Displaying 20 results from an estimated 20000 matches similar to: "extracting the standard error in lrm"
2008 Sep 21
1
glmer -- extracting standard errors and other statistics
Hello,
I am using glmer() from lmer(lme4) to run generalized linear mixed
models. However, I am having a problem extracting the standard errors
for the fixed effects.
I have used:
summary(model)$coef
fixed.effects(model)
coef(model)
to get out the parameter estimates, but do not seem able to extract the
se's.
Anybody have a solution?
Thanks,
John
2008 Jun 30
2
difference between MASS::polr() and Design::lrm()
Dear all,
It appears that MASS::polr() and Design::lrm() return the same point
estimates but different st.errs when fitting proportional odds models,
grade<-c(4,4,2,4,3,2,3,1,3,3,2,2,3,3,2,4,2,4,5,2,1,4,1,2,5,3,4,2,2,1)
score<-c(525,533,545,582,581,576,572,609,559,543,576,525,574,582,574,471,595,
557,557,584,599,517,649,584,463,591,488,563,553,549)
library(MASS)
library(Design)
2008 Dec 13
2
Obtaining p-values for coefficients from LRM function (package Design) - plaintext
Sent this mail in rich text format before. Excuse me for this.
------------------------
Dear all,
I'm using the lrm function from the package "Design", and I want to
extract the p-values from the results of that function. Given an lrm
object constructed as follows :
fit <- lrm(Y~(X1+X2+X3+X4+X5+X6+X7)^2, data=dataset)
I need the p-values for the coefficients printed by calling
2004 Jan 29
2
Calculating/understanding variance-covariance matrix of logistic regression (lrm $var)
Hallo!
I want to understand / recalculate what is done to get
the CI of the logistic regression evaluated with lrm.
As far as I came back, my problem is the
variance-covariance matrix fit$var of the fit
(fit<-lrm(...), fit$var). Here what I found and where
I stucked:
-----------------
library(Design)
# data
D<-c(rep("a", 20), rep("b", 20))
V<-0.25*(1:40)
V[1]<-25
2006 May 09
1
trying to use standard notation
Hi, all. In setting up my package for post-processing regression
models, I am trying to use standard notation as much as possible: thus,
I use coef() to access estimated coefficients. I wrote a function
called se.coef() to grab standard errors, and se.fixef() and se.ranef()
to grab se's from coefficients estimated from lmer().
I also need a function to access sigma-hat (the residual sd
2010 Jun 19
1
Extracting P-values from the lrm function in the rms library
Hello again R users,
I have a devilishly hard problem, which should be very simple. I hope someone out there will have the answer to this on the tip of their tongue.
Please consider the following toy example:
x <- read.table(textConnection("y x1 x2
indv.1 bagels 4 6
indv.2 donuts 5 1
indv.3 donuts 1 10
indv.4 donuts 10 9
indv.5 bagels 0 2
indv.6 bagels 2 9
indv.7 bagels 8 5
indv.8
2010 Nov 22
2
Help: Standard errors arima
Hello,
I'm an R newbie. I've tried to search, but my search skills don't seem
up to finding what I need. (Maybe I don't know the correct terms?)
I need the standard errors and not the confidence intervals from an
ARIMA fit.
I can get fits:
> coef(test)
ar1 ma1
intercept time(TempVector) - 1900
2008 Feb 28
4
standard errors
Hi, guess my problem has simple solution.
I want to extract ONLY Std. Errors of Max. Lik. estimates
(my_fit<-mle(object,...)), the same as I can do with estimates by:
x<-as. matrix(coef(my_fit)).
I could not find any function similar to 'coef(my_fit)', which extracts only
Standard Errors. So far all I can do is to type: summary(my_fit) and then
get the whole output (with Standard
2017 Sep 14
3
Help understanding why glm and lrm.fit runs with my data, but lrm does not
Dear all,
I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have successfully fitted a logistic regression model using the "glm" function as shown below.
library(rms)
gusto <-
2011 May 18
1
logistic regression lrm() output
Hi, I am trying to run a simple logistic regression using lrm() to calculate a
odds ratio. I found a confusing output when I use summary() on the fit object
which gave some OR that is totally different from simply taking
exp(coefficient), see below:
> dat<-read.table("dat.txt",sep='\t',header=T,row.names=NULL)
> d<-datadist(dat)
> options(datadist='d')
2010 Aug 05
3
How to extract se(coef) from cph?
