similar to: help identifying clusters

I'm not sure if this is what you want. But the function coordinates() in sp package gives you the coordinates of SpatialObjects. Regards. Rodrigo. 2010/6/9 Nikhil Kaza <nikhil.list@gmail.com> > You need to execute gpclibPermit() to enable gpclib. > > library(maptools) should have issued a warning to that effect. > > > Nikhil Kaza > Asst. Professor, > City and

Greetings all, Ran into a strange problem with the krige function from geoR. The problem that I am having is that while the krige function seems to work well, the resulting predicted values are all NAs. Given the size of the datasets I am working with can't attach it, but I can provide snippets of the datasets. > casedata station year month day obs mpe bias type

Hi everybody. I'll first explain my problem and what I'm trying to do. Admit this example: I'm working on 5 different weather stations. I have first in one file 3 of these 5 weather stations, containing their data. Here's an example of this file: DF1 <- data.frame(station=c("ST001","ST004","ST005"),data=c(5,2,8)) And my two other stations in

Hi! I am trying to implement non-bipartite matching. I have around 500 sites which can be clustered by 10 regions. I am able to calculate pairwise Mahalanobis distances between sites (thanks to another post in the forum). However, I want to constrain my match to sites within the same region. Thus I want to replace elements of the distance matrix with a high value, say 999999, for sites not of the

Hi all, I am sorry if this is a very basic quesion, but I have no experience with analyzing spatial data and could not find the right function/package quickly. Any hints would be much appreciated. I have a matrix of spatial point patterns like the one below and want to find the number of independent components (if that's the right term) in that matrix (or in that image). x=matrix(c(0,1,0,0,0,

Hi lily, It's not too hard to do it using dataframes. Getting the indexing right is usually that hardest part: # these values are the centers of the black cells lat<-rep(28:38,11) lon<-rep(98:108,each=11) pop<-sample(80:200,121) # just use the data.frame function blackcells<-data.frame(lat=lat,lon=lon,pop=pop) plot(0,type="n",xlim=c(97.5,108.5),ylim=c(27.5,38.5),

a) you need to read the help pages on the paste function... more likely you are looking for the paste0 function because extra spaces will most likely break the GET request format. b) quotes do not become "stuck" as \" ... that is a visual representation intended to clarify that that quote is not terminating the string but is actually part of it. If you want to see the contents

Hope one of you could help with the following question/problem: We would like to explain the spatial distribution of juvenile fish. We have 2135 records, from 75 vessels (code_tripnr) and 7 to 39 observations for each vessel, hence the random effect for code_tripnr. The offset (‘offsetter’) accounts for the haul duration and sub sampling factor. There are no extreme outliers in lat/lon. The model

I have done the following using readLines directory <- "~/" files <- list.files(directory) data_frames <- vector("list", length(files)) for (i in seq_along(files)) { df <- readLines(file.path(directory, files[i])) df <- df[-(1:13)] df <- data.frame(year = substr(df,1,4), month = substr(df, 6,7), day =

Hello I am a new user of R . and I ve problem with R and netcdf . I succed installation , I could use all examples . But when I take my netcf it is different . I want to do statistic on this kind of file . 1) first calculate mean . my data is like that through ncdump -h test.nc netcdf test { dimensions: lat = 301 ; lon = 401 ; time = UNLIMITED ; // (80 currently)

Dear CSAG R users, I will be glad if someone can point out what I am doing wrong or not doing at all in this. I am trying to write out netcdf file in R. I have 26 time step but only the first time step is written. For example: >library(ncdf) >path <- '/home/work/' >forecast <- open.ncdf(paste(path,'cam.1980.2005.nc',sep="")) > fore <-

Dear CSAG R users, I will be glad if someone can point out what I am doing wrong or not doing at all in this. I am trying to write out netcdf file in R. I have 26 time step but only the first time step is written. For example: >library(ncdf) >path <- '/home/work/' >forecast <- open.ncdf(paste(path,'cam.1980.2005.nc',sep="")) > fore <-

Hi lily, There are one or two assumptions to be made here. First is that the latitude and longitude values of the "black" cells are equally spaced as in your illustration. Second, that all latitude and longitude values for the "red" cells fall at the corners of four "black" cells. You can get the four "black" cells by finding the lat/lon values that are

> On Oct 15, 2017, at 3:35 PM, Miluji Sb <milujisb at gmail.com> wrote: > > Dear David, > > This is amazing, thank you so much. If I may ask another question: > > The output looks like the following: > > ### > dput(head(x,15)) > c("Metadata for Requested Time Series:", "", "prod_name=GLDAS_NOAH025_3H_v2.0", >

Hi Jim, Thanks. It works. I now have more complex problems. If at each blackcell, there are two variables such as pop and mood. For each variable, there are daily records in one year, so 365 records for pop and 365 records for mood. The averaged values for the redcells should be daily records too. What kind of format do you recommend for this problem? Right now, I just get the latitudes and

Hi, I'm trying to read a subset of a netcdf file into R, but although I'm relatively experienced using R, I'm still new to netCDF files, so this may be a very simple/stupid question! I've included an example of the type of file I'm looking at here. www.met.reading.ac.uk/~swp06hg/ccd1983_01-dk1_20.nc (~7Mb) It's a 2D array of the variable CCD along with its lat and

Dear David, This is amazing, thank you so much. If I may ask another question: The output looks like the following: ### dput(head(x,15)) c("Metadata for Requested Time Series:", "", "prod_name=GLDAS_NOAH025_3H_v2.0", "param_short_name=Tair_f_inst", "param_name=Near surface air temperature", "unit=K",

I am ploting gridded time series data. I would like the actual lat and lon value appear on the graph-if possible inside the graph as numbers. If there is also more elegant ways to plot the graphs I will appreciate more suggestions. ################################# library(ggplot2) library(lattice) month <- c("Jan", "Feb", "Mar", "Apr", "May",

R Help, I posted a question on StackOverflow yesterday regarding an issue I've been having with the RgoogleMaps packages' displaying of axes. ?Here is the text of that submission: http://stackoverflow.com/questions/6258408/rgooglemaps-axes "I can't find any documentation of the following problem I'm having with the axis labels in RGoogleMaps: library(RgoogleMaps) datas

Hi, everyone I got some problems when trying to subscript the value of vector and list, by using calculated indices. Here is the vector I am generated lon<-rep(0,886);lat<-rep(0,691) for (i in 1:886){ lon[i]<-112+0.05*(i-1) } for (i in 691:1){ lat[i]<--44.5+0.05*(691-i) } For a given location of lon(xp) and lat(yp), I would like to calculate the position of them,