similar to: Quick GREP challenge

Hi All, I have a character vector with naems of cities in the us. I need to extract the number that appear after the word "New York", for example, x<-c("P Los Angeles44AZ", "P New York722AZ", "K New York20") I want the results to be 722, 20 cab I use the grep function, if so how? I appreciate your help, thanks, -- View this message in context:

I have had some comments on sqldf regarding its dependence on tcltk such as the second last sentence on this blog post: http://translate.google.com/translate?hl=en&sl=zh-CN&u=http://www.wentrue.net/blog/%3Fp%3D453&prev=http://blogsearch.google.com/blogsearch%3Fhl%3Den%26ie%3DUTF-8%26q%3Dsqldf%26lr%3D%26sa%3DN%26start%3D10 sqldf does not directly use tcltk but it does use strapply in

Are there packages that allow improved String and URL processing? E.g. extract parts of a URLs such as sub-domains, top-level domain, protocols (e.g. https, http, ftp), file type based on endings, check if a URL is valid or not, etc... I am currently only using split and paste. Are there better and more efficient ways to handle strings e.g. finding sub-strings or to do pattern matching? What

Hello, I just don't get this and would appreciate if someone could write a line or two: I'm trying to build this package and it stops installing after I add the following to the NAMESPACES file: >importFrom(gsubfn,strapply) The error during the package test is: Error in MyPackage::MyFunction : package 'MyPackage' has no name space and is not on the search path Calls:

Hello; I am a R newbie and would like to know correct and efficient method for doing string replacement. I have a large data set, where I want to replace character "M", "b", and "K" (currency in Million, Billion and K) to millions. That is 209.7B with (209.7 * 10e6) and 100.00K with (100.00 *1/100) and etc.. d <- c("120.0M", "11.01m",

I have a string such as fileName<-"Agg.20.20.20-all-01". All I want to do is pull the "20.20.20" and the "all" as strings. Obviously, they aren't always those values. The "20.20.20" can be "30.30.30" but it's always after the . which is next to the second g in Agg and it's always the same length. The all might not always be

I have a matching problem that I cant solve. mystring = "xxx{XX}yy{YYY}zzz{Z}" where "x","X","y","Y","z","Z" basiclly can be anything, letters, digits etc. I'm only interested in the content within each "{}". I am close but not really there yet. library(gsubfn) strapply(mystring,"\\{[^\\}]+",, perl=F)

I have a data.frame as the following: var1 var2 9G/G09 abd89C/T90 10A/T9 32C/C 90G/G A/A . . . . . . 10T/C 00G/G90 What I want is to get the letters which are on the left and right of '/'. for example, for "9G/G09", I only want "G", "G", and for "abd89C/T90", I only want "C" and

Given a text like I want to be able to extract a matched regular expression from a piece of text. this apparently works, but is pretty ugly # some html test<-"</tr><tr><th>88958</th><th>Abcdsef</th><th>67.8S</th><th>68.9\nW</th><th>26m</th>" # a pattern to extract 5 digits > pattern<-"[0-9]{5}" #

Hi all, Does anyone have a version of strsplit that keeps the string that is split by. e.g. from x <- "A: 123 B: 456 C: 678" I'd like to get c("A:", "123 ", "B: ", "456 ", "C: ", 678) but strsplit(x, "[A-Z]+:") gives me c("", " 123 ", " 456 ", " 678") Any ideas? Thanks,

Dear R guru: If I got a variable aaa<- "up.6.11(16)" how can I extract 16 out of the bracket? I could use substr, e.g. substr(aaa, start=1, stop=2) [1] "up" But it needs start and stop, what if my start or stop is not fixed, I just want the number inside the bracket, how can I achieve this? Many thanks yan

Hi R, A quick question: How do we find the number of words in a string? Example: C="Have a nice day" And the number of words should be 4. any built in function or?... Thanks, Shubha Shubha Karanth | Amba Research Ph +91 80 3980 8031 | Mob +91 94 4886 4510 Bangalore * Colombo * London * New York * San José * Singapore * www.ambaresearch.com This e-mail may contain

Hi, this should be an easy one, but I can't figure it out. I have a vector of tests, with their units between brackets (if they have units). eg tests <- c("pH", "Assay (%)", "Impurity A(%)", "content (mg/ml)") Now I would like to hava a function where I use a test as input, and which returns the units like: f <- function (x) sub("\\)",

Hi again, how to elegantly split s <- "ABCDEFGT(P)HIJK" into "A" "B" "C" "D" "E" "F" "G" "T(P)" "H" "I" "J" "K" (independently of which letters 'T' or 'P' actually represent ...). Please jumstart my regexing, Joh

Hi List, I've got a count matrix like this: [-11.9,-11] (-11,-10.2] (-10.2,-9.3] (-9.3,-8.44] [-11.9,-10.6] 0 0 0 0 (-10.6,-9.3] 0 0 0 0 (-9.3,-8.01] 0 0 0 0 (-8.01,-6.73] 0 0 0 0 I want to

Hi, sorry if it is a too stupid question, but how do I a string search in R: I have a dataframe A with A$test like: test1 bcdtestblabla2.1bla cdtestblablabla3.88blabla and I want to search for string that start with 'dtest' and ends with number and return the location of that substring and the number, so the end result would be: NA NA 3 2.1 2 3.88 I find grep can

Dear all, I have a data.frame with a column like the x shown below myDF<-data.frame(cbind(x=c("[[1, 0, 0], [0, 1]]", "[[1, 1, 0], [0, 1]]","[[1, 0, 0], [1, 1]]", "[[0, 0, 1], [0, 1]]"))) > myDF x 1 [[1, 0, 0], [0, 1]] 2 [[1, 1, 0], [0, 1]] 3 [[1, 0, 0], [1, 1]] 4 [[0, 0, 1], [0, 1]] As you can see my x column is composed of

... sorry for reposting this in a more appropriate forum than r.general ... Hello, I just don't get this and would appreciate if someone could write a line or two: I'm trying to build this package and it stops installing after I add the following to the NAMESPACES file: >importFrom(gsubfn,strapply) The error during the package test is: Error in MyPackage::MyFunction : package

Hello, Anyone knows how can I do this in a cleaner way? mynumber = 1001 as.numeric(unlist(strsplit(as.character(mynumber),""))) [1] 1 0 0 1 Thanks in advance, Gustavo

Dear list, I'm seeking advice to extract some numeric values from a log file created by an external program. Consider the following example, input <- readLines(textConnection( "some text <ax> = 1.3770E-03 <bx> = 3.4644E-07 <ay> = 1.9412E-04 <by> = 4.8840E-08 other text <aax> = 1.3770E-03 <bbx> = 3.4644E-07