similar to: times

Hello, I am working on a project consisting of several r-scripts written in the tinn editor. Is it possible to create a superior r script containing commands to run the sub-scripts one by one? ----- Tamara Hoebinger University of Vienna -- View this message in context: http://www.nabble.com/run-r-scripts-%28tinn%29-via-command-tp22580362p22580362.html Sent from the R help mailing list archive

Hello, I have a dataframe containing dates, times and other parameters. The times have the format "h:m", e.g. 13:00 or 5:30, R classes them as factors. I want to change the times to integers e.g. 13:00 -> 1300. I tried to use "chron" to create a chronological object, but it didn't work for the times (yust for the dates). ----- Tamara Hoebinger University of Vienna --

Hello, I have a problem with reading a csv-file. One colum of the inputfile consists of characters and numbers. After reading the csv-file I create a new dataframe by dividing the values of that colum into more colums (then a colum contains just characters or numbers) but the numbers are converted to factors. How can I create the new dataframe without having the numbers converted to factors?

Hello, I have a problem with a tklistbox. The user should be able to choose one out of two calculation methods needed for further calculations. My r-script for that purpose looks like that: require(tcltk) tt<-tktoplevel() tl<-tklistbox(tt,height=4,selectmode="single",background="white") tkgrid(tklabel(tt,text="select method for LAI

There seems no default setting for tck, causing problems for plot.times() > library(chron) > dts <- dates(c("02/27/92", "02/27/92", "01/14/92", + "02/28/92", "02/01/92")) > y<-chron(dts,out.format=c("dmy","h:m:s")) > y [1] 270292 270292 140192 280292 010292 > plot(y,1:5) Error in axis(n, at =

I a have a text file where every line is like that: "2007-12-03 13:50:17 Juan Perez" ("yy-mm-dd hh:mm:ss First Name Second Name") I would like to make a data frame with two column one for date and the other one for name. When I use read.delim it was transformed in a data frame with 4 colums. Bye, Sebasti?n.

Hello, I am having some fun dealing with dates and times. My input is a excel csv file with two columns with data in the following format: date time 25-Jun-1961 04:00:00 i.e. day - month - year hour:min:sec I would like to have a single object in R that combines these and converts them into a sensible R format (e.g.

dear R users, I have troubles performing Moran.I test as suggested on http://www.ats.ucla.edu/stat/r/faq/morans_i.htm my spatial data are longitude and lattitide of communities. The calculation of the inverse distance matrix according to the homepage (using my data) datAL <- read.csv2("C:\\Konvergenz AL.csv", header=T) ALdist <- as.matrix(dist(cbind(datAL$L?nge,

Hi, I keep on trying to write some small scripts in order to learn R but even with basic scripts I have problems ... I start with the name of a file which is in fact the time the file has been generated (I cannot change the format). Then I convert namefile with strptime. The problem occurs when I add another time from another file with append. It displays some informations I don't want. I

Hi everybody How do I do to calculate the median and average of a colum of time data like this: "8:50:10". I also need to plot the time difference between two colums Thanks a lot -- View this message in context: http://n4.nabble.com/median-for-time-data-tp932287p932287.html Sent from the R help mailing list archive at Nabble.com.

Hello dear useRs and wizaRds, I encountered the following problem using the hist() method for the 'times' classes from package 'chron'. You should be able to recreate it using the code: library(chron) # pasted from chron help file (?chron) dts <- dates(c("02/27/92", "02/27/92", "01/14/92", "02/28/92", "02/01/92")) class(dts)

I have two local variables: startTime and expectedStartTime. Both are chron related objects. When I look at the class for the objects I can see they are of class "times". When I print them to the console, they both read: "09:30:00" When I print them as.numeric(), they both read: 0.3958333 When I try and compare them: (as.numeric(startTime) == as.numeric(expectedStartTime)) it

Dear all, As a novice user of R I ran into a problem that's quite hard for me to resolve. I have a database containing data of a clinical trial in which patients are included that survived or died: x <- matrix(data=c(1:5,0, "1/1/2012 00:00:00",0,0,"1/7/2012 00:00:00"), nrow=5, ncol=2, dimnames= list(NULL,c("ID", "dateofdeath"))) My file is a .csv

the date were created with chron with this argument format=c(dates="Y/m/d", times="H:M:S")) so I have the dates being displayed as (10/06/22 12:00:00) I would like to have them displayed as "2010-06-22 12:00:00" or "%Y-%m-%d %H:%M:%S" and then I can convert these for mergeing with another data frame x <- (structure(c(14464, 14464.0104166667,

Agradezco la ayuda recibida me vino muy bien,,, el problema de instalar el paquete lubridate es que no está en los repositorios de Debian,,, al usar RStudio creo que se debe instalar en ~/R/x86_64-pc-linux-gnu-library previa compilación de fuente bajada de r-cran,,, cosa que será otro pedido de ayuda en el futuro si sale mal,,, Saludos Horacio El día 30 de diciembre de 2016, 7:05, Carlos Ortega

Full_Name: Dennis Wolf Version: 1.9.0 OS: Mac OS 10.3.3 Submission from: (NULL) (160.91.76.23) platform powerpc-apple-darwin6.8 arch powerpc os darwin6.8 system powerpc, darwin6.8 status major 1 minor 9.0 year 2004 month 04 day

Buenas, esta pregunta es un poco elemental, pero estoy haciendo mis primeras experiencias en R. Yo tengo un CSV con el siguiente formato... fecha;Gastos;media móvil;Holt Winter 31/08/02;2498,5;;2498,5 29/09/02;2250,93;2320,63;2424,229 31/10/02;2212,46;2097,87;2360,6983 30/11/02;1830,22;2092,78;2201,55481 ,,,,,,, los guardo en un dataframe con gastos=read.csv2("indice_gastos.csv"),

Hello, How can I convert Close colume of the below xts time series data into a list of Close values ? I'd like to plot Close values as a list. &gt; head(zc) Close (10/15/12 09:00:00) 252.40 (10/15/12 09:01:00) 253.10 (10/15/12 09:02:00) 253.15 (10/15/12 09:03:00) 253.30 (10/15/12 09:04:00) 253.25 (10/15/12 09:05:00) 253.45 I tried the below command to plot it.

Dear Group, Having a character vector like this one: [1] "03:38:55" "07:42:38" "08:04:27" "08:17:13" "08:41:14" "08:46:58" [7] "08:47:11" "08:53:51" "08:57:51" "08:58:56" I try to do a histogram over times of a day. All I want to know, if my solution is proper or if there is another

I am running a simple R program, its skeleton is enclosed below. The program reads about 80 files with about 5000 lines with coloumns of data. After an unpredictable and variable number of loops for run to run, it exits with segmentation fault or alternatively with the error Error in names<-.default(*tmp*, value = fnames) : Unimplemented feature in duplicate Removing the call to