similar to: Paired t-tests

Hello, My name is Rodrigo, I am using R program and I have a trouble. I am trying to do a dendrogram with genetics information. Let me explain... The Similarity Matrix was already did, and with this matrix I want to construct a dendrogram. So, the distance is done. I need to transform this matrix (that I have) in a dendrogram, I woud be very grateful if someone could help me. PS: I am sending

Hello, A nice guy call Jun Shen was helping me out with this, but I require a bit more help. Below is my data set or list called 'test'. I'm trying to calculate the %RSD for each pair of index and keep it in cronological order if you can imagine a 3rd column with 'date' beside index. Result Index 1 0.2901 17 2 0.2928 17 3 0.2913 18 4 0.2893 18 5

Hi All, I have data with 400 individuals and the following information Grade: pass or fail coded as 1 for pass and 0 for fail Sex: male or female ( coded as 1 for male and 2 for female ) Age Teaching.method : can be 1,2,3 I want to fit a logistic regression where the outcome if (1=pass or 0 for fail) and the rest of the variables are the regressors. My question is that I am not sure

Is there a way to set up a regression in R that forces two coefficients to be equal but opposite in sign? I'm trying to setup a model where a subject appears in a pair of environments where a measurement X is made. There are a total of 5 environments, one of which is a baseline. But each observation is for a subject in only two of them, and not all subjects will appear in each

Hi everyone, I've just notice a problem with ordered factor variables. It appears that row-binding two ordered factors together looses the ordered attribute. The following example happens both in R1.3.1 and R1.4.1 (on RedHat 7.2): > y <- ordered(gl(3,6),labels=1:3) > y [1] 1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 3 Levels: 1 < 2 < 3 > data <-

Hello All, I have a data with two columns. In one column it is date and in another column it is flow data. I was able to read the data as date and flow data. I used the following code: creek <- read.csv("creek.csv") library(ggplot2) creek[1:10,] colnames(creek) <- c("date","flow") creek$date <- as.Date(creek$date, "%m/%d/%Y") The link to my data

Hello, I'm trying to create a for loop for a data set, I have a list of results in this data set and I want to take the 1st two add them together and divide by the mean of the 1st to, then do the same for the 3rd and 4th values in the list and so on and each time return a value for the calculation on each pair. Any help would be appreciated. Thanks, Al [[alternative HTML version

Thank you, Greg, and also to Scott Ellison, who replied privately. I am in the process of trying out both suggestions. After I sent my initial message, I came across the Systemfit package, which allows specification of constraints on parameters. In theory, this should solve my problem perfectly. However, I was not able to get it to work with my data, as every attempt yielded the following

Target: FreeBSD 6.2-STABLE on i386 autoconf says: configure:2122: checking build system type configure:2140: result: i386-unknown-freebsd6.2 [...] configure:2721: gcc -v >&5 Using built-in specs. Configured with: FreeBSD/i386 system compiler Thread model: posix gcc version 3.4.6 [FreeBSD] 20060305 [...] objdir != srcdir, for both llvm and gcc. Release build. llvm-gcc 4.2 from source.

LLVMers, The 2.2 prerelease is now available for testing: http://llvm.org/prereleases/2.2/ If anyone can help test this release, I ask that you do the following: 1) Build llvm and llvm-gcc (or use a binary). You may build release (default) or debug. You may pick llvm-gcc-4.0, llvm-gcc-4.2, or both. 2) Run 'make check'. 3) In llvm-test, run 'make TEST=nightly report'. 4) When

I want to take the first row of each unique ID value from a data frame. For instance > ddTable <- data.frame(Id=c(1,1,2,2),name=c("Paul","Joe","Bob","Larry")) I want a dataset that is Id Name 1 Paul 2 Bob > unique(ddTable) Will give me all 4 rows, and > unique(ddTable$Id) Will give me c(1,2), but not accompanied by the name column.