similar to: Adding row name to dataframe

Displaying 20 results from an estimated 8000 matches similar to: "Adding row name to dataframe"

2010 Oct 11
2
(no subject)
Dear List, I am trying to plot date vs. time, but am having problems getting my y-axis labels how I want them.? When left on its own R plots time at 6 hour intervals from 03:00 to 23:00.? I am wanting 6 hour intervals from 2:00 to 22:00.? I realize yaxp doesn't work in plot(), so I am trying to get it to work in par().? However, now I get the ticks where I want them but the time is output
2010 Sep 26
2
Changing x-axis on boxplot
Dear List, ? I am creating a boxplot with two subsets, very similar to the example by Roger Bivand at ?boxplot (reproduced below).? I am trying to change the labels on the x-axis to have one number to cover both subsets.? I can do this in other plots by using axis=FALSE followed by a separate axis() command.? I have also tried variations in the names= argument but can't get it to work.?
2010 Nov 11
1
Count continuous dates
Dear List, I have a series of dates and I am needing to know the greatest length of continuous dates - i.e. the number of dates before a break in the series.? For example, below there are three continuous series of dates with lengths 4, 6, and 8.? How can I count the number of continuous dates?? rle() will do it for constant integers, but I can't figure a way to modify it for continuous
2010 Dec 12
4
legend not appearing in Word document
I need help with using graphics in Word 2007 that will later be converted into a pdf document.? I have tried several formats and found that?I get the best quality of graphics using .wmf, .eps format, but when I convert it to .pdf I get a bunch of lines across the figures.? I also tried .tiff and .png but they give me much lower quality.? The best quality that converts to pdf appears to be
2010 Jul 18
1
Reading files with varying number of columns
Dear R list, I am trying to read files with a varying number of columns and can't figure out how to get them in the proper format.? Some rows have five value and some have seven.? Is there a way to read them in so that two empty columns are added to every row that has only five values?? An example of the data follows.? Thanks!? Tim >46,B,00301,2004-02-03,11:59:16
2010 Oct 12
2
Memory limit problem
Dear List, I am trying to?plot?bathymetry contours around the Hawaiian Islands using the package rgdal and PBSmapping.? I have run into a memory limit when trying to combine two fairly small objects using cbind().? I have increased the memory to 4GB, but am being told I can't allocate a vector of size 240 Kb.? I am running R 2.11.1 on a Dell Optiplex 760 with Windows XP.? I have pasted
2011 Oct 26
1
Using abline in lattice
Dear all, being a relative beginner in R, I apologize for posting the second question within two days. So I want a stacked barchart, which should look like the one produced by this code: Tuvalu <- c(9,3,4,0,3,0,0) Singapor <- c(38,0,0,0,12,19,0) Samoa <- c(26,16,2,0,5,2,0) PNG <- c(56,4,0,5,2,0,56) Micronesia <- c(6,0,0,0,0,0,0) graph4 <-
2010 May 06
2
splitting character strings and converting to numeric vectors
This seemingly should be quite simple but I can't solve it: I have a long character vector of geographic data (data frame column named "XY") whose elements vary in length (from 11 to 14 chars). Each element is structured as a set of digits, then an underscore, then more digits, e.g: > data.frame(head(as.character(XY))) head.as.character.XY.. 1 -448623_854854 2
2005 Apr 11
0
plotting Principle components vs individual variables.
Dear R, I'm trying to plot the first principle component of an analysis vs the first variable but am having trouble. I have no trouble doing the initial plot but have difficulty thereafter. First I want to highlight some points of the following data set list(running) [[1]] X100m X200m X400m X800m X1500m X5K X10K Marathon Argentina 10.39 20.81 46.84 1.81
2005 Apr 11
1
plotting Principal components vs individual variables.
