similar to: difftime error

I am trying to convert an array from numeric values back to date and time format. The code I have used is as follows; for (i in 0:(length(DateTime3)-1)) { DateTime3[i] <- (strptime(start, "%m/%d/%Y %H:%M")+ i*interval) where start <- [1] "1/1/1981 00:00" However the created array (DateTime3) contains [1,] 347156400 347157600 347158800 347160000 347161200 347162400

Hi, For this example: O <- c(0 0 0 2 0 0 2 0) I want to create an array every time O[i] > 0. The array should be in the form; R[j] <- array(-1, dim=c(2,O[i])) i.e. if O[i] > 0 4 times I want 4 R arrays. Does anyone have any suggestions? Thanks, Doug -- View this message in context: http://r.789695.n4.nabble.com/Create-Arrays-tp2996706p2996706.html Sent from the R help

Hi, I am having some problems using the if statement correctly. I have used it many times previously so I dona't know what is different with this case. Here is my problem: I have a 1X10 matrix of values as follows: > H.MC [,1] [1,] 4.257669 [2,] 7.023242 [3,] 4.949857 [4,] 5.107000 [5,] 4.257669 [6,] 4.257669 [7,] 4.257669 [8,] 4.257669 [9,] 4.257669 [10,] 4.257669

Hi there. I have the following graph: http://www.nabble.com/file/p10928148/map.jpg However, some datapoints occur at the same place as other datapoints and are so layered on top of each other. I would like to know if there is any possible way in which I could view those datapoints that are layered on top of each other ...maybe by rotating using latitude to show the datapoints underneath (but

R community, I am trying to write a code that fills in data gaps in a time series. I have no R or statistics background at all but the use of R is proving to be a large portion of my PhD research. So far my code identifies where and the number of new entries required but I do not know how to add additional rows or columns into an array. Any advice on how this can be done? Here is an example:

R community, I am creating a bivariate return level plot by adding calculated return period values as lines onto an existing plot using the following code with the points representing the return periods. plot(H2,D2,pch="+",axes=TRUE) points(H.10,D.10, type="l",col="blue") points(H.20,D.20, type="l",col="green") points(H.50,D.50,

Dear R community, I am creating large graphs with hundreds of thousands of datapoints. My usual way for output was pdf, but now I am getting file sizes of >30Mb that do not open well (or at all) in Adobe. Is there a way to reduce the resolution or get rid of overlaying datapoints? Any other idea is also warmly welcome! Thank you and wishing you a good day! Georg. **********************

Dear Ms and Mr R, I am seeking a visually appealing presentation of 3 variables (~30 datapoints) that are correlated and that should to into the same direction. The objective is to show that they do go in the same direction and what differences there might be while also giving an idea of the values of the variables. I had done this with simple bargraphs for 6 datapoints in the past, but for

It is known that function bkde2D (package "KernSmooth") returns a matrix of density estimates over the mesh induced by x1 and x2. In Details it is written that "... heights of the kernel, scaled by the bandwidths, at each datapoint are summed. This sum, after a normalization, is the corresponding fhat value in the output". There are several questions: 1) How to calculate

Hello, I'm currently using a simple plot to visualize some mean values. I'm having ~200 datapoints on the x-axis, each has 10 records. I'm currently plotting only the mean value of each of the datapoints. What I need is a way to visualize the quartiles/error/whatever of these points. I thought about boxplots, but I have to many points on the xaxis - it would be impossible to see

Hello, I am trying to plot age distribution data for a certain condition that runs in families. Below is a simplified view of the dataset, i.e. in this case there are four families, each line corresponding to one individual with age at diagnosis and sex. > famdata family age sex 1 fam1 2.1 f 2 fam1 2.3 f 3 fam1 1.0 m 4 fam2 7.3 f 5 fam2 4.1 f 6 fam2 1.2 f 7

Hi all, here is my situation In my experiment, I expose 10 subjects to 24 different conditions of stimuli. Each condition is exposed to the same subject 3x. This would make each subject have 24x3=72 data points. All the subjects combined would have 72x10=720 data points with each condition having 30 datapoints. To find the grand average of each condition, I find the average of all the

I am trying to do something in R and would appreciate a push into the right direction. I hope some of you experts can help. I have two distributions obtrained from 10000 datapoints each (about 10000 datapoints each, non-normal with multi-model shape (when eye-balling densities) but other then that I know little about its distribution). When plotting the two distributions together I can see that

Hi- I am trying to find a way to diffuse GIS data on a European map. I have a dataset consisting of particular locations scattered across Europe, along with magnitude and value information. I can plot these as discrete points with something like the following: "geocode" is a dataframe with four columns: LAT; LONG; MAGNITUDE;VALUE. library(maps) library(mapdata)

Full_Name: Suharto Anggono Version: 2.8.1 OS: Windows Submission from: (NULL) (125.161.134.206) About PR#14067, now I understand why (Date + difftime) does not use '+.Date'. But, before I understand, it was surprising. The surprise is also reflected in the post "Problem with +(POSIXt, difftime) dispatching -- WAS: How to create sequence of constant time interval" in R-help

Full_Name: Suharto Anggono Version: 2.8.1 OS: Windows Submission from: (NULL) (125.165.81.48) There is already PR#13369. But, the problem is not just the warning. C:\Program Files\R\R-2.8.1\bin>R --vanilla R version 2.8.1 (2008-12-22) Copyright (C) 2008 The R Foundation for Statistical Computing ISBN 3-900051-07-0 R is free software and comes with ABSOLUTELY NO WARRANTY. You are welcome

Hi, I am trying to take difference of two time objects. I want to fix the result's unit to minutes. How can I do that? Here is an example: > difftime(x, y) Time difference of 2.030720 hours > difftime(x, z) Time difference of 30.34672 mins where x = '2007-03-05 08:32:58' y = '2007-03-05 06:31:07' and z = '2007-03-05 08:02:37' How can I get answer

On Thu, Jun 10, 2010 at 3:39 PM, Gustaf Rydevik <gustaf.rydevik at gmail.com> wrote: > Hi all, > > The recent change in 2.11 that made as.numeric() return false on > difftime-objects broke some of my code that calculated age classes of > individuals using cut(). While this was no big thing to fix for me, it > might be wise > to provide a cut.difftime method to ?stop

On Thu, Jun 10, 2010 at 3:39 PM, Gustaf Rydevik <gustaf.rydevik at gmail.com> wrote: > Hi all, > > The recent change in 2.11 that made as.numeric() return false on > difftime-objects broke some of my code that calculated age classes of > individuals using cut(). While this was no big thing to fix for me, it > might be wise > to provide a cut.difftime method to ?stop

I have a column of 1000 datapoints from the normal distribution with mean 2 and variance 4. How can I get a histogram of these observations with 20 bins with each bin having 50 observations? -- Thanks, Jim. [[alternative HTML version deleted]]