similar to: drilling down data on charts

Hi All, I want to have an array/ matrix that looks this x<- 0 0 1 1 1 3 5 4 4 7 -1 8 9 10 6 I hope this makes sense. So basically if I want x[1,3] it will access 0 and similarly x[4,2], -1. Thanks in advance, Sachin p.s. sorry about the corporate notice. --- Please consider the environment before printing this email --- Allianz - Best General Insurance Company of the Year 2010*

Hi All, I'm trying to create labels to plot such that it doesn't show up as scientific notation. So for example how do I get R to show 1e06 as $1,000,000. I was wondering if there was a single function which allows you to do that, the same way that as.Date() allows you to show in date format on a plot. Thanks, Sachin --- Please consider the environment before printing this email ---

Hi R, In the following code my x-axis is formatted in month format. Which Im happy with. The y-axis is what I want to re-format with something else. My question is, is it possible just to switch off the xaxis in plot function (see below). If not how do you get the months to show up as FEB-YYYY, MAR-YYYY and so on, so I could fit a label on x-axis. Thanks, Sachin p.s. sorry about corporate

Hi All, I've reproduced the example from Prof. Friedrich Leisch's webpage. When I write sweave("Example-1.Snw") OR sweave("Example-1.Rnw"), (yes, I renamed them). I get the following error: Writing to file example-1.tex Processing code chunks ... 1 : echo term verbatim Error: chunk 1 Error in library(ctest) : there is no package called 'ctest' Also while

Hi All, I am trying to run R scripts on a server rather than my own machine. The biggest reason being that the data can be 3GB+; more than my RAM can handle. Anyway is there a way to do this. I am trying to find a SAS alternative. In SAS you can do (keyword) rsubmit; and get things running remotely on a server. Is there something similar on R. Couldn't find a comprehensive answer online.

Hi All, Currently my plot shows the y-axis in scientific notation (1e07 and so on). I want to be able to display this in dollars such that it shows $10,000,000 (including the commas). How do I do this. Also with the xlabel and ylabel. I've specified: 'title('Cash vs Time',xlab='Period',ylab=''); Im hoping that this will also not display anything on the y-axis.

Hi All, I have a date in the format of yymmdd (without any of the backslashes, eg. 100731). How do I convert this into a Rdate and plot it? I don't want the number of days from 1970's showing up as my date (Its the date I require). Thanks, Sachin p.s. sorry about the corporate notice I can't remove it. --- Please consider the environment before printing this email --- Allianz -

Hi all, Just following on from a previous thread (for loop). Is there a parallel 'for' loop like matlab (parfor maybe?). I know there was a Nvidia GPU version for blas somewhere. But is there a CPU or a GPU version of the for loop? Thanks, Sachin p.s. sorry about the corporate notice below: cant get rid of it. Don't have other mail client access at the office :( --- Please consider

Hi all, When I write out some values and then use 'plot' and 'lines' respectively I can get R to plot me two lines. However when I get the data from a csv file and run it I only manage to get one line running (whichever was invoked first). The sample files are attached below and I've reproduced the code below with the suspicious part marked as #??? (not even sure if thats

Hi All, When I run the following code, I cannot see the entire number. As opposed to seeing 1,000,000,000. I only see 000,000 because the rest is cut off. The cex option doesn't seem to be doing anything at all. y<-seq(1e09,5e09,1e09); plot(1:5,y,ylab='',yaxt='n' ); axis(2, at=y, labels=formatC(y,big.mark=",",format="fg"),las=2,cex=0.1); Any thoughts?

Hi All, I've been looking around (maybe not extensively) but I couldn't find any documentation on the list of fonts thats useable with R. Im trying to change the font of the title, seems like mtext is the only way so far, which can actually write on top of each other depending on the lines: plot(1:5,1:5); mtext("Title",side=3,cex=3.5,line=1); mtext("Sub

Hi, dear fellows, I was wondering how can I simulate from an estimated density function? I used my training data set and already have estimated density values at some fixed points. I plan to simulate some data from such estimated density and compare them to my validation data set. Anyone can help out is really appreciated. Thanks. Jay -- View this message in context:

I stupidly decided to save my last workspace (a large dataset) and every time I open R it loads it back in. Can I stop this? Also how do you clear variables. Thanks, Sachin --- Please consider the environment before printing this email --- Allianz - General Insurance Company of the Year 2009+ + Australia and New Zealand Insurance Industry Awards This email and any attachments has been sent by

Hi, This might be me missing something painfully obvious but why does the cube root of the following produce an NaN? > (-4)^(1/3) [1] NaN > As we can see: > (-1.587401)^3 [1] -4 Thanks! Greg

Hi All, Are there any escape characters that I should be aware of when using table.read? I don't have any '#' characters in this table. I get the error: A<-read.table("P:/temp.csv",header=TRUE, sep=","); Error in scan(file, what, nmax, sep, dec, quote, skip, nlines, na.strings, : line 11018 did not have 85 elements but when i open it in excel everything is

Hi All, Is it possible to write a program such that it downloads a csv from a given web address? Would be great if this could be done at a particular time during the day as well. Say 9AM monday-friday. Incase you are curious Im just trying to analyse some stocks data. Thanks, Sachin p.s. sorry about corporate notice --- Please consider the environment before printing this email --- Allianz -

Dear all, I am pretty new to R only having an introduction course, so please bare with me. I am doing my PhD at The Max Planck Institute of Immunobiology where I am analyzing some calorimetry data from some mice. I have a spreadsheet consisting of measurements of the respiratory exchange rate at different time points measured every 9 minutes over some days. My goal is "bin"/average the

Hi all, What would be an efficient way to match rows of a matrix to a vector? ex: m<-matrix(1:9, nrow=3) m [,1] [,2] [,3] [1,] 1 4 7 [2,] 2 5 8 [3,] 3 6 9 ################################# which(m==c(2,5,8)) # I want this to return 2 ###################### Thanks, Sachin [[alternative HTML version deleted]]

Hi all, It seems like I cannot use normal 'if' for data frames. What would be the best way to do the following. if data$col1='high' data$col2='H' else if data$col1='Neutral' data$col2='N' else if data$col='low' data$col2='L' else #chuch a warning? Note that col2 was not an existing column and was newly assigned for this

I am using a similar dataset to the following: a= c("Fruits", "Adam","errorA", "steve", "errorS", "apples", 17.1,2.22, 3.2,1.1, "oranges", 3.1,2.55, 18.1,3.2 ) a_table=data.matrix(t(matrix(a,nrow=5))) I would like to plus minus every second column starting from errorA (using xtable/ hmisc) example output (ignoring