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Hello, Please I am a learner. My operating system is ubuntus and I am trying to install raster package from R-forge site. I entered sudo apt-get install r-base-dev on the command line and that worked fine. I then typed R at the command line so as to run R. Inside R, I typed > install.packages("raster",repos="http://R-Forge.R-project.org<http://r-forge.r-project.org/>")

Dear List, I am currently running R-2.10.1. I wish to install R-2.13.0 or update my R-2.10.1 to the R-2.13.0. I have downloaded R-2.13.0 but wish to seek your advice before installing that. Please is there a better way of updating to the newer version other than downloading and installing the version? Thanks for your suggestions. Ogbos [[alternative HTML version deleted]]

Dear All, I have a script that draws longitude and latitude of lightning occurrence. This script was running fine before. But when I changed my system and do a fresh install on another laptop, this error persist. source("script") Error in eval(expr, envir, enclos) : could not find function "pointsToRaster" I have tried to see if there is any other package I need to install

Hi, A terrific resource for this type of issue (and pretty much anything related to R) is http://rseek.org/ I'm sure I use it at least daily. Check out ... http://rseek.org/?q=pointsToRaster The first hit is about pointsToRaster() - it has been replaced by raster::rasterize() Cheers, Ben > On Apr 30, 2016, at 4:28 AM, Ogbos Okike <giftedlife2014 at gmail.com> wrote: > >

Dear All, I have just installed a new version of R (Version R-2.11.0) and did install other packages such as raster with ease. However, I could not start the plotting device x11(). I remembered that somewhere at the stage of installation, an error occurred : 'configure: error: --with-x=yes (default) and X11 headers/libs are not available' I tried avoiding this error by using ./configure

Hi everybody, I have a huge longitude and latitude data. I have used raster package to get the since of its global distribution. But I wish to display the information using a few points on the world map. The data is of the form: 95.2156 0.8312 -65.3236 -3.3851 -65.2364 -3.2696 -65.2349 -3.2679 164.7025 -17.6404 148.8214 -4.8285 -67.6568 2.6477 -73.4833 -0.2350 40.9587 -16.8655 -61.6474 8.1179

Hello, I am runing linux on Ubuntus. I find it difficult to install R packages. I am in South Africa. It always asked me to choose the nearest CRAN mirror. I normally choose South Africa and once I clicked Ok, the error message pasted below will appear. Please I am a new student of R and Ubuntus. The other warning "argument 'lib' is missing: using

Dear all, I am trying to add error bars on a boxplot but have encountered an error as indicated below. Is there a package I need to install or a library I have to load before this goes please. Thanks for any idea. Ogbos x<-replicate(20,rnorm(50)) boxplot(x,notch=TRUE,main="Notched boxplot with error bars") error.bars(x,add=TRUE) Error: could not find function "error.bars"

Good day to you all, I have lightning data containing date, time, latitude and longitude. I hope that distribution of latitude and longitude will give number of lightning occurrence in a region. I have used factor function to sum up the number of events on latitude and longitude axis and saved as x and y. But when I tried to plot the two, I had and error message ( Error in image.default(x, y, z) :

Dear Rui, Thanks again for resolving this. I have already started using the version that works for me. But to clarify the second part, please let me paste the what I did and the error message: > set.seed(2024) > data <- data.frame( + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1 days"), 100L, + TRUE), + count = sample(10L, 100L, TRUE) + ) > > # coerce

Hi Everybody, I have a matrix of about 45 columns. Some of the rows contain zeros. Using >data1<-data[complete.cases(data),], I can remove the "NA" rows. But I am unable to tackle that of zeros. Can anybody give me an idea of how to remove rows containing zeros in a matrix. Thanks so much Best Ogbos [[alternative HTML version deleted]]

?s 01:43 de 29/03/2024, Ogbos Okike escreveu: > Dear Rui, > Thanks again for resolving this. I have already started using the version > that works for me. > > But to clarify the second part, please let me paste the what I did and the > error message: > >> set.seed(2024) >> data <- data.frame( > + Date = sample(seq(Sys.Date() - 5, Sys.Date(), by = "1

Greetings to you all. I have two datasets - Time and magnitude. For a particular location, the magnitude of the parameter varies with time. I wish to obtain a polar coordinate distribution of time (0-24h) and magnitudes so as to visualize how magnitude varies with different times of the day (e.g., morning, midnight hours). I have searched for "polar coordinates in R" but could not get

Dear List, I am trying to label a plot with the symbol +/- sigma. Using something like - expression (2*sigma) gives me the symbol 2ó. However, adding +/- to it beats me. The code I am using is: plot(x,y,type="l",main=" expression(paste("±", plain(2*ó)),sep=""). Any suggestion will be appreciated. Best Ogbos [[alternative HTML version deleted]]

Dear Members, Compliments of the Season!! Below is a part of a code I use for Fourier analysis of signals. The code handles data with the format 05 01 01 8628 (year, month, day and count) 05 01 02 8589 (year, month, day and count) The sample data is attached as 2005daily.txt. I would like to adapt the code to handle data of the form: 05 01 01 00 4009

Hi, I am learning how to do principal component analysis in R. However, since I am family with only a few built-in functions like prcomp, sd, cor, I started manually with examples in text books while trying to use the few functions I know to manipulate what they have in the text. From the example in the text I obtained a data set. Using cor and cov, I calculated the correlation and covariance of

Kind Experts, Many thanks for your guide. I have tried to figure out something that can help me plot my own data using the examples you referred me to. I copied part of the code as: set.seed(44) N=500 events <- as.POSIXct("2011-01-01", tz="GMT") + days(floor(365*runif(N))) + hours(floor(24*rnorm(N))) + # using rnorm here

Hi Ogbos, You can just use ISOdate. If you pass more values, it will process them: ISOdate(2018,01,22) [1] "2018-01-22 12:00:00 GMT" > ISOdate(2018,01,22,18,17) [1] "2018-01-22 18:17:00 GMT" Add something like: if(is.null(data$hour),data$hour<-12 then pass data$hour as it will default to the same value as if you hadn't passed it. Jim On Mon, Jan 22, 2018 at 6:01

Good evening to everybody. I have a data of four columns - three of the columns represent date while the fourth is counts. Setting 4000 as my minimum point/value, I wish to find out the number of counts that are less or equal to 4000 and the dates they occur. I have installed pastecs and have been trying to use turnpoints function to do this. I have not been much lucky. I am a still learning. I

Hello, To me as a beginner, every problem looks big. Below is what I was asked to do as part of a code that will solve my problem. I have used read.table to read my data into R and assigned the column names with colnames(dat)<- ... . But to go from txt<-" to the last " at the bottom of the table below is what I am unable to do. Could anybody please tell me how to type or arrive at