similar to: How can I read date format '02-Jan-02' ?

Hello All, I've been reading books about R for awhile now and am in the process of replicating the SAS analyses from an old report. I want to be sure that I can do all the things I need to in R before using it in my daily work. So far, I've managed to read in all my data and have done some data manipulation. I'm having trouble with fixing an error in a date variable though, and was

Dear R Helpers, I am having difficulty with strptime. I wish to find the differences between two vectors of times. I have apparently no difficulty to convert the vectors to the appropriate format using strptime. But, then difftime does not calculate all the differences. Here is the code and output:- dob=strptime(as.character(datx$BDT),'%d-%b-%y'); dob$year=dob$year-100

Hi, I wanted to calculate the age of people in my dataset by subtracting the individual's date of birth from their intake into a program. After several hours, searches of help archives, and the downloading of lubiridate, I have had no luck with this. Below is the code I used. > intakeDS$DOB <- as.character(intakeDS$DOB) > intakeDS$DOB <- as.Date(intakeDS$DOB,

Hi, I wrote a little helper that calulates someone''s age based on his/her date of birth. def age(dob) diff = Date.today - dob age = (diff / 365.25).floor age.to_s end It works fine, but it''s not completely accurate as it just takes the average days in a year. It should be able to calculate this more accurately, right? I can''t work it out

Hello, I have a data which looks like below: Some of the patients have multiple diagnosis. ID(200 patients)   Diag (100 unique Diag-200 in general)   Proc (50 uniqe Proc)  DOB (200)   Gender (200)    a                           daig1 b                           diag2 c                            diag1 I want to reformat this data to : ID   diag1 diag 2 diag 3..  diagx   proc1   proc2  

--------------------- Kernel Begin ------------------------ 1 Time(s): Clock: inserting leap second 23:59:60 UTC ---------------------- Kernel End ------------------------- hee hee. gotta love it....

Dear R experts, I'm reading data from an online database via API and it gets delivered in this messy comma separated structure, > RAW.API <-

Hello, I have some data that has dates in the form 27.02.37. I convert them to a date object as follows: as.Date(data$date,format="%d.%m.%y") But this gives me years such as 2037 when I would like them to be 1937. I thought of trying to take off some time i.e. as.Date(camCD$DoB,format="%d.%m.%y") - 100*365 But that doesn't seem to work out correctly. Any ideas how to

I have files which have columns of data that look like this: DOB 9/27/1964 ... That is, dates in month/day/year format. When variables like DOB are read in, they are converted to factors. So, I wrote this to convert from date to age in years: age<-function(x) {as.numeric(Sys.time()-strptime(as.character(x),format="%m/%d/%Y"))/365.25} This isn't very precise or pretty, but it

Hi, I have a column of DOB in mm/dd/yyyy. I want to convert this format to age. Thanks a lot.   Best,Farnoosh Sheikhi [[alternative HTML version deleted]]

On Tue, 26 Mar 2024 14:50:41 +0100 Franta Hanzl?k <franta at hanzlici.cz> wrote: > On Tue, 26 Mar 2024 08:01:27 +0000 > Rowland Penny via samba <samba at lists.samba.org> wrote: > > > On Tue, 26 Mar 2024 02:57:51 +0100 > > Franta Hanzl?k via samba <samba at lists.samba.org> wrote: > > > > > Please, it is possible (perhaps with some Samba

All of the tutorials and the Agile book use MySQL and I''ve got that working. I am now trying to use PostgreSQL and can''t seem to get going. Is my problem the db setup in postgresql? I have installed postgres-pr The error message when I try to access http://localhost:3000/clients when using PostgreSQL (MySQL works fine) ActiveRecord::StatementInvalid (RuntimeError: ERROR

On Tue, 26 Mar 2024 08:01:27 +0000 Rowland Penny via samba <samba at lists.samba.org> wrote: > On Tue, 26 Mar 2024 02:57:51 +0100 > Franta Hanzl?k via samba <samba at lists.samba.org> wrote: > > > Please, it is possible (perhaps with some Samba schema extension?) to > > have items as 'c' (countryName), 'l' (localityName), 'l' > >

I had occasion recently to read in a one-line *.csv file that looked like: "CandidateName","NSN","Ethnicity","dob","gender" "Smith, Mary Jane",111222333,"E","2/25/1989","F" That "F" (for female) in the last field got transformed to FALSE. Apparently read.csv (and hence read.table) are inferring

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Hi, I use Sweave extensively in my consulting work. When submitting reports to the scientists I work with I like to use the citation function to reference any packages I use, to give proper acknowledgement. I noted in the documentation that a citation inherits from bibentry, and indeed, > citr<- citation() > class(citr) [1] "citation" "bibentry" However, following

Dear All, I installed R 2.7.0 and tried to call a dataset i had ealier own called on R2.6.2 but i keep on getting an error: use("maltreat.dta") Error in fromchar(x) : character string is not in a standard unambiguous format Tried doing the same with R2.7.1 but i get the same error. However if i call the same on R 2.6.2, there is no error: use("maltreat.dta") > des()

On Fri, Jun 10, 2016 at 5:25 PM, Gor Nishanov <gornishanov at gmail.com> wrote: > Hi Eli: > > >> Naively, you would expect that it would be legal to hoist the store... > >> but that breaks your coroutine semantics because the global could be > mutated > >> between the first return and the resume. > > Hmmm... I don't see the problem. I think

All, I would like to apply a set of rules to each row of the sample data set below. The rule sets are the guidelines for determining an individual's date for retirement eligibility. The rules are found in this document, http://www.opm.gov/feddata/RetirementPaperFinal_v4.pdf. I am only interested in the top two categories for retirement eligibility, the CSRS and FERS plans. The data set has

Full_Name: Dong-Yun Kim Version: 1.7.0/1.8.1 OS: WinMe/WinXP Submission from: (NULL) (4.33.147.192) Hi all, It appears that R has a problem with evaluating logical "==" operator. The following are a few examples I found: > 2.1+0.2==2.3 [1] FALSE > 2.7+0.1==2.8 [1] FALSE > 2.7+0.2==2.9 [1] FALSE > 3.1+0.2==3.3 [1] FALSE Thanks. Dong-Yun Kim