similar to: Drop matching lines from readLines

I have a question about the output given below after running few lines of code. Surely a 101 query! MF_Data <- read.csv("MF_Data_F.txt", header = F, sep="|") temp <- head(MF_Data) #Get the sample Data temp1 <- subset(temp, select= c(V1,V4,V6)) #where V1, V4, V6 are the col names .. to Get the relevant data names(temp1) <- c('Ticker',

I'm attempting to create an array of treatment comparisons for modelling data generation. This involves comparison of one treatment (c2) with another (c3), relative to a common comparator (c1). Attached code gives me the correct array but need to remove duplicates. Duplicates relate only to c2 and c3 such that I need to remove r3 because c2 and c3 are same as r1 with c2 and c3 swapped r5

Dear All, I am trying to create a empty structure that I want to fill gradually through the code. I want to use something like rbind to create the basic structure first. I am looking for a possibility to do an rbind where the columns names dont match fully (but the missing columns can be defaulted to either zero or n/a) (my actual data has a lot of columns). Please see the data frames below I

Hello, I have a data frame as below ... in cases where I have N.A. I want to use an average of the past date and next date .. any help? 13/10/2010 A 23 13/10/2010 B 12 13/10/2010 C 124 14/10/2010 A 43 14/10/2010 B 54 14/10/2010 C 65 15/10/2010 A 43 15/10/2010 B N.A. 15/10/2010 C 65 ---------------------------------------------------------------------------- -------------------------- Thanks

Dear Group, I have the following data matrix which is a timeseries. > dput(tData) structure(list(A = c(0.2, 0.13, 0.05, 0.1, 0.02, 0.18, 0.09, 0.06, 0.13), B = c(0.15, 0.06, 0.09, 0.02, 0.03, 0.12, 0.01, 0.15, 0.06), C = c(-0.1, 0, -0.07, -0.06, -0.05, -0.05, -0.06, -0.08, -0.07), D = c(-0.15, -0.05, -0.1, -0.03, -0.13, -0.04, -0.1, -0.04, -0.15), E = c(-0.17, -0.16, -0.08, -0.07, -0.09,

Dear Group, I have a following dataset: > a A B C D 1 22 3 31 40 2 26 31 36 32 3 3 7 49 16 4 24 40 27 26 5 20 45 47 0 6 34 43 11 18 7 48 48 24 2 8 3 16 39 48 9 20 49 7 21 10 17 36 47 10 > dput(a) structure(list(A = c(22L, 26L, 3L, 24L, 20L, 34L, 48L, 3L, 20L, 17L), B = c(3L, 31L, 7L, 40L, 45L, 43L, 48L, 16L, 49L, 36L), C = c(31L, 36L, 49L, 27L, 47L, 11L, 24L,

I'm unable to find the OR operator like other language .. any suggestions? I want to do If (condition1 OR condition 2){ do something } Thanks for answering this elementary question. [[alternative HTML version deleted]]

Dear R-Group, I am looking for suggestions for the "best" IDE for R. Best is obviously subjective but I need just the basic features that should function well (and I looked through the threads already). - Proper integration with R 2.11.1 - Good key shortcuts ... similar to the R Gui - Manageability of Projects, etc. - Neat formatting features I tried Revolution R but it seems huge in

Hello Group, I need a modification in the data.table example to get my intended result shown below ... is there a more simple way! dt <- data.table(A = rep(1:3, each=4), B = rep(1:4, each=3), C = rep(1:2, 6)) dt[, transform(.SD,D=mean(A)), by="B"] The result I want is below ... which is probably long winded! data.table(unique(as.data.frame(dt[, transform(.SD,D=mean(A)),

Hello,   I tried to use a variable to refer colname, but I got error, could anyone give me advice?   >df=data.frame(cbind(AB=1:3,AC=3:5)) > df$AC [1] 3 4 5 > df$paste("A","C",sep="") Error: attempt to apply non-function thanks Jian   [[alternative HTML version deleted]]

I am trying to find the function where I can search for a pattern in a text string (I thought I could use grep for this but no :(). > x [1] "abcdefghijkl" I want to find the positions (i.e. equivalent of nchar) for "cd" and in case there are multiple hits .. then the results as a array Thank you.

I need to transpose the following input dataset into an output dataset like below Input Date TICKER Price 11/10/2010 A 0.991642 11/10/2010 B 0.475023 11/10/2010 C 0.218642 11/10/2010 D 0.365135 12/10/2010 A 0.687873 12/10/2010 B 0.47006 12/10/2010 C 0.533542 12/10/2010 D 0.812439 13/10/2010 A 0.210848 13/10/2010 B 0.699799 13/10/2010 C

Hi Group, Is there something like a delay function based on System time or equivalent? I basically am generating a few graphs and I would like to see each graph for say 2mins before moving on to the next one? I can always have an empty for-loop I guess but is there a better way? Thanks, S

Hello Group, I have an R-function that works fine for most part but sometime runs into a long loop! (I'm lazy and short on time to debug right now so want to do something easy) For my purpose, it is ok to make few errors .... is there a way I can put a timeout on a function and the r-process needes to move on to the next step? Thank you. S

Dear Group, I am having a function that I am running in a loop that generated two results for each loop The result1 is a zoo object The result2 is a data frame Now I want to put both of them in a list or some structure ... that I can access or output to a file after the loop is done. For e.g. for (i in 1:20){ niceFunction(x[i],i) } niceFunction (x,i) { result1 = someOperations() #zoo

Hi Group, I often need to print out data frames with results of analysis into a neat little image to copy and paste into documents. I need apply formatting like bold, currency signs, number formats, header shading etc. I currently output the data into csv and format using good old excel. Any suggestions if there are packages to help with such activities (to some level of basic functionality). I

Dear Group, Is there some way for me to package a few lines of R-code as exe and have it running in the background? (unable to find info in the archives) Even better if I can package it as an installation and send to my team who do not have any background in programming / R? If they can install and run the exe ... it would suffice. Thanks, S

Dear Group, Why does write.csv modify the date format when it write to a file. I have the following variable Param_Dat: dput(Param_Dat) structure(list(Last_Successful_Run = structure(1L, .Label = "30/10/2010", class = "factor")), .Names = "Last_Successful_Run", class = "data.frame", row.names = c(NA, -1L)) When I do:

Hi Group, I am having a strange problem for this simple task. I am using read.table to read a plan 3 column CSV file . the file is getting read . But the first column has datetime in the csv file in the following format: 20110221.114041 But this is being read as 20110221 only . the time portion (decimal is missing) in the data frame Any idea why? Thanks, Santosh

Hello Group, This is an open-ended question. Quite fascinated by the things I can do and the control I have on my activities since I started using R. I basically have been using this for analytical related work off my desktop. My experience has been quite good and most issues where I need to investigate and solve are typical items more related to data errors, format corruption, etc... not