similar to: Plotting multiple histograms on same panel

Displaying 20 results from an estimated 9000 matches similar to: "Plotting multiple histograms on same panel"

2012 Jun 27
1
lattice histogram log and non log values
Hello all, Please consider the following library(lattice) Colors. <-rep(brewer.pal(7, "Dark2"),2) color <- 1 Data.X.. <- data.frame(UnitArea = c(rnorm(1000), rnorm(1000)), Type = c(rep("Base",1000),rep("Log",1000))) histogram( ~ UnitArea | Type, data = Data.X.., xlab = "Unit Area", type = "density", panel =
2012 Feb 06
5
I bet apply has a solution
Hi all For the data below, I would like to return a logical value indicating differences in the data. #Create data Data..<-data.frame(a=rep(1,10),b=c(rep(1,9),2),c=c(rep(1,8),2,2)) a b c 1 1 1 1 2 1 1 1 3 1 1 1 4 1 1 1 5 1 1 1 6 1 1 1 7 1 1 1 8 1 1 1 9 1 1 2 10 1 2 2 So what I want is to return logical value telling me if all the values are the same. So the result would be a b
2012 Oct 11
3
Sorting a data frame by specifying a vector
Hello all, I cannot seem to figure out this seemingly simple procedure. I want to sort a data frame by a specified character vector. So for : df.. <- data.frame(Season=rep(c("Summer","Fall","Winter","Spring"),4),Obs= runif(length(rep(c("Summer","Fall","Winter","Spring"),4)))) I want to sort the data frame
2011 Dec 06
2
To Try or to TryCatch, I have tried to long
So after about 4 hours struggling with Try and TryCatch I am throwing in the towel. I have a more complicated function that used logspline through iterative distributions and at some point the logspline doesnt function correctly for some subsets but is fine with others so I need to be able to identify when the error occurs and stop curtailing the distribution and I think this Try or TryCatch
2010 Nov 29
3
List elements of NULL to value
Hi everyone, I am posting this because i know its easy and i cant for the life of me figure out how to do it though i have tried and through a ridiculously complex loop made it happen. I need to convert some list elements of NULL value to 0s so they mesh with my data frame properly. So for A<-list(1,NULL) returns [[1]] [1] 1 [[2]] NULL Would instead return [[1]] [1] 1 [[2]] [1] 0
2010 Jan 12
5
Drop last numeral
Hello all, Frustrated and i know you can help I need to drop the last numeral of each of my values in my data set. So for the following i have tried the ?substring but since i have to specify the length, but because my data are of varying lengths it doenst work so well Data<-c("1131", "1132", "1731" ,"1732" ,"1821" ,"1822",
2010 Oct 28
4
Alter character attribute
Hi everyone I have some records that include a date attribute for the date and time but i need to separate the data and analyze it separately in GIS by Month and Year, so i need to pull these attributes out and create their own attribute field. So the input: RawData2.. returns ID period_end_date 1 22 9/10/2007 0:00:00 2 44 2/2/2006 0:00:00 and i need to get ID period_end_date
2010 Jan 25
3
Issue using tapply
Hello all, I am trying to use the tapply function to sum some values and change the column names of the resulting vector. I input Emp Et 1 10565 ACC 2 7515 ADM 3 625 AGF 4 6243 CNS 5 12721 EDU 6 3924 FIN 7 18140 HLH 8 3686 INF 9 15841 MFG 10 243 MIN 11 1864 MNG 12 4664 OSV 13 5496 PRF 14 4988 PUB 15 2166 REC 16 2153 REL 17 16082 RTL 18 3582 TRN 19 757 UTL 20
2011 Dec 01
2
Summarizing elements of a list
Hi everyone, I looked around the list for a while but couldn't find a solution to my problem. I am storing some results to a simulation in a list and for each element i have two separate vectors(is that what they are called, correct my vocab if necessary). See below Version1_<-list() for(i in 1:5){ Version1_[[i]]<-list(First=rnorm(1),Second=rnorm(1)) } What I want is to put all
2011 Sep 01
3
Oh apply functions, how you confuse me
Hi guys, I have a crap load of data to parse and have enjoyed creating a script that takes this data and creates a number of useful graphics for our area. I am unable to figure out one summary though and its all cause I dont fully understand the apply family of functions. Consider the following: #Create data
2010 Jun 03
2
Subsetting for unwanted values
Hi all, I have toyed with this for too long today and in the past i used multiple lines of code to get at what i want. Consider the following: All i need to do is subset Pc to the values that do not equal Pc.X. The first attempt doesnt work because i have unequal lengths. The second attempt doesnt give me an the right answer.
