similar to: compare two matrices

Displaying 20 results from an estimated 2000 matches similar to: "compare two matrices"

2006 Mar 16
3
Did I use "step" function correctly? (Is R's step() function reliable?)
Hi all, I put up an exhaustive model to use R's "step" function: ------------------------ mygam=gam(col1 ~ 1 + col2 + col3 + col4 + col2 ^ 2 + col3 ^ 2 + col4 ^ 2 + col2 ^ 3 + col3 ^ 3 + col4 ^ 3 + s(col2, 1) + s(col3, 1) + s(col4, 1) + s(col2, 2) + s(col3, 2) + s(col4, 2) + s(col2, 3) + s(col3, 3) + s(col4, 3) + s(col2, 4) + s(col3, 4) + s(col4, 4) + s(col2, 5) + s(col3,
2017 Jun 21
4
selecting dataframe columns based on substring of col name(s)
Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) What I haven't been able to suss out is how to efficiently 'extract/manipulate/play with' columns from the data frame, making use
2010 Jul 24
2
union data in column
Is there any function/way to merge/unite the following data GENEID col1 col2 col3 col4 G234064 1 0 0 0 G234064 1 0 0 0 G234064 1 0 0 0 G234064 0 1
2010 Mar 22
1
help needed with boxplot
I am new to R, can anyone help with boxplot for a dataset like: file1 col1 col2 col3 col4 col5 050350005 101 56.625 48.318 RED 051010002 106 50.625 46.990 GREEN 051190007 25 65.875 74.545 BLUE 051191002 246 52.875 57.070 RED 220050004 55 70 80.274 BLUE 220150008 75 67.750 62.749 RED 220170001 77 65.750 54.307 GREEN file2 col1 col2 col3 col4 col5 050350005 101 56.625 57 RED 051010002 106 50.625 77
2010 Oct 11
2
Split rows depending on time frame
Hi, I have the following data frame, where col2 is a startdate and col3 an enddate COL1 COL2 COL3 A 40462 40482 B 40462 40478 The above timeframe of 3 weeks I would like to splits it in weeks like this COL1 COL2 COL3 COL4 A 40462 40468 1 A 40469 40475 1 A 40476 40482 1 B
2017 Jun 21
0
selecting dataframe columns based on substring of col name(s)
> On Jun 21, 2017, at 9:11 AM, Evan Cooch <evan.cooch at gmail.com> wrote: > > Suppose I have the following sort of dataframe, where each column name has a common structure: prefix, followed by a number (for this example, col1, col2, col3 and col4): > > d = data.frame( col1=runif(10), col2=runif(10), col3=runif(10),col4=runif(10)) > > What I haven't been able to
2008 Mar 16
2
How to loop through all the columns in dataframe
Hi: Can anyone advice me on how to loop and perform a calculation through all the columns. here's my data xd<- c(2.2024,2.4216,1.4672,1.4817,1.4957,1.4431,1.5676) pd<- c(0.017046,0.018504,0.012157,0.012253,0.012348,0.011997,0.012825) td<- c(160524,163565,143973,111956,89677,95269,81558) mydf<-data.frame(xd,pd,td) trans<-t(mydf) trans I have these values that I need to
2009 Oct 02
3
help with regexp mass substitution
Hello * i have to rename a lot of variables, and, given that they have regular name constructs, I would like to use regexps. Here's a dump of my head(names(df)) varnames <- c("id.quest", "txt.1.3", "col1.1.3", "col2.1.3", "col3.1.3", "col4.1.3", "col5.1.3", "txt.2.3", "col1.2.3",
2010 Apr 29
2
by funtion
Hello, I have a data.frame: name    col1    col2    col3    col4 AA    23    54    0.999    0.78 BB    123    5    1    0.99 AA    203    98    0.79    0.99 I want to get mean value data.frame in terms of name: name    col1    col2    col3    col4 AA    113.0000  76.0000   0.8945   0.8850 BB    123.00   5.00   1.00   0.99 I tried to use by function: >aa<-by(test[,2:5], feature, mean)
2019 Feb 12
7
Leer un txt a trozos
Estimad en s eRRer en s, Tengo un txt que quiero importar a R. Pero no tiene un formato adecuado para usar cosas normales, como por ejemplo read.csv() El formato es algo así: time 1 col1 col2 col3 col4 dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato dato end time 2 col1 col2 col3 col4 dato dato dato dato dato dato dato dato dato dato dato dato dato
2006 Dec 14
5
Better way to change the name of a column in a dataframe?