At the cost of breaking the thread I'm going to change your subject and replace 'Principle' by 'Principal'. I just can't stand it any longer... OK, here is how I would solve your other problems. First put > wh <- c("USA", "New Zealand", "Dominican Republic", "Western Samoa", "Cook Islands") > ind
2007 Mar 26
1
Handling Multiple Select Lists
Hi All, After much searching and head scratching I post you this! I can''t seem to find a generic way to handle multiple select data. The function I use to receive form values will only pass the first selected value from a multiple select. I have pasted part of the form and the function below. Thanks for any pointers, Vince // Example selectbox <select
2010 Apr 02
1
Selecting the first row based on a factor
Hello there, I have a situation where I would like to select the first row of a particular factor for a data frame (data example below). So that is, I would like to select the first entry when the factor1 =A and then the first row when factor1=B etc. I have thousands of entries so I need some general way of doing this. I have a minimal example that should illustrate what I am trying to do. I am
2009 Jul 24
3
Duplicated date values aren't duplicates
Dear list, I just had a function (as.ltraj in Adehabitat) give me the following error: "Error in as.ltraj(xy, id, date = da) : non unique dates for a given burst" I checked my dates and got the following: > dupes<-mydata$DateTime[duplicated(mydata$DateTime)] > dupes [1] (07/30/02 00:00:00) (08/06/03 17:45:00) Is there a reason different dates would come up as duplicate
2008 Jul 18
1
manipulate a matrix2
Building upon Jim's answer below (Thanks Jim, that helped a lot), I need to pickup where this thread left off. I'm using Vegan to calculate the Jaccard's Index and the Row.Names and column names are represented in my matrix as seen here. [,3] [,5] [,6] [,9] [,11] [3,] 0 6 11 16 21 [5,] 2 0 12 17 22 [6,] 3 8 0 18 23 [9,] 4 9
2010 Jul 17
2
Plot error
Hi guys, I am a newbie to R, so apologies in advance. I created this simple table in excel, saved in tab delimited .txt: name value_1 value_2 1 bill 1 4 2 ben 2 2 3 jane 3 1 >test <-read.table("\path\to\file", sep="\t", header=TRUE) >x <-c(seq["value_1"]) >y <-c(seq["value_2"])
2003 Jan 21
2
newbie: data frame to vector
Sorry, but I'm very new to R. I'm trying to figure out how to convert a column from a data frame to a vector. More specifically, I have read in a comma separated value table which contains a number of variables in columns, plots in rows... t <- read.table("G:/R/table1.txt", sep=",", header=TRUE) the data comes in just fine. Now I want to do an XY plot of 2
2012 Jun 04
1
Plotting with Rgraphviz
Hi All, After a lengthy battle just to get the package installed, I am not able to actually use Rgraphviz to generate any plots. I tried just using the sample code in the documentation (http://www2.warwick.ac.uk/fac/sci/moac/people/students/peter_cock/r/rgraphviz/) and I get the following: *> > library(Rgraphviz) > test.matrix<-matrix(rep(c(0,1,0,0), 9), ncol=6, nrow=6) >
2012 Nov 17
3
transform input argument (matrix) of function
Dear list!   I would like to write a function to transform matrix, which is input argument of a written function. It is easy with new matrix (see below), but my idea is to transform input argument (matrix) of function without any additional matrixes. Here is an example: fun1 <- function(xy) { xy <- cbind(xy[,1], xy[,2], xy[,1] + xy[,2]) return(xy) }   df1 <- matrix(c(1,2,3,1,2,3), ncol =
2009 Jun 09
3
Splicing factors without losing levels
Hi list! An operation that I often need is splicing two vectors: > splice(1:3, 4:6) [1] 1 4 2 5 3 6 For numeric vectors I use this hack: splice <- function(x, y) { xy <- cbind(x, y) xy <- t(xy) dim(xy) <- length(x) * 2 return(xy) } So far, so good (?). But I also need splicing for factors and I tried this: splice <- function(x, y) { xy <-
2013 May 21
3
add identifier column by row
I want to add identifier column (Date) to a time series data frame. I want to name the "Date" column be from 1 to 30 every 1440 rows. Say I have a data like this (I simply my actual data here): $dat ID Var 1 1 2 4 3 6 4 7 5 7 6 8 How can I add identifier column (Date) from 1 to 3 every 2 rows and have output like this: ID