similar to: tapply output

Dieter Menne pointed out that the (small) xml attachment didn't make it. Here is an in-line version (see end of message). Let's hope it works this time. I'm struggling with interpreting XML files created by ADODB as data.frames and I'm looking for advice. Note: This xlm contains a result set which comes from a rectangular data array. I've been trying to play with

Hello, I have an unbalanced panel data set that looks like: ID,YEAR,HEIGHT Tom,2007,65 Tom,2008,66 Mary,2007,45 Mary,2008,50 Harry,2007,62 Harry,2008,62 James,2007,68 Jack,2007,70 Jordan,2008,72 That is, James, Jack, and Jordan are missing a YEAR. Is there any command that will "fill in" the missing YEAR such that the end result will be balanced and look like: ID,YEAR,HEIGHT

I am using R-2.10.1 binary from CRAN on a WinXP Pro system. I also use SAS v9.2 on the same box. I just started using the SAS ODBC driver that comes with version 9 of SAS. I have been able to set up an ODBC source for SAS datasets using the driver, and then with RODBC I am able to read a sample SAS dataset. > library(RODBC) > ch <- odbcConnect('sasodbc', believeNRows=FALSE)

I'm struggling with interpreting XML files created by ADODB as data.frames and I'm looking for advice (see attached example file). Note: This file contains a result set which comes from a rectangular data array. I've been trying to play with parameters to the xmlToDataFrame function in the XML package but I dont get it to extract the data frame. This is what the result should look

Hello, does anyone know how to take the mean for a subset of observations? For example, suppose my data looks like this: OBS NAME SCORE 1 Tom 92 2 Tom 88 3 Tom 56 4 James 85 5 James 75 6 James 32 7 Dawn 56 8 Dawn 91 9 Clara 95 10 Clara 84 Is there a way to get

I want to find the last record for each person_id in a data frame (from a SQL database) ordered by date. Is there a better way than this for loop? for (i in 2:length(history[,1])) { if (history[i, "person_id"] == history[i - 1, "person_id"]) history[i, "order"] = history[i - 1, "order"] + 1 # same person else history[i,

Hi, Does tapply change the order when applied on a factor? Below is the code I tried. > mylevels<-c("IN0020020155","IN0019800021","IN0020020064") >

As an R beginner, I feel brain dead today as I can not find the answer to a relatively simple question. Given a array of string values, for example lets say "mary", "bob", "danny", "sue", and "jane". I am trying to determine how to perform a logical test to determine if a variable is an exact match for one of the string values in the array

Dear R-mates, # Here's what I am trying to do. I have a dataset like this: id = c(rep(1,8), rep(2,8)) dur1 <- c( 17,18,19,18,24,19,24,24 ) est1 <- c( rep(1,5), rep(2,3) ) dur2 <- c(1,1,3,4,8,12,13,14) est2 <- rep(1,8) mydata = data.frame(id, estat=c(est1, est2), durat=c(dur1, dur2)) # I want to one have this: id = c(rep(1,8), rep(2,8))

Hi UserRs, I know that there has to be an easy way to do this in R (probably easy enough that once someone clues me in I'll smack myself on the forehead for not figuring it out myself), but my searches on my own have not yielded any hints. I have many fields in my dataset that participants entered as "free lists" - i.e., the field constitutes a varying number of names each

Hello, I have the following data.frame structure(list(Study = structure(c(1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L, 15L, 16L, 17L, 18L, 19L, 1L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 13L, 14L,

I need to create 100 variable ,whose name is id.1,id.2~~~~id.100 then I need to let a vector say id<-c(id.1,id.2....id.100) any easy way to do this? thanks a lot~ [[alternative HTML version deleted]]

I had occasion recently to read in a one-line *.csv file that looked like: "CandidateName","NSN","Ethnicity","dob","gender" "Smith, Mary Jane",111222333,"E","2/25/1989","F" That "F" (for female) in the last field got transformed to FALSE. Apparently read.csv (and hence read.table) are inferring

Hi, This is my first post; I'm new to R but am a senior statistical programmer. I have done a lot of graphs using SAS Graph but now am trying to transition to using graphs in R. I'm trying to produce a graph where the colors have three categories- ideally I would like them to be Green for good, Yellow for Questionable, and Red for bad. So I tried to do this in GGPLOT; here is my code:

Dear R users, I have a rather knotty analysis problem and I was hoping that someone on this list would be able to help. I was advised to try this list by a colleague who uses R but it is a statistical inquiry not about how to use R. In brief I have a 3x2 anova, 2 tasks under 3 conditions, within subjects. I also took a variety of personality measures that might influence the results under the

I hope this time I'm using the "iris" dataset correctly: ir <- rbind(iris3[,,1], iris3[,,2], iris3[,,3]) lir <- data.frame(log(ir)) names(lir) <- c("a","b","c","d") I'm trying to understand the meaning of expressions like "~ a+b+c+d", used with princomp, e.g. princomp(~ a+b+c+d, data=lir, cor=T) By inspection, it

Hello, It's an alternative to use SAS by function in R? I want to plot d histograms by plot.from example bellow: Thank you! plot d 1 1 16.3 2 1 25.0 3 1 57.8 4 1 17.0 5 2 10.8 13 2 96.4 17 3 76.0 18 3 32.0 19 3 11.0 20 3 11.0 24 3 106.0 25 3 12.5 21 4 19.3 22 4 12.0 26 4 15.0 27 5 99.3 32 7 11.0 36

When Asterisk uses an ISDN interface, it periodically sends to CLI messages such as: == Primary D-Channel on span 1 down [...] == Primary D-Channel on span 1 up Is there a simple programmatic way of capturing them for monitoring purposes? Enzo

Hi I'd like to you know if this is possible to do this with swfdec, or even to know if one day, it will be possible I have a swf player that grabs some piece of sprites, music and move all this in some kind of a cartoon Is it possible with swfdec to record this cartoon into an avi file ? Thanks Enzo ___________________________________________________________________________

I’ve installed R 3.1 with the latest Fedora rpm (R-3.1.0-5.el6.x86_64.rpm) and I run into some issues with openblas. I’ve documented this with an open question on stack overflow here: http://stackoverflow.com/questions/24158372/openblas-r-3-1-and-fedora-centos-dist Basically before 3.1 I had 3.02 and I was able to install and use openblas following the instruction from official CRAN