similar to: rearrange command in quantreg package

Dear all, I am trying to estimate the prediction from a fixed effects model and their confidence intervals as well. Though I do not want to include in the prediction and at the confidence intervals the intercept. For that reason I used the argument incl.non.slopes=FALSE. But either if it is TRUE or FALSE it does not have any difference and also the system does not provide any warning. I really

Hi, I am trying to use (i) as an index but R considers it as a function and not as text. To be more specific I would like for example to estimate some regressions named qrnox1, qrnox2, qrnox3,..... and so on. But when I am using qrnox(i) ot qrnox[i] it tries to find the ith element of vector qrnox. The thing is that I want to estimate the qrnoxi regression and not the qrnox(i) function or

Does anyone know how could I get the significant codes from mixed model output fitted with a GEE package? The output I got is the following: GEE: GENERALIZED LINEAR MODELS FOR DEPENDENT DATA gee S-function, version 4.13 modified 98/01/27 (1998) Model: Link: Logit Variance to Mean Relation: Binomial Correlation Structure: Exchangeable Call: gee(formula = bru

Hi, i''m working with a date_select field, and I''ve got the following question. The date_select outputs something that looks like: <select name="widget[designedon(1i)]"> <option value="2001">2001</option> </select> I''m used to using prototype to access form elements, but I seem to be missing something here. I''m

Hello, I am using the following iptables POSTROUTING rule to NAT some RFC 1918 addresses: iptables -t nat -A POSTROUTING -s 192.168.19.23 ! 192.168.0.0/255.255.0.0 -p tcp --dport 80 -j SNAT --to-source 10.32.4.2 (I am using SNAT instead of MASQUERADE for performance reasons). I have several addresses on the 192.168.0.0/16 subnet that I am SNAT''ing similarly. Problem is, ''tc

Hello, Any word on when extended attribute support will be added to OCFS2? What are the impediments to someone implementing this? Alternatively, has anyone implemented a patch to add extended attribute support to OCFS2? I've been watching the open source Lustre fs development, too. I noticed that they have added extended attribute support. However, OCFS2 is more attractive for some

Dear all How can I obtain the data from the function "rearrange" in package quantreg More especifically, based on the example below (available in the help of the rearrange function), how can I access the data generated by "rearrange(zp)" ? data(engel) z <- rq(foodexp ~ income, tau = -1,data =engel) zp <-

hi, it's a nice thing that we've a centos-announce list, but currently the subject of this mails on this list has very long lines. eg: ----------------------------------------- [CentOS-announce] CESA-2006:0160 Moderate CentOS 3 i386 tetex - security update [CentOS-announce] CESA-2006:0140 Important CentOS 3 ia64 kernel - security update ----------------------------------------- which means

Hi All, I am trying to rearrange alphabetically each element in a character vector. ex: say the first element in the vector is "cba", and my goal is to turn it into "abc". The suggested function to use is sort(). But it turns out that sort doesn't work at the level of element. So I am wondering that if there is an alternative function for this purpose. Please help me out .

My question arises when I use levelplot graphics. For example, levelplot(z~x*y|fg) where fg is a factor with three levels of 'a','b','c'. The panels come out in a default order. I would like to rearrange the panels in a manner of 'c','b','a'. I used fg<-ordered(fg, levels=c('c','b','a')) But the panels are still the

Dear R-expert, How to swap and rearrange the row so that I will have Jan-Dec in order? > est31 ??????????? p0 est.alpha est.beta? est.rate Jan? 0.8802867 0.7321440 7.241757 0.1380880 Mar? 0.8598566 0.7096567 7.376367 0.1355681 May? 0.6204301 0.8657272 6.036106 0.1656697 July 0.5032258 0.9928488 4.027408 0.2482986 Aug? 0.5322581 0.9625738 4.103121 0.2437169 Oct? 0.6792115 0.8526226 5.105218

Patches 1 & 2 are fine, ACK. I have a separate comment about patch 4 coming up. In libguestfs we handle optional args by putting them in a separate list (so instead of { args; ret } we have we have { args; optargs; ret }). This gets translated into a language like Python in the natural way. However for C it's translated into a varargs list with a rather complex system of flags, see:

Greetings, I am using rpart for classification with "class" method. The test data is the Indian diabetes data from package mlbench. I fitted a classification tree firstly using the original data, and then exchanged the order of Body mass and Plasma glucose which are the strongest/important variables in the growing phase. The second tree is a little different from the first one. The

Hello, First, ggplot2 is great! Second, sorry for the basic nature of my question. I have data in the form of a melt table like this: Subject Day Ab Variable Value 1 1 Yes A 3 1 3 Yes A 5 1 5 Yes A 7 2 1 No A 2 2 3 No A 4 2 5 No A 6 3 1 Yes A 1 3 3 Yes A 3 3 5 Yes A 5 4 1 No A 4 4 3 No A 6 4 5 No A 8 1 1 Yes B 3 1 3 Yes B 5 1 5 Yes B 7 2 1 No B 2 2 3 No B 4 2 5 No B 6 3 1 Yes B 1 3 3 Yes B 3 3 5

This is an API/ABI break, but we have not yet declared stable API. In order to use optional arguments in languages that support that, any optional arguments must be last. Let's be consistent in this by rearranging the arguments to block_status so that flags is always last. --- generator/generator | 10 ++++++---- interop/dirty-bitmap.c | 6 +++--- lib/rw.c

Dear R users, I need to to the the following. Let a= 1 2 3 4 5 6 and b= -1 -2 -3 be (2x3) matrices. -4 -5 -6 I need to combine the two matrices into a new (2x6) matrix like this: ab = ( 1 -1 2 -2 3 -3 ) 4 -4 5 -5 6 -6 How can this be done in R? ----------------------------------------------------------------- ?????? ???

Dear all: I have this: A1 B1 C1 D1 E1 A2 B2 C2 D2 E2 A3 B3 C3 D3 E3 And I want this A1 E1 B1 E1 C1 E1 D1 E1 A2 E2 B2 E2 C2 E2 D2 E2 A3 E3 B3 E3 C3 E3 D3 E3 Example: m<- matrix(1:15,nrow=3,byrow=T) m v<- unlist(list(t(m[,1:4]))) u<- rep(c(5,10,15),c(4,4,4)) data.frame(v,u) This is the result I want but I would like to learn a simpler way to do it. Any clue?

Dear all, I hope that this question is not too weird, I will try to explain it as good as I can. I have to write a function for a school project and one limitation is that I may not use the in built function sample() At one point in the function I would like to resample/rearrange the items of my sample (so I would want to use sample, but I am not allowed to do so), so I have to come up with sth

Dear R-list, Is there a way to convert the typical long R data-format to a 1-line per subject format? I have data formatted as: Group subj condition variable 1 1 1 746.36625 2 2 1 1076.152857 1 3 1 1076.152857 2 4 1 657.4263636 1 5 1 854.1266667 2 6 1 1191.676154 1 7 1 1028.175385 1 1 2 46.36625 2 2 2 76.152857 1 3 2 76.152857 2 4 2 57.4263636 1 5 2 54.1266667 2 6 2 191.676154 1 7 2 028.175385

------- Forwarded message follows ------- From: Petr Pikal <petr.pikal at precheza.cz> To: Henrik Parn <henrik.parn at bio.ntnu.no> Subject: Re: [R] paired t-test. Need to rearrange data? Date sent: Tue, 08 Aug 2006 16:13:47 +0200 Hi Uff, it takes me a bit headache but this shall do it ?unstack ?table ?t new.list<-unstack(test.data,y~id)