similar to: print numbers

Dear list, I have a list, as follows : a <- 5 names(a) <- "a" b <- 9 names(b) <- "b" c <- 15 names(c) <- "c" x <- list("i" = a, "j" = b, "j" = c) I want to invert the list, like this : $a i 5 $b j k 9 15 I do not find a clean solution. Could anyone give me elegant ideas ? Thanks in advance, Carlos

Hi all, >From a list of strings, I desire to filter out the followings: 1. Digits at the beginning of the strings 2. Character "SPE" following the digits (if it exists) 3. Any characters followed by hyphen The following produces the desired result, but would like to know whether this can be done more efficiently. Any suggestions would be much appreciated. dat <- c("2148

I want to create a graph to express the idea of the area under a pdf curve, like http://r.789695.n4.nabble.com/file/n3032194/w7295e04.jpg Thank you for any help. ----- A R learner. -- View this message in context: http://r.789695.n4.nabble.com/How-to-plot-a-normal-distribution-curve-and-a-shaded-tail-with-alpha-tp3032194p3032194.html Sent from the R help mailing list archive at Nabble.com.

I don't know the real reason, but help("==") gives some clues. For numerical and complex values, remember == and != do not allow for the finite representation of fractions, nor for rounding error. Using all.equal with identical is almost always preferable. See the examples. x1 <- 0.5 - 0.3 x2 <- 0.3 - 0.1 x1 == x2 # FALSE on most machines

Hi John, Here is my code practicing. Please give me some advises. Thank you. Wu Gong # Extract the function string f.str <- sub("y~","",exprtext) # Get arglist from the text sp1 <- paste("\\",c(getGroupMembers(Arith),"(",")"),sep="") sp2 <- getGroupMembers(Math) sps <-

I have a data.frame as the following: var1 var2 9G/G09 abd89C/T90 10A/T9 32C/C 90G/G A/A . . . . . . 10T/C 00G/G90 What I want is to get the letters which are on the left and right of '/'. for example, for "9G/G09", I only want "G", "G", and for "abd89C/T90", I only want "C" and

R developers, Seems I get a bad result ("%#4.0-1e" in particular) when trying to use prettyNum digits=0 with scientific notation. I tried on both my Linux box and on an online R evaluator and saw the same problem, so it's not limited to my box at least. I see the problem in both R 3.5.3 and R 3.3.2. options(scipen=-100) prettyNum(1, digits=0) [1] "%#4.0-1e" prettyNum(2,

Hi -- I'm looking for alternatives to regex for a fairly simply 'reformatting' problem. Alternatives only because a lot of folks have trouble parsing/interpreting regex expressions, and I'm looking for suggestions for something more 'transparent'. Here is an example of what I'm trying to do. Take the following string, which I call x, and for each character in the

Hi there, i'm not getting along with the following problem. I'd like to print a real number, e.g. x <- 12.3 with exactly two digits after the decimal point, e.g. 12.30 I've tried the whole format(), formatC() and prettyNum() functions but did not have any success with it. This should work with all real numbers, in case even with 0.0 (-> 0.00). For cracks this thing is pretty

Hello R-helpers, I have a problem with formatting a single number to show leading zeros. For example, I want "2" displayed as "002". My numbers have 1 to 3 digits and I would like them all to display 3 digits for printing. I know I could use "paste" in a loop with several "if"s, but I was wondering if there is a single function that can do this. I have

I do: x<-rnorm(1000) quantile(x,c(.025,.975)) 2% 98% -1.844753 1.931762 Since I want to find a 95% confidence interval, I take the .025 and .975 quantiles. HOWEVER R says I have the 2% (not 2.5%) and 98% (not 97.5%) points. Is it just rounding the printed 2% and 98%, or is it REALLY finding .02 and .98 points instead of .025 and .975? Thanks for any help. Bill Simpson

I do: x<-rnorm(1000) quantile(x,c(.025,.975)) 2% 98% -1.844753 1.931762 Since I want to find a 95% confidence interval, I take the .025 and .975 quantiles. HOWEVER R says I have the 2% (not 2.5%) and 98% (not 97.5%) points. Is it just rounding the printed 2% and 98%, or is it REALLY finding .02 and .98 points instead of .025 and .975? Thanks for any help. Bill Simpson

Hi I am not sure if it is more readable > paste(paste(unlist(strsplit(x,"")),".", sep=""), collapse="") [1] "1.0.1.1.0.1.1.1." If you did not want last dot, it is a bit shorter. > paste(unlist(strsplit(x,"")),collapse=".") [1] "1.0.1.1.0.1.1.1" > Cheers Petr Tento e-mail a jak?koliv k n?mu p?ipojen?

FWIW, it doesn't seem to be happening on Mac OS: > format(2^30, digits=0) [1] "1.e+09" > prettyNum(12345.6, digits=0) [1] "1.e+04" A glibc misfeature? -pd > On 22 Mar 2019, at 10:10 , Martin Maechler <maechler at stat.math.ethz.ch> wrote: > > Thank you, Robert for raising this here ! > >>>>>> Robert McGehee

formatC() is great for formatting numbers! But it would be even better if it could optionally insert commas (or semicolons), e.g. R> formatC(1234567.89, digits=2, format="f", commas=T) [1] "1,234,567.89" Here's a snippet of code that does that, which could more or less just be inserted into at the end of formatC if any R-core guru were so inclined. "r"

Hello, I am trying to print a table with numbers all rounded to the same number of digits (one after the decimal), but R seems to want to not print ".0" for integers. I can go in and fix it one number at a time, but I'd like to understand the principle. Here's an example of the code. The problem is the 13th element, 21 or 21.0: >nvb_deaths <- round(ss[,10]/100,digits=1)

Under R-1.5.0 on Solaris 2.6: R> prettyNum(123456789, big.mark=",") [1] ",123,456,789" and that bad behavior (leading comma) spills into formatC as well: R> formatC(123456789, digits=0, format="f", big.mark=",") [1] ",123,456,789" Looks to me like a bug in src/library/base/R/format.R, in function prettyNum: B.[i.big] <-

Is it possible to write the output/results (redirect) to a latex file? Jeff. Jeff D. Hamann Hamann, Donald & Associates, Inc. PO Box 1421 Corvallis, Oregon USA 97339-1421 Bus. 541-753-7333 Cell. 541-740-5988 jeff_hamann at hamanndonald.com www.hamanndonald.com -.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.- r-help mailing list -- Read

Hi, Search through the R archives, and couldn't find my answer... how do you format numbers with commas (standard American, one every three digits)? Thanks, Matt -- It is from the wellspring of our despair and the places that we are broken that we come to repair the world. -- Murray Waas

? Fri, 23 May 2025 11:47:33 +0000 Marttila Mikko via R-devel <r-devel at r-project.org> ?????: > When called with a numeric vector, the `replace.zero` argument is > disregarded. > > > prettyNum(0, zero.print = "- ", replace.zero = TRUE) > [1] "-" > Warning message: > In .format.zeros(x, zero.print, replace = replace.zero) : >