similar to: Different way of aggregating

Hello Where could I find examples on how to work with the time index in a timeseries or zoo series? Let say I've got this series DATA 1990-01-01 10:00:00 0.900 1990-01-01 10:01:00 0.910 1990-01-01 10:03:00 0.905 1990-01-01 10:04:00 0.905 1990-01-01 10:05:00 0.890 ....................... 2000-12-31 20:00:00 0.992 How do I make simple calculations such as ... ? Calculate the

down vote favorite Hello I have a zoo series. It lasts 10 years and its frequency is 15min. I'd like to get a new zoo series (or vector) with the same number of elements, whith each element equal to the first element of the day. That's, The first element everyday is repeated throughout the wole day. This is not same as aggregate(originalseries,as.Date,head,1) because this gives a

Hello, I am trying to find a direct way to write a nested if of sorts to find data for a specific time range for a specific day (across a range of days) and have exhausted my abilities with the manuals I have at hand. I have a good deal of data of this approximate form: day time price 1 1am 5 1 2am 7 1 3am 9 1 4am 12 2 1am 5 2 2am 7 2

Hello How can I select several not continuous rows ? If I wanted to select rows 1 to 7 I'll write mydata[,1:7] But what if I need to select rows 1 to 5 and 10 to 15? -- View this message in context: http://r.789695.n4.nabble.com/How-to-select-not-continous-rows-tp3003840p3003840.html Sent from the R help mailing list archive at Nabble.com.

Hello Imagine I have a vector with ones and zeroes I write it compactly: 1111111100001111111111110000000001111111111100101 I need to get a new vector replacing the "N" ones following the zeroes to new zeroes. For example for N = 3 1111111100001111111111110000000001111111111100101 becomes 1111111100000001111111110000000000001111111100000 I can do it with a for loop but I've read

Hello What's the differente betwen using "plot" and using "print" in order to plot a graph? For example in order to plot the result of a histogram. cheers -- View this message in context: http://r.789695.n4.nabble.com/plot-vs-print-tp3045256p3045256.html Sent from the R help mailing list archive at Nabble.com.

Hello. I don't uderstant when to use textConnection and when not. Some examples do it, some not. I've even seen something like con <- textConnection(rev(rev(ReadLines('data.txt'))[-(1:2])) data <- read.table(con) close(con) -- View this message in context: http://r.789695.n4.nabble.com/when-to-use-textConnection-tp2327132p2327132.html Sent from the R help mailing list

Hello How do you compare R to SAS in terms of speed and management of large datasets? What about Revolution R? I've seen on their site, they claim that Revolution R is much faster than R and it's multithread... Can you really notice the difference?. What dissadvantage does it have? I think it's based on R 2.10. but R already issued the version 2.12 Regards What alternative

Hello Why this works: ncota <- 1 nslope <- 29 resul <- matrix(rep(0,ncota*nslope*4),ncota*nslope,4) But this doesn't? ncota <- 1 sini <- 0.1; sfin <- 1.5; spaso <- 0.05; nslope <- 1+((sfin-sini)/spaso) resul <- matrix(rep(0,ncota*nslope*4),ncota*nslope,4) I guess the problem is that the division gives a noninteger number. How can I get the second one work? I

Hello I've used read.table to read a file that contains numbers such as 0.00001 when I write them back with write.table those numbers appear as 1e-5 How can I keep the old format? thanks -- View this message in context: http://r.789695.n4.nabble.com/number-format-writing-1e-5-instead-of-0-00001-tp3003831p3003831.html Sent from the R help mailing list archive at Nabble.com.

hello I think I've found a bug I don't know if it's a chron bug or a R one. (05/12/05 23:00:00) +1/24 gives (05/12/05 24:00:00) instead of (05/13/05 00:00:00) it looks like the same but it's not because when you get the date of this datetime it says day 12 instead of 13. Please, forward it to the place where this bugs are supposed to be posted. cheers -- View this message

Hello I have a table of this kind: function x1 x2 x3 2.232 1 1 1.00 2.242 1 1 1.01 2.732 1 1 1.02 2.770 1 2 1.00 1.932 1 2 1.01 2.132 1 2 1.02 3.222 1.2 1 1 ..... ... .. .. The table represents the values of a function(x1, x2, x3) for each combination x1, x2, x3. I'd like to generate a plot where each point has the coordinates x=x1, y=x2,

Hello I have two series (that can have with different frequencies or with missing values). I merge them and use na.locf, getting a zoo objet with a common index and two core columns. How can I add this columns getting a new zoo series? Any other way of adding two asynchronou series? regards -- View this message in context:

Hello I have a file with this format 2005-01-03 09:05 0.00 2005-01-03 09:10 0.01 2005-01-03 09:15 0.02 2005-01-03 09:20 0.03 2005-01-03 09:25 0.04 2005-01-03 09:30 0.05 2005-01-03 09:35 0.06 2005-01-03 09:40 0.07 2005-01-03 09:45 0.08 2005-01-03 09:50 0.09 2005-01-03 09:55 0.10 2005-01-03 10:00 0.00 2005-01-03 10:05 0.00 .... some

Hello How can I substitute all NA values by zero in a R zoo series? I've been reading about na.locf and na.omit but I think none of them do what I need. thanks. -- View this message in context: http://r.789695.n4.nabble.com/Substitute-NAs-by-zero-tp2546715p2546715.html Sent from the R help mailing list archive at Nabble.com.

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I have hundreds of megabytes of price data time series, and perl scripts that extract it to tab delimited files (I have C++ programs that must analyse this data too, so I get Perl to extract it rather than have multiple connections to the DB). I can read the data into an R object without any problems. thedata = read.csv("K:\\Work\\SignalTest\\BP.csv", sep = "\t", header =

Hi All, I am interested in aggregating a data frame based on 2 categories--mean effect size (r) for each 'id's' 'mod1'. The 'with' function works well when aggregating on one category (e.g., based on 'id' below) but doesnt work if I try 2 categories. How can this be accomplished? # sample data id<-c(1,1,1,rep(4:12)) n<-c(10,20,13,22,28,12,12,36,19,12,

I am currently summarising a data set by collapsing data based on common identifiers in a column. I am using the 'aggregate' function to summarise numeric columns, i.e. "aggregate(dat[,3], list(dat$gene), mean)". I also wish to summarise text columns e.g. by concatenating values in a comma separated list, but the aggregate function can only return scalar values and so something

I have a frame which contains 3 columns: "date" "defectnum" "state" And I want to get the most recent state change for a given defect number. date is POSIXct. I have tried: aggregate(ev$date, by=list(ev$defectnum), max) Which appears to be working except that the dates seem to come back as integers (presumably the internal representation of POSIXct). When I