Hello R users -- If I have a dataframe such as the following, named "frame" with the columns intended to be named col1 through col6, > frame col1 col2 cmlo3 col4 col5 col6 [1,] 3 10 2 6 5 7 [2,] 6 8 4 10 7 1 [3,] 7 5 1 3 1 8 [4,] 10 6 5 4 9 2 and I want to correct or otherwise change the
2009 Dec 20
2
Remove rows in a matrix that match rows in another matrix
Dear R Community, The following seems like a simple problem, but I''ve been stuck on it for some time, with no luck using matching or subsetting functions. I''m trying to remove the rows from a large matrix that match rows in another large matrix. A (small scale) example: col1<-c("A", "B", "C", "D") col2<-c("A",
2012 Oct 18
4
speeding read.table
R 2.15.1 OS X Colleagues, I am reading a 1 GB file into R using read.table. The file consists of 100 tables, each of which is headed by two lines of characters. The first of these lines is: TABLE NO. 1 The second is a list of column headers. For example: TABLE NO. 1 COL1 COL2 COL3 COL4 COL5 COL6 COL7 COL8 COL9 COL10
2008 Apr 09
1
Replace values according to conditions
Greetings R-users, I have the following data called mydata in a data.frame Col1 Col2 Col3 Col4 Col5 1 2 4 6 7 8 8 7 3 5 4 4 5 6 7 I want to replace the data according to the following conditions Condition 1 if data <= 3, replace with -1 Condition 2 if data >=6, replace with 1 Condition 3 if data = 4 or data =5, replace with 0
2010 Oct 21
2
Adding rows to column
I'm new to R. I'm extracting important columns from single table using following code: File2<-"file.txt" table2<- read.delim(File2, skip=19, sep=";", header=F, na.strings=NA, fill=T) #extracting column 7 where rows match "ID" col1<- table2[grep("ID", table2[,1]),7] #similarly extracting column 9,11,13,15 col2<-
2011 Oct 10
1
Linear programming problem, RGPLK - "no feasible solution".
In my post at https://stat.ethz.ch/pipermail/r-help/2011-October/292019.html I included an undefined term "ej". The problem code should be as follows. It seems like a simple linear programming problem, but for some reason my code is not finding the solution. obj <- c(rep(0,3),1) col1 <-c(1,0,0,1,0,0,1,-2.330078923,0) col2 <-c(0,1,0,0,1,0,1,-2.057855981,0) col3
2011 Aug 25
2
replicate lines of data frame
Greetings! I am just now learning to use R for my dissertation project. I need to manipulate a lot of text and numeric data. I created a data frame that has 7 columns and 127 unique rows. Now I need to replicate each line 6 times and then later change values in the first 2 columns. I am trying to figure out how to accomplish this. I think that I need to use rep(my.df, each=6) but it does
2011 Jan 24
2
how to slice a zoo object
Hi Would anyone have any pointers on how to slice up a large zoo table. I have the following structure: - > str(ZOO_OBJ) ?zoo [1:632, 1:83] 30.4 30.4 30.4 30.4 30.3 ... ?- attr(*, "dimnames")=List of 2 ??..$ : NULL ??..$ : chr [1:83] "COL1" "COL2" "COL3" "COL4" ... ?- attr(*, "index")= POSIXct[1:632], format: "2009-05-01
2018 May 08
2
Dinamic variables in loop
Hello, I am a newbie in R and I have a problem. I want this line: newMyData <-MyData[!(is.na(col1)) | !(is.na(col2)) | !(is.na(col3)) | !( is.na(col4)) | !(is.na(col5)),] write in for loop. The number of col[number] may be different from 3 to 8 Is there any ideas? Thank you Laura [[alternative HTML version deleted]]
2016 Dec 20
2
colnames for data.frame could be greatly improved
Hello, colnames seems to be not optimized well for data.frame. It escapes processing for data.frame in if (is.data.frame(x) && do.NULL) return(names(x)) but only when do.NULL true. This makes huge difference when do.NULL false. Minimal edit to `colnames`: if (is.data.frame(x)) { nm <- names(x) if (do.NULL || !is.null(nm)) return(nm) else