similar to: multiple assignments ?

Try factor(vec2) in your bwplot() call. -----Original Message----- From: r-help-bounces at stat.math.ethz.ch [mailto:r-help-bounces at stat.math.ethz.ch]On Behalf Of Ernesto Jardim Sent: Friday, July 09, 2004 9:41 AM To: Mailing List R Subject: [R] Problem with bwplot Hi, I'm ploting some box-and-whisker plots with bwplot but I'm not getting any box-and-whiskers ... just dots.

Hello, I'm writing a piece of code where I need to compare multiple same length vectors. I've gone through the basic functions like identical() or all(), but they only work for comparing 2 vectors. From 3 vectors on, it doesn't work . Example: Assuming vec1 <- c (1,2,3,4,5) vec2 <- c(1,2,3,4,5) vec3 <- c(1,2,3,4,4) identical (vec1,vec2,vec3) returns TRUE, since the 2

Hi, there I'm currently trying to figure out how to keep my "factor" levels for a variable when moving it from one data frame or matrix to another. Example below: vec1<-(rep("10",5)) vec2<-(rep("30",5)) vec3<-(rep("80",5)) vecs<-c(vec1, vec2, vec3) resp<-rnorm(2,15) dat<-as.data.frame(cbind(resp, vecs))

Hi all, I’ve narrowed down a problem in my code to the following test case: - - - - typedef struct {float v[2];} vec2; typedef struct {float v[3];} vec3; vec2 getVec2(); vec3 getVec3() { vec2 myVec = getVec2(); vec3 res; res.v[0] = myVec.v[0]; res.v[1] = myVec.v[1]; res.v[2] = 1; return res; } - - - - Compiling this with any level of optimization for arm64 gives incorrect code,

Dear all, Without a loop, I would like transform 3 numeric vectors empty of 0/1 of same length Vec1 : transform 1 to A and 0 to "" Vec2 : transform 1 to B and 0 to "" Vec3 : transform 1 to C and 0 to "" to obtain only 1 vector Vec who is the paste of the 3 vectors (Ex : ABC, BC, AC, AB,...) Any idea ? Thank you for your help -- Michel ARNAUD

Help-Rs,   I've got three vectors representing participants:   vec1 <- c(4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81) vec2 <- c (1,2,3,4,5,6,7,8,9,10,11,12,44,45,46,47,48,49,50,51,52,53,54,55,56,57,58,59,60,61,62,63,64,65,66) vec3 <- c (1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,52)   I'd

Thanks Bruce. > On 4 May 2015, at 13:18, Bruce Hoult <bruce at hoult.org> wrote: > > I can confirm that, with Apple LLVM version 6.0 (clang-600.0.56) (based on LLVM 3.5svn) > > Very strange! Yes, that’s what I thought. I’ve also checked the binary downloads for OS X from llvm.org <http://llvm.org/> and get the same broken code from both the 3.5.2 and 3.6.0 releases.

Hello R specialists, I have a base vector called vBase with 102 elements. I have another vector vec1 which elements are only part of vBase but is shorter. I transform vec1 so I get a vector with the same size as vBase and with each common element on the same indexed row. If a value is missing in vec1 then I put a Na like this: vec1 vBase Amsterdam Amsterdam Na

I would like to know whether there is a faster way to do the below operation (updating vec1). My objective is to update the elements of a vector (vec1), where a particular element i is dependent on the previous one. I need to do this on vectors that are 1 million or longer and need to repeat that process several hundred times. The for loop works but is slow. If there is a faster way, please let

I want to create a number of vectors like : vec1 <- rnorm(1) vec2 <- rnorm(2) vec3 <- rnorm(3) and so on........... Here I tried following : for (i in 1:10) paste("vec", i, sep="") <- rnorm(i) However obviously that is not working. Here vectors I need to be seperated i.e I do not want to create a "list". How to modify above code? -- View this

Thanks. Yes. Your approach can identify: Glaxy ace S 5830 and S 5830 Glaxy ace But you can not identify using same program: Iphone 4S 16 G Iphone 4S 16G How should I solve both in same time. Kind regards,Tammy [[alternative HTML version deleted]]

I have the following question, which is elementary but I am unable to answer. In a for(i=10) loop, I am trying to represent the 10 1-dimensional vectors l1, l2,... l10 by some expression that will run through these values. ie. soppose I want to add l1 + ... + l10 I could go x <- 0 for(i in 1:10){ x <- x+ l(i)} This should return x to be the sum of the 10 li's for i from 1 to 10

Hi, May be this helps: m1<- as.matrix(read.table(text=" y1 g24 y1 0 1 g24 1 0 ",sep="",header=TRUE)) m2<-as.matrix(read.table(text="y1 c1 c2 l17 ?y1 0 1 1 1 ?c1 1 0 1 1 ?c2 1 1 0 1 ?l17 1 1 1 0",sep="",header=TRUE)) m3<- as.matrix(read.table(text="y1 h4??? s2???? s30 ?y1 0 1 1 1 ?h4 1 0 1 1 ?s2 1 1 0 1 ?s30 1 1 1

This can be vectorized. Try ix <- seq_along(vec2) S_diff2 <- sapply(seq_len(N1-(N2-1)*ratio_sampling), \(j) sum((vec1[(ix-1)*ratio_sampling+j] - vec2[ix])**2)) On Sun, Jun 16, 2024 at 11:27?AM Laurent Rhelp <laurentRHelp at free.fr> wrote: > > Dear RHelp-list, > > I try to use the package comprehenr to replace a for loop by a list > comprehension. > > I

Dear R-helpers: I have a question related to using do.call to call cbind and get. #the following works vec1 <- c(1,2) vec2 <- c(3,4) ColNameVec <- c('vec1','vec2') mat <- do.call("cbind",lapply(ColNameVec,get)) mat #put code above into a function then it does not work #before doing so, first remove vec1 and vec2 from global environment rm(vec1,vec2) test

Hello. Sorry I am not sure this question should go to llvm or mesa3d-dev mailing list, so I post it to both. I am writing a llvm backend for a modern graphics processor which has a ISA very similar to that of Direct 3D. I am reading the code in Gallium-3D driver in a mesa3d branch, which converts the shader programs (TGSI tokens) to LLVM IR. For the shader instruction also found in LLVM IR,

Dear RHelp-list, ?? I try to use the package comprehenr to replace a for loop by a list comprehension. ?I wrote the code but I certainly miss something because it is very slower compared to the for loops. May you please explain to me why the list comprehension is slower in my case. Here is my example. I do the calculation of the square difference between the values of two vectors vec1 and

Is there any built-in way to lexicographically compare two vectors of the same length in R? The textbook algorithm could be coded as follows: lex.cmp <- function (vec1,vec2) { for (j in 1:length(vec1)) { if (vec1[j] < vec2[j]) { return(-1) } if (vec1[j] > vec2[j]) { return(1) } } return(0) } Thanks, Gabriel

I would be more strong on this advice: learn to think in R, rather than thinking in Python, when programming in R. R has atomic vectors... Python does not (until you import a package that implements them). I find that while it is possible to import R thinking into Python, Python programmers seem to object for stylistic reasons even though such thinking speeds up Python also. A key step in that

Laurent, Thank you for introducing me to a package I did not know existed as I use features like list comprehension in python all the time and could see using it in R now that I know it is available. As to why you see your example as slow, I see you used a fairly complex and nested expression and wonder if it was a better way to go. As you are dealing with an interpreter doing delayed