similar to: Unix batch to different nodes

Hello help, I have changed around some graphing code and made it into a function. Previously they y label of the axis was inserted as text in its own layout box. text(1,1, expression(~degree~C),cex=1) This worked great and resulted in the symbol for degree. In the function, I have changed it so: text(1,1,paste(b_unit),cex=1) and b_unit<-expression(~degree~C) This now inserts ~degree~C

Hello and thanks for helping. #some data L3 <- LETTERS[1:3] dat1 <- data.frame(cbind(x=1, y=rep(1:3,2), fac=sample(L3, 6, replace=TRUE))) #When x==1 and y==1 I want to replace the 1 values with NA #I can select the rows I want: dat2<-subset(dat1,x==1 & y==1) #replace the 1 with NA dat2$x<-rep(NA,nrow(dat2) dat2$y<-rep(NA,nrow(dat2) #select the other rows and rbind

Hello, I am a bit over my head on this issue. My colleagues and I are running R off of our server. We all have admin rights and prior to yesterday we all had our own libraries. Our main system administrator advised us that we should have a shared library. So, I am trying to do this. I have downloaded the latest version of R and installed it on the main drive of our server in the "Program

Hello, If I have a dataframe: example(data.frame) zz<-c("aa_bb","bb_cc","cc_dd","dd_ee","ee_ff","ff_gg","gg_hh","ii_jj","jj_kk","kk_ll") ddd <- cbind(dd, group = zz) and I want to divide the column named group by the "_", how would I do this? so instead of the first row being x

Hello, I am trying to use R to download a bunch of .csv files such as: http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia I have tried the following and neither work: a<- getURL(" http://biocache.ala.org.au/ws/occurrences/download?q=Banksia+ericifolia") Error in curlPerform(curl = curl, .opts = opts, .encoding = .encoding) : embedded nul in string: and

Hello, I am not sure where to begin with this problem or what to search for in r-help. I just don't know what to call this. If I have 5 columns, the first 2 are the x,y, locations and the last three are variables about those locations. x<-seq(1860,1950,by=10) y<-seq(-290,-200,by=10) ANN<-c(3,0,0,0,1,0,1,1,0,0) CTA<-c(0,1,0,0,0,0,1,0,0,2) GLM<-c(0,0,2,0,0,0,0,1,0,0)

Hello, I am trying to cycle through a csv and make some summary statistics. I need to select rows based on the number in the row name that comes after the letter 'y'. For example, ? BA1y1 would equal 1, ?C3A2r3y1 would equal 1 and ?MA3r3y1r3 would equal 1. I currently have my code ?cycling through by the 5th character but my rows have variable length and the y can occur in several

Hello, I am running R on a server that several people share. Previously we all had separate libraries for R. I have set up R so everyone on the server shares the same library and I downloaded the latest version of R and installed it on the main drive of our server in the "Program Files" folder (obvious enough). I changed the Environmental Variables in the advanced system setting so

Hey All, Two questions. Firstly, what is the difference between create and create! I see that create is document in the api http://api.rubyonrails.org/classes/ActiveRecord/Base.html#M002269 What is the difference between the two of these functions and where is the create! function defined. Also, What are the differences between these two calls? a) SomeModel.create!{ :property_a =>

Dear List, I am making a list of all the files in a folder and I want to exclude one file called "proj.current". This is the 31st file in a folder. Currently I use the command: tdirs <- list.files(pattern="proj.")[-31] However I would like to exclude it based on its name and not the position. Any advice would be useful. Thanks, Daisy Daisy Englert Duursma Room

Hey, I need to get the number of years (as a number) between two dates. Here is what I have as a helper. # Returns the number of years between now and the specified date. def years_ago(date) dateDifference = DateTime.now - date results =Date.day_fraction_to_time(dateDifference) return results[0] / 24 / 365; end I''m sure there is a better way to do this. What is it?

Dear List, I am using the command plot to present the relationship between bird richness (Y axis) and elevation (X axis). However, I would like to observe the distributions of bird richness in different administrative areas (A, B, C, …., G) in this plot. For example, the dots in area A might fall in the upper right part of the plot, while those in area B might appear in the middle of

Hello, I think this is a simple problem but I am not coming up with a simple solution. I think it just an indexing problem. I can easily replace values in a matrix from a dataframe when the dataframe has row and column numbers. In the example below I use row and column names and I can not get it to work #make a matrix where rows and columns are the lat and long for a bounding box of Australia

random selection of cells in raster based on distance from xy locations Hi, I am trying to sample a raster for random cells that occur within a specific distance of point locations. I have successfully found multiple ways of doing this but have memory issues with very large datasets. To overcome this problem I am working with lists. I am now stuck on how to randomlly sample the correct elements

I have recently been learning and trying to develop some application parts using Rails. One issue I may have is that one of the potential clients will want to have one of their external web pages POST to the Rails controller. I tried the naive approach - copy the HTML generated for the Rails controller action for doing the same POST (Create of a domain object). I had this working, or so I

Working through the Users and Authentication of Learning Rails book (great book, code needs to be proof-read in a few cases, though), I came across this: There''s still one leftover that may be worth addressing, depending on your security needs. The authorization? method has secured the data, and the view no longer shows the user options they can''t really use, but if a

Hello, I have two plots on the same screen. I use the command par(mfrow=c(1,2)) in order to do this. When I try to make a legend for both plots, it only puts the legend in the plot on the right side. If I would like a legend that is outside of both of the plots, how would I do this? Thanks [[alternative HTML version deleted]]

Hey guys, I've search a few threads about deleting a value from a vector, but no one has addressed this question so far. I want to delete the last value from a string of values I have: r = [ 1, 2, 3, 4, 5 ], and i want to make r2 = to [ 1, 2, 3, 4] So that r2 is just like r, except that it missing the final value. Thanks, -- View this message in context:

Hi, I want to impute the missing values in my data set multiple times, and then combine the results (like multiple imputation, but manually) to get a mean of the parameter(s) from the multiple imputations. Does anyone know how to do this? I have the following script: y1 <- rnorm(20,0,3) y2 <- rnorm(20,3,3) y3 <- rnorm(20,3,3) y4 <- rnorm(20,6,3) y <- c(y1,y2,y3,y4) x1 <-

i need to send massive emails to various customers, here 2 solutions i have think: 1- customers = Customer.find(:all, :conditions => "newsletter = 1") customers.each do |c| @email = c.email Mailer.deliver_send_newsletter(@subject, @email, @notice_id) end 2- customers = Customer.find(:all, :conditions => "newsletter = 1") customers.each do |c| addresses <<