpr is the struct pointer for my

Hi, I have a matrix like this, two columns: a, b a b c1 21 c2 19 c2 20 c2 20 c4 25 c5 18 c5 18 how to prepare a new matrix removing the rows with repeated units in b columns, like there are two 20 and two 18 in b column (others are unique in b col). I wanna a pure matrix with one 20 and one 18. Thanks a lot! Yan [[alternative HTML version deleted]]

Is there a reason scriptaculous provides what appears to be a redundant function? The reason I''m asking is that it only seems to be used twice throughout all of scriptaculous, and it doesn''t appear to work properly (for some reason it''s returning the actual element, rather than an array with all of the elements) If there is no reason, I''ll modify it to use

Hello, I've noticed a specific type of pipe() usage that works in released R, but not in r-devel. In 4.3.2 on macOS, I can write to a connection returned by pipe(), i.e. "hello, world" prints here: > R.version.string [1] "R version 4.3.2 (2023-10-31)" > con <- pipe("cat") > writeLines("hello, world", con) hello, world But in r-devel on

Hi, First of all - thank you for the answers regarding shared library. If i am attempting to translate the library from Linux to Windows - i think i will need some heavy baby-sitting ;-))) It is way out of my league - for now. Meanwhile i have this new question: suppose i have a data.frame with x and y columns and 10 rows, 1 to 10. I also have a variable m (or an array if you like) with 5

Hi, I have a table where column 1 has ID numbers and column two has data, and I have a vector containing a subset of those ID numbers. How can I create a new table with only the rows from the old table that match the IDs in the vector, like below: Original Table: ID Value 1 123 2 123 3 123 4 123 vect: [2, 3] New table: ID Value 2 123 3 123

Hello, I'm using <read.csv("filename",header=TRUE) but need to extract just certain columns or rows from the file. Much thanks. -- View this message in context: http://n4.nabble.com/selecting-certain-columns-or-rows-from-a-csv-tp1835692p1835692.html Sent from the R help mailing list archive at Nabble.com.

Hi, I have a data-frame r (shown below is a subset) with the following column names: date time sample vct norm hct deltact $time has 8 levels: 0h, 0.5h, .....24h. $deltact holds real numbers. I want to subset this dataframe by the levels of $time. For all the rows which have r$time == "0h" I would like to convert the present value of r$deltact to 0. Any pointers to a

Hello, I have a specific problem, I have a large dataframe, and after clustering I want to select certain colums, the elements of a subcluster. My dataframe looks like this : > colnames(data) [1] "101KF4319097339" "102KF4319101170" "103KF4319047549" "104KF4319046389" [5] "105KF4319013260" "106KF4319025582"

Hi, I want to use the value of variable to quote elements in matrix. For example, I have a matrix like:               y1   y2m1         1      2m2         3      4 where y1,y2,m1,m2 are column and row names.  I have two random character variable, say x,  that could be either  y1 or y2  and  y that could be either m1 or m2.  So can I  do like   Matrix[y,x] to quote elements?  I've tried this

Hello, I have a data frame with 2 columns: year and code. In code column, I want to replace elements that are not "8210", "8310", or "9190" with "others". -- Sincerely, Yosub Jung. [[alternative HTML version deleted]]

I have 2 vectors A and B. For each element of B I'd like to find the index of the next higher or equal element in A. And I'd like to store it effectiv. E.g.: A <- c(1,3,7,8,10) B <- c(5,8) result: 3, 4 I have a possibility but for long vectors it works not very effectiv: ans <- sapply(B, function(x) which.max(A[A < x]) ) as.integer(ans + 1) Is there anyone how has a better