similar to: filter data.frame

Hello everyone, I have versions 2.7.2 and 2.10.1 installed on a machine that has no access to internet. In 2.7.2 I can use ? to get help on functions, which in 2.10.1 that does not work, all I see is "starting httpd help server...done" and then nothing. Have I downloaded 2.10.1 incorrectly (=forgot to tick some box for local help file repository) or is the internet help now the

sorry I had a mistake sending my question without a subject. I do resend again. Please excuse me. > Hello > I have a data array with soil variables (caperf), in which the variable "clay" is factor (as I see entering str(caperf)) . I need to do a regression model, so I need to have arcilla (=clay) as a numeric variable. For that I have entered > >

Dear users, My problem concerns save() within a for loop. Here is my code: for (i in 1:4) { temp <- data.frame(a=(i+1):(i+10), b=LETTERS[(i+1):(i+10)]) filename <- paste("file", i, sep="") assign(filename, temp) save(filename, file=paste(filename, ".rda", sep="")) } As you can see, save() doesn't work as I would like: (1) the object

Hi, I have tried looking at the archives but havent found any answer that works till now (Sorry if i have missed anything) I am a newbie to R and i am trying to carry out hierarchical clustering using hclust -> as.dendrogram and then plotting the results as a dendrogram using the plot function plot(object). My question is : In the function "plot", can one decrease the leaf label

It looks from str(SA) that Response IPS1 is a data.frame of class "anova", which probably cannot be coerced to vector. Maybe you can use unlist() instead of as.vector() Or something like SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even maybe with unlist() Without a better REPRODUCIBLE example, I cannot tell more (maybe some others

Dear All If I have the following dataset V1 V2 x y y x z b a c b j d l c o How do I use R command to get the total number of different letter in column "V1" column "V1" has 7 different letters. Thank you -- View this message in context: http://r.789695.n4.nabble.com/Summing-up-Non-numeric-column-tp3077710p3077710.html Sent from the R help mailing list archive

Hi. In a data set I have a variable that takes values from 1 to 14. For each subgroup of values of this variable, I would like to obtain some descriptive statistics of other variables present in the data set. I've been trying with a "for" loop but I couldn't get nothing. Could you please suggest me some lines? -- View this message in context:

Hey all, I am writing a function in which I will have a matrix of 4 columns and a variable amount of rows. The first to columns will always contain be of the Character type, the third and fourth columns can be a variation of data types, usually characters and integers, but sometimes lists or matrices. At one point the code makes, for each row, a copy of that row, then it makes some adjustments

Dear group, I am trying to write functions, but as a beginner, everything is not so obvious. Let's say I want the results in a list of elemts like this : tot1, tot2, etc Here is a function: toto <- function(x,y) { for(i in x:y){ paste(c("tot",i),collapse="")<-(i*2) } } If I type this : >toto(1,5) I get this message error: Error in paste(c("tot",

Greetings, I am a very novice user with R, and in the course of running a linking procedure : P.old<- function (a, c, b, xi){ #a contains a parameters #c contains c parameters #b contains b parameters #xi is a one column vector containing quadrature points for xi(=theta-gamma)for one item tmp <- a*(xi-b)

Dear users, I have looked on different sources and found different functions to prompt the user to provide input. However, I couldn't find one that does exactly what I'm looking for. select.list() and menu() are nice because a graphic window appears to prompt the user. However, the user can only choose from a predefined list of choices. readline() and scan() are more free in the

Dear users, I would like to process all the lists from all *.rda files that I have in one folder. Up to now, I can load all the *.rda files without any problem. The problem is when I want to access the list saved within each *.rda file (only one list per rda file). Here is my code: fpath <- "D:/R" listnames <- list.files(path=fpath, pattern=glob2rx("*.rda"),

Dear R users, I would like to compare two dataframes, actually their categorical variables (as factors) only (there are 12, from column 1 to 12). The reason I do that is that I got 2 datasets from two different methods and I would like to be sure that each method used the same data (3D images) to extract 2 different sets of 3D parameters. Is it clear so far? So I thought about using

Hi I got an table that contains this colum and i wonder if there is any nice way to extract all rows that contains all dose that start with A02, so all the rows that have A020 and A021 etc etc... | A010 | | A010 | | A010 | | A020 | | A020 | | A020 | | A020 | | A020 | | A021 | | A021 | Thx for your help //Joel -- View this message in context:

There is now a document called "Some hints for the R beginner" whose purpose is to get people up and running with R as quickly as possible. Direct access to it is: http://www.burns-stat.com/pages/Tutor/hints_R_begin.html JRR Tolkien wrote a story (sans hobbits) called 'Leaf by Niggle' that has always resonated with me. I offer you an imperfect, incomplete tree (but my roof is

Hello is there in R any operator that give you all the data of a matrix for example in matlab x(2,3) returns the 2ndth row and 3rdth column x(2,:) returns all the columns of the 2nd row. In R now I would like to print all the  CRagent[[i]][2]  CRagent[[:]][2] doesnot work of course. Other option is to make a loop with an index i that spans from 1:last element of CRagent[[]] but this is not

Dear group, Here is a list : l <- list("100415", "100416", "100419", "100420", "100421", "100422", "100423", "100426", "100427", "100428", "100429", "100430", "100503", "100504", "100505", "100506", "100507",

Dear All, I have a data frame with State and 12 Months as column. I want to convert all the 12 month column from factor to numeric. any help will be greatly appreciated. > str(data) 'data.frame': 33 obs. of 9 variables: $ State : Factor w/ 33 levels "Andaman and Nicobar Islands",..: 1 2 3 4 5 6 7 8 9 10 ... $ April : Factor w/ 21 levels

Dear All, I have a data frame "data" with Jan , Feb as column. I using like this data$Jan to take Jan column. I have the Jan in another variable var1 <- "Jan" data$var1 I need to replace the variable value there . Any help will be greatly appreciated. Thanks & Rg Mohan L [[alternative HTML version deleted]]

Hi all, probably a simple problem for you but I am stuck. This simple function adds columns (with differing length) to data frames: add.col <- function(df, new.col) { n.row <- dim(df)[1] length(new.col) <- n.row cbind(df, new.col) } Now I would like to extend that method. A new parameter 'name' shouild allow people to pass in a name for that new column. Is that possible and