similar to: discerning plot dots using colors

Hello, If I have a dataframe: example(data.frame) zz<-c("aa_bb","bb_cc","cc_dd","dd_ee","ee_ff","ff_gg","gg_hh","ii_jj","jj_kk","kk_ll") ddd <- cbind(dd, group = zz) and I want to divide the column named group by the "_", how would I do this? so instead of the first row being x

Hello, I am a bit over my head on this issue. My colleagues and I are running R off of our server. We all have admin rights and prior to yesterday we all had our own libraries. Our main system administrator advised us that we should have a shared library. So, I am trying to do this. I have downloaded the latest version of R and installed it on the main drive of our server in the "Program

Hello help, I have changed around some graphing code and made it into a function. Previously they y label of the axis was inserted as text in its own layout box. text(1,1, expression(~degree~C),cex=1) This worked great and resulted in the symbol for degree. In the function, I have changed it so: text(1,1,paste(b_unit),cex=1) and b_unit<-expression(~degree~C) This now inserts ~degree~C

Dear List, I am making a list of all the files in a folder and I want to exclude one file called "proj.current". This is the 31st file in a folder. Currently I use the command: tdirs <- list.files(pattern="proj.")[-31] However I would like to exclude it based on its name and not the position. Any advice would be useful. Thanks, Daisy Daisy Englert Duursma Room

Hi, I want to impute the missing values in my data set multiple times, and then combine the results (like multiple imputation, but manually) to get a mean of the parameter(s) from the multiple imputations. Does anyone know how to do this? I have the following script: y1 <- rnorm(20,0,3) y2 <- rnorm(20,3,3) y3 <- rnorm(20,3,3) y4 <- rnorm(20,6,3) y <- c(y1,y2,y3,y4) x1 <-

Hello and thanks for helping. #some data L3 <- LETTERS[1:3] dat1 <- data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE))) #When x==1 and y==1 I want to replace the 1 values with NA #I can select the rows I want: dat2<-subset(dat1,x==1 & y==1) #replace the 1 with NA dat2$x<-rep(NA,nrow(dat2) dat2$y<-rep(NA,nrow(dat2) #select the other rows and rbind

Hello, I am not sure where to begin with this problem or what to search for in r-help. I just don't know what to call this. If I have 5 columns, the first 2 are the x,y, locations and the last three are variables about those locations. x<-seq(1860,1950,by=10) y<-seq(-290,-200,by=10) ANN<-c(3,0,0,0,1,0,1,1,0,0) CTA<-c(0,1,0,0,0,0,1,0,0,2) GLM<-c(0,0,2,0,0,0,0,1,0,0)

Hello, I am trying to cycle through a csv and make some summary statistics. I need to select rows based on the number in the row name that comes after the letter 'y'. For example, ? BA1y1 would equal 1, ?C3A2r3y1 would equal 1 and ?MA3r3y1r3 would equal 1. I currently have my code ?cycling through by the 5th character but my rows have variable length and the y can occur in several

Hello, I am trying to use R to download a bunch of .csv files such as: http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia I have tried the following and neither work: a<- getURL(" http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia") Error in curlPerform(curl = curl, .opts = opts, .encoding = .encoding) : embedded nul in string: and

Hello, I am struggling with computing nodes in Unix. I have the use of a Unix server that has 30 nodes and I would like to batch scripts. Here is an R example that results in 72 repeated tasks based on the 2 loops. If I wanted to send these out to the different nodes, each node has 1 task and the remaining 42 tasks are put in a queue, what would I do? #Example:

Hello, I think this is a simple problem but I am not coming up with a simple solution. I think it just an indexing problem. I can easily replace values in a matrix from a dataframe when the dataframe has row and column numbers. In the example below I use row and column names and I can not get it to work #make a matrix where rows and columns are the lat and long for a bounding box of Australia

Hello, I am running R on a server that several people share. Previously we all had separate libraries for R. I have set up R so everyone on the server shares the same library and I downloaded the latest version of R and installed it on the main drive of our server in the "Program Files" folder (obvious enough). I changed the Environmental Variables in the advanced system setting so

Dear List, I am running constrained correspondence analysis for abundance data of 7 birds. However, I would like to check which bird prefers which environment gradient by showing the species with different colors of the dots in cca plot (package vegan). Please kindly help and thank you Elaine [[alternative HTML version deleted]]

Dear List, I have a richness data distributing across 20 N to 20 S latitude. (120 E-140 E longitude). I would like to draw the richness in the north hemisphere and a regression line in the plot (x-axis: latitude, y-axis: richness in the north hemisphere). The above demand is done using plot. Then, south hemisphere richness and regression are required to be generated using the same y-axis above

random selection of cells in raster based on distance from xy locations Hi, I am trying to sample a raster for random cells that occur within a specific distance of point locations. I have successfully found multiple ways of doing this but have memory issues with very large datasets. To overcome this problem I am working with lists. I am now stuck on how to randomlly sample the correct elements

Hello, I have two plots on the same screen. I use the command par(mfrow=c(1,2)) in order to do this. When I try to make a legend for both plots, it only puts the legend in the plot on the right side. If I would like a legend that is outside of both of the plots, how would I do this? Thanks [[alternative HTML version deleted]]

Hey guys, I've search a few threads about deleting a value from a vector, but no one has addressed this question so far. I want to delete the last value from a string of values I have: r = [ 1, 2, 3, 4, 5 ], and i want to make r2 = to [ 1, 2, 3, 4] So that r2 is just like r, except that it missing the final value. Thanks, -- View this message in context:

Dear I use dataset , as called "mpg" This is code ggplot(data=mpg)+ geom_point(mapping = aes(x=displ, y=hwy, colour=year)) But I would like to see only "year of 1999" in this relationship between x and y variables How could I change the code in this direction? I found the following code library(dplyr)year_1999 <- filter(mpg, year=="1999")ggplot(year_1999,

Dear List, I am trying to plot the result of cca using matplot but failed. Pls kindly help and thanks. Elaine The error message was error in xy.coords(x, y, xlabel, ylabel, log = log) : (list) object cannot be coerced to type 'double' code rm(list=ls()) library(vegan) library(MASS) # input richness birdrich

Hi ! I am new to R, and using the MAC version onto Mac OS 9.1. My question concerns the problem I encounter when I try to read some data I have using the read.table function. I always get an error of type : Error in scan(file = file, what = what, sep = sep, quote = quote, dec = dec, : line 1 did not have 9 elements Here is my code: varnames <- c("names", "symbol",