similar to: combinations

Hello, I have a dataframe w/ 3 variables of interest: transaction,date(tdate) & time(event_tim). How could I create a 4th variable (last_trans) that would flag the last transaction of the day for each day? In SAS I use: proc sort data=all6; by tdate event_tim; run; /*Create last transaction flag per day*/ data all6; set all6; by tdate event_tim; last_trans=last.tdate; Thanks

Hi List, I have start and end times of events structure(list(start = c("15:00", "15:00", "15:00", "11:00", "14:00", "14:00", "15:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00", "12:00",

Hi All, I would to rsync data spread of many files from remote site. Each file may exist in total different location - the path for each file may be different. My question is: Can I do it one single rsync command, giving a file containing list of paths as parameter, or do I need to run rsync for each file. I did not find any option doing it in the man page. I tried to play with

I hadn't noticed any interactive slowdown, but when I got around to running the notmuch performance suite, there seems to be some noticable slowdown with the glass backend (default in Xapian 1.3.5) compared to chert (using xapian 1.2.22) These tests are on an older i7 with 12G of RAM and an SSD. I'm reasonable confident they are CPU bound. One curious thing is the increase in system time

Had this error when trying to add comments to another user''s photo. ActiveRecord::StatementInvalid in User photosController#show Mysql::Error: Unknown column ''comments.user_id'' in ''on clause'': SELECT photos.`id` AS t0_r0, photos.`user_id` AS t0_r1, photos.`title` AS t0_r2, photos.`body` AS t0_r3, photos.`created_at` AS t0.... I did create a user_id

Olly Betts <olly at survex.com> writes: > > So the T00-new.sh numbers make sense - there's more work to do, and > we need to read existing positional data more to insert the new stuff, > so the increased reads and writes make sense. > > But guessing at what the other two tests do, I wouldn't expect them to > be affected by this. The non-optimized-away cases of

Is it possible to get R to output the value of an expression, that is being calculated within a function? I've attached a very simple example but for more complicated ones would like to be able to debug by seeing what the value of specific expressions are each time it cycles through a loop that executes the expression. I'm relatively new to this so there may be much simpler more elegant

Simple one, have read and googled, still no luck! I want to create several empty vectors all of the same length. I would like multiple empty vectors (vec1, vec2, vec3) and want to create them all in one line. I've tried vec1,vec2,vec3 <- vector(length=5) and c(vec1,vec2,vec3) <- vector(length=5) and several other attempts but nothing seems to work ... suggestions? Thanks Jim

I attempted to install an X100P card but it was not correctly recognized by my Redhat 9 install. I had a test install running without any cards which was working great minus the outward dialing since no cards existed. Now that I have a card, I want to add it to the system. Do I have to scratch the whole current install in order to get the X100P running on my system or is there a way to get it

Simple one here ... but can't get it to work ... for (i in 1:4){ paste("stuff",[i]),sep="") <- 3 + i } ls() rm(list=ls()) I just want it to create 4 new variables called stuff1, stuff2, stuff3, stuff4 with the corresponding assignments. I realise that there are more elegant functions but this is just a model of a bigger situation. Thanks Jim

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ls is a list of character vectors created by strsplit() I want to concatenate the 1st 4 character elements of each list item as a new vector called file. I admit to being confused about list syntax even after numerous readings. Here's what I tried: ls <- list(c("Focused", "10k", "A12", "t04.tif", "+", "µm"),

I'm attempting to sort a 3 dimensional array that looks like this > x , , 1 [,1] [,2] [1,] 9 9 [2,] 7 9 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2] [1,] 2 1 [2,] 3 2 Such that it ends up like this .... > y , , 1 [,1] [,2] [1,] 2 1 [2,] 3 2 , , 2 [,1] [,2] [1,] 6 5 [2,] 4 6 , , 3 [,1] [,2]

I'd like to save some calculation outputs as a pdf, to incorporate with others in a document. I've tried pdf("filename") name_of_object_to_output dev.off() but it doesn't seem to work, appears that this pdf function is for graphics? Is there a way to output numerical objects to pdf? Thanks J Dr. Jim Maas University of East Anglia

Is any one else having problems with Voicepulse today? Suddenly, I can't register and calls to my Voicepulse numbers get a fast busy. Bruce Komito High Sierra Networks, Inc. www.servers-r-us.com (775) 236-5815

Is there a way to convince R to create a character vector without using the quotes? This works ex1 <- c("first","second") but when I try this it doesn't ext <- as.character(c(first,second)) it complains. I have many variables to put into character vectors so dispensing with the quotes would be useful. Thanks Jim =============================== Dr. Jim Maas

I'm trying to work out the simplest way to remove the upper and lower quantiles, in this case upper and lower 25% from an array. I can do it in two steps but when I try it in one, it fails. Is there something simple missing from my syntax or are there other simple elegant way to accomplish this? Thanks J > i <-1:20 > i2 <- i[i<quantile(i,.75)] > i3 <-

If possible I would like to combine two different character arrays in combinations Array1 <- c("height","weight","age","sex") Array2 <- c("trt0","trt1","trt2") I would like to combine these two character vectors to end up with such ... Array3 "height.trt0.trt1" "height.trt0.trt2"

I can not understand why this fails > > faicoutput2 <- list(stuff21 = as.numeric(faicout$coefficients[2]), + stuff31=as.numeric(faicout$coefficients[3]), + stuff41=as.numeric(faicout$coefficients[4]), + stuff32=(stuff21-stuff31), + stuff42=(stuff21-stuff41), +

I'm using the range command to get the minimum and maximum values of an array as in x <- range(array_y) which gives me two values such as [1] -2 9 I need to be able to test if this range of values includes a third value. For example I'd like to query 1) does the range of -2 to 9 include 3, answer TRUE 2) does the range of -2 to 9 include -6, answer FALSE? All values could be