2010 Mar 04
2
Removing colon from numerical data
Basic question, looked through the forum and documentation but didnt see a solution. So consider O<-c(1:20) D<-c("1:","2:","3:","4:","5:","6:","7:","8:","9:","10:","11:","12:","13:","14:","15:","16:",
2011 Jan 07
2
Dont show zero values in line graph
Hey everyone, Im getting better at plotting my data but cant for the life of me figure out how to show a line graph with missing data that doesnt continue the line down to zero then back up to the remaining values. Consider the following x<-c(1:5,0,0,8:10) y<-1:10 plot(0,0,xlim=c(0,10), ylim=c(0,10),type="n",main="Dont show the bloody 0 values!!") lines(x~y,
2010 Mar 10
1
trouble getting multinimial logit model to work properly
Greetings all, please consider the following data: #Build Data frame Slope<-c(1.291370, 12.208500, 2.110930, 0.578990, 5.019520, 0.807444, 0.554079 , 1.257080, 0.241504 , 0.184337 , 0.383044 , 0.342021) Exposure<-c(790.54, 1167.79 , 845.58 , 1082.47 , 1189.61 , 677.17 , 2058.56 , 469.09 , 112.02 , 803.31 , 254.14 ,1336.16) FwyDist<-c(11809.4222 ,10623.0458, 12279.6271,
2010 Sep 13
1
Transforming character vector
Hi guys, Cant seem to find a solution for this. I am looking for a substitute for cut that can transform character vectors. So as cut would be used below to transform YearCat-> YearCat2 base on Year and vector Ag<-c("00-'70","'71-'75","'76-'85","'86-'09") using 'cut '
2010 Oct 26
1
Cut including the 0 value as separate bin
Hi everyone, I have been using R too long to have to ask this but here i am. How do i create a separate bin for the 0 value? So for: #Create data frame DF<-data.frame(A=0:20) #Create label vector labs<-1:6 #Create buckets and label DF$Cut<-cut(DF$A,c(0,4,8,12,14,16,20),labels=labs,include.lowest=TRUE) I want the 0(zero) value to be in a separate bin. Sorry for the lame post...
2010 Feb 23
1
select row based on highest value
Please consider the following #Data to use Props<-c("p754921","p754921" ,"p754921","p75506" ,"p75506" ,"p75506","p75506","p75508","p75508","p75508","p75508","p75508") TAZ<-c(38,37,37,171,171,282,171,46,46,169,169,169) Area<-c(109828.04, 128134.71, 46469.57,
2010 Jun 07
1
Transforming list to data frame with corresponding columns
Hi all, Consider the following. a<-list(c("MHsub","MHsub","SFD","Duplex")) b<-list(c("MHsub","MHsub","SFD")) c<-list(c("MHpark","SFD","SFD")) d<-list(c("MultiFam","MultiFam","MultiFam","Duplex")) all<-list(a,b,c,d)
2012 Nov 29
1
Coerce rownames to factor for ordering
Hi all, I think this might be an easy one but I cannot think of a way to do this other than what I am currently attempting. I simply want to sort my data frame's rownames by a defined vector so that the plots I generate from that vector are in the desired order Consider the test data below: #Create test data DataToPlot.. <- data.frame("Location1" =
2012 Jun 20
2
Using object as literal value in list vector
Hello all , This is a pretty simple question I think but cannot find an answer on the list or in my brain. I would like to iterate through a loop and use a vector of strings to name a number of list elements. For instance #Create vector of strings Et<- c("ACC","RTL","WHL") MeanValues_ <- list("ACC" = 1000, "RTL" = 2000,