Hello,
I am modeling some survival data wih cph (Design). I have modeled a predictor
which showed non linear effect with restricted cubic splines. I would like to
retrieve the se(coef) for other, linear, predictors. This is just to make nice
LateX tables automatically. I have the coefficients with coef().
How do I do that?
Thanks,
David Biau.
[[alternative HTML version deleted]]
2006 Oct 02
1
a question regarding 'lrm'
Hi List,
I don't understand why 'lrm' doesn't recognize the '~.' formula. I'm pretty sure it was working before. Please see below:
I'm using R2.3.0, WinXP, Design 2.0-12
thanks,
...Tao
> dat <- data.frame(y=factor(rep(1:2,each=50)), x1=rnorm(100), x2=rnorm(100), x3=rnorm(100))
> lrm(y~., data=dat, x=T, y=T)
Error in terms.formula(formula, specials =
2009 Aug 21
1
Possible bug with lrm.fit in Design Library
Hi,
I've come across a strange error when using the lrm.fit function and the
subsequent predict function.
The model is created very quickly and can be verified by printing it on
the console. Everything looks good. (In fact, the performance measures
are rather nice.)
Then, I want to use the model to predict some values. I get the
following error: "fit was not created by a Design
2010 Dec 09
1
error in lrm( )
Dear Sir or Madam?
I am a doctor of urology,and I am engaged in developing a nomogram of bladder cancer. May I ask for your help on below issue?
I set up a dataset which include 317 cases. I got the Binary Logistic Regression model by SPSS.And then I try to reconstruct the model
?lrm(RECU~Complication+T.Num+T.Grade+Year+TS)? by R-Project,and try to internal validate the model through
2003 May 14
1
Multiple comparison and lme (again, sorry)
Dear list,
As a reply to my recent mail:
> simint and TukeyHSD work for aov objects.
> Can someone point me to similar functions for lme objects?
Douglas Bates wrote
There aren't multiple comparison methods for lme objects because it is
not clear how to do multiple comparisons for these. I don't think the
theory of multiple comparisons extends easily to lme models. One
could
2017 Sep 14
0
Help understanding why glm and lrm.fit runs with my data, but lrm does not
> On Sep 14, 2017, at 12:30 AM, Bonnett, Laura <L.J.Bonnett at liverpool.ac.uk> wrote:
>
> Dear all,
>
> I am using the publically available GustoW dataset. The exact version I am using is available here: https://drive.google.com/open?id=0B4oZ2TQA0PAoUm85UzBFNjZ0Ulk
>
> I would like to produce a nomogram for 5 covariates - AGE, HYP, KILLIP, HRT and ANT. I have
2008 May 28
1
extracting information from lmer objects
Hi,
I wish to extract a subset of the information of given by
summary(lmer.object) as a dataframe. In particular, I wish to extract
just a table listing the Estimate, Std Error, and t-values rounded to
3 decimal places. I have learned how to extract the coefficients with
"round(fixef(lmer.object),3)" and the standard errors with
"round(sqrt(diag(vcov(a.lmer))),3)"
but I do not
2004 Sep 30
1
polr (MASS) and lrm (Design) differences in tests of statistical signifcance
Greetings:
I'm running R-1.9.1 on Fedora Core 2 Linux.
I tested a proportional odds logistic regression with MASS's polr and
Design's lrm. Parameter estimates between the 2 are consistent, but the
standard errors are quite different, and the conclusions from the t and
Wald tests are dramatically different. I cranked the "abstol" argument
up quite a bit in the polr
2012 Oct 16
1
Package survey: Compute standard deviations from complex survey designs
Hello,
svyvar from the survey package computes variances (with standard errors)
from survey design objects. Is there any way to compute standard
deviations and their standard errors in a similar manner?
Thanks a lot,
Sebastian
2007 Mar 16
3
ARIMA standard error
Hi,
Can anyone explain how the standard error in arima() is calculated?
Also, how can I extract it from the Arima object? I don't see it in there.
> x <- rnorm(1000)
> a <- arima(x, order = c(4, 0, 0))
> a
Call:
arima(x = x, order = c(4, 0, 0))
Coefficients:
ar1 ar2 ar3 ar4 intercept
-0.0451 0.0448 0.0139 -0.0688 0.0010
s.e.