Displaying 20 results from an estimated 40000 matches similar to: "sample() question"
2008 Aug 28
2
sample consecutive integers efficiently
Hi all,
I have some rough code to sample consecutive integers with length
according to a vector of lengths
#sample space (representing positions)
pos<-c(1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20)
#sample lengths
lengths<-c(2,3,2)
From these two vectors I need a vector of sampled positions.
the sampling is without replacement, making things tough as the sampled
integers need
2006 Mar 23
3
Sampling in R
Hi all!
I was wondering if you can help me with a little sampling issue I'm
having in R.
I have a database with 100 observations.
I need to sample n=9 sample size, 200 times (i.e. get 200 samples of
size 9).
N (pop. size) =100
Each sample can't contain the same observation more than one time
(i.e. the program needs to check if the obs. has already been sampled
into the sample -
2006 Jul 04
2
random sampling problems?
Dear friends,
suppose my dataset is the following data:
id<-1:9
x<-c(1,2,3,1,2,3,1,2,3)
y<-c(1,1,1,2,2,2,3,3,3)
data<-data.frame(id,x,y)
id x y
1 1 1 1
2 2 2 1
3 3 3 1
4 4 1 2
5 5 2 2
6 6 3 2
7 7 1 3
8 8 2 3
9 9 3 3
i want to do sampling like this:say the sample size is 3.
First: random sampling from x;
Next ,random sampling from
2006 Oct 19
4
Question about random sampling in R
Hi,
I looked up the help file on sample(), but didn't find the info I was
looking for.
When sample() is used to resample from a distribution, e.g., bootstrap, how
does it do it? Does it use an uniform distribution, e.g., runif(), or
something else? And, when the help file says:"sample(x) generates a random
permutation of the elements of x (or 1:x)", would I be correct if I
2011 Oct 08
2
Permutation or Bootstrap to obtain p-value for one sample
Hi,
I am having trouble understanding how to approach a simulation:
I have a sample of n=250 from a population of N=2,000 individuals, and I
would like to use either permutation test or bootstrap to test whether this
particular sample is significantly different from the values of any other
random samples of the same population. I thought I needed to take random
samples (but I am not sure how
2009 Dec 21
3
Question About Repeat Random Sampling from a Data Frame
Good Morning:
I've read many, many posts on the r-help system and I feel compelled to quickly admit that I am relatively new to R, I do have several reference books around me, but I cannot count myself among the fortunate who seem to strong programming intuition.
I have a data set consisting of 1637 observations of five variables: tensile strength, yield strength, elongation, hardness and a
2010 Sep 25
2
OT: What distribution is this?
Hi
This is OT, but I need it for my simulation in R.
I have a special case for sampling with replacement: instead of sampling
once and replacing it immediately, I sample n times, and then replace all n
items.
So:
N entities
x samples with replacement
each sample consists of n sub-samples WITHOUT replacement, which are all
replaced before the next sample is drawn
My question is: which
2017 Aug 05
2
Nested for loop
Hi! Thanks for taking the time to read this.
The code below creates a graph that takes 100 samples that are between 5%
and 15% of the population (400).
What I'd like to do, however, is add two other sections to the graph. It
would look something like this:
from 1-100 samples take 100 samples that are between 5% and 15% of the
population (400). From 101-200 take 100 samples that are between
2010 May 22
3
How sample without replacement on more than one variables?
Hello All,
sample() only sample on one variable x. But I'm interested in sampling
more than one variable without replacement.
Suppose I have 3 vectors x, y, z. I want to draw samples from all
three vectors such that the combination of the three elements in each
draw is not the same as any previous draws. I could use expand.grid to
generate a vector out of the three vectors. But when the
2009 May 28
2
Bug in base function sample ( ) (PR#13727)
Full_Name: Michael Chajewski
Version: 2.9.0
OS: Windows XP
Submission from: (NULL) (150.108.71.185)
I was programming a routine which kept reducing the array from which a random
sample was taken, resulting in a single number. I discovered that when R
attempts to sample from an object with only one number it does not
reproduce/report the number but instead chooses a random number between 1 and
2017 Aug 06
0
Nested for loop
Hi Kirsten,
I can run your example code but I can't quite follow your division of sampling. Can you restate the the task? Below is what I think you are asking for, but I have the feeling I may be off the mark.
Set A: 400 samples, draw 100 in range of 5 to 15
Set B: 800 samples, draw 100 in range of 5 to 15
Set C: 300 samples, draw 100 in range of 5 to 15
Ben
> On Aug 5, 2017, at
2017 Aug 06
1
Nested for loop
Hi Ben,
That's exactly right! Except for each set it's the sample population that
is 400, 800 or 300. I want to take 3 samples, each of 100, where only the
population differs. I can do this separately, but I'm having trouble
putting them all on the same graph.
I'd like to have sample on the x axis (1-300) and estimate on the y axis. I
want to show how population affects the
2007 Oct 31
2
survey weights in sample with replacement
>> Hi,
I am trying to draw a random sample from an household survey with sample weight. Is there any function in R or Splus which allows this.
Regards,
*******************************************************
Mehtabul Azam
Department of Economics
Southern Methodist University
Dallas TX 75275-0496
Tel: (214) 214 938 3906
Email: mazam at smu.edu <mailto:mazam at smu.edu>
2005 Jun 16
1
Survey - Cluster Sampling
Dear WizaRds,
I am struggling to compute correctly a cluster sampling design. I want
to do one stage clustering with different parametric changes:
Let M be the total number of clusters in the population, and m the
number sampled. Let N be the total of elements in the population and n
the number sampled. y are the values sampled. This is my example data:
clus1 <-
2010 Nov 15
5
Sampling problem
Hey,
I am hoping someone can help me with a sampling question.
I have a data frame of 8 variables (the first column is the subjects' id):
SubID CSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 6 5 6 2 6 2 2 4
2 6 4 7 2 6 6 2 3
3 5 5 5 5 5 5
2011 Mar 09
2
Complex sampling?
R users,
I am trying to generate a randomized weekday survey schedule that ensures even coverage of weekdays in
the sample, where the distribution of variable DOW is random with respect to WEEK. To accomplish this I need
to randomly sample without replacement two weekdays per week for each of 27 weeks (only 5 are shown). However,
I need to sample from a sequence (3:7) that needs to be
2007 Apr 27
2
proportional sampling
Dear All,
I wonder if you could help me.
I have a table with a series of sites that I would like to sample from.
The table has 5 columns:
ID
X Coordinate
Y Coordinate
Value
Factor
The conditions are that each site can be selected more than once and the
probability of it being selected (or sampled) is proportional to a factor
located in column 'Factor'
I am novice in terms of R, and
2012 Jan 29
2
Drawing sample
Dear all, here I need to draw all possible samples of size 2, from a population, which is characterized by c(1,4,56, 3). Sampling will be done with replacement. Is there any direct R function to faciliate this darwing?
?
Thanks for your help
2011 Mar 07
3
generate 3 distinct random samples without replacement
Hello:
I wonder if I could get a little help with random sampling in R.
I have a vector of length 7375. I would like to draw 3 distinct random samples, each of length 100 without replacement. I have tried the following:
d1 <- 1:7375
set.seed(7)
i <- sample(d1, 100, replace=F)
s1 <- sort(d1[i])
s1
d2 <- d1[-i]
set.seed(77)
j <- sample(d2, 100, replace=F)
s2 <- sort(d2[j])
2009 Jul 23
5
Random # generator accuracy
Dan Nordlund wrote:
"It would be necessary to see the code for your 'brief test' before anyone
could meaningfully comment on your results. But your results for a single
test could have been a valid "random" result."
I've re-created what I did below. The problem appears to be with the
weighting process: the unweighted sample came out much closer to